Advanced Placement (AP)
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06.06.2020 the following question

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Advanced Placement (AP)

Step-by-step answer

Answer Part A:

1. There is a significant negative relationship between anxiety and academic performance, described as:

a. Subjects with lower anxiety scores have higher current GPAs, or;

b. Subjects who have lower current GPAs have higher anxiety scores.

Explanation:

We can tell that the two variables (anxiety and academic performance) have a negative relationship from its correlation coefficient (-.64). The negative sign shows the relationship, while the statistical significance (p < .01 or p < .05) shows whether there is a relationship or not.

Remember, the power of the correlation (as represented by the number 0.64) does not tell you whether a relationship actually happens or not. It can, however tell the strength of a relationship. A .64 is usually described as moderate to strong, depending on which reference you are using.

Also remember that this is not causation - we do not know which variable causes changes at the other. This is why it is possible to describe the relationship with either option (A) or (B). It is preferable to use a neutral sounding one such as the one stated above: By only saying that there is a negative relationship between the two variables.

2. There is no relationship between hours sleeping per night and academic performance.

Explanation:

A correlation coefficient of 0.00 means that there is no relationship between two variables. The closer a correlation coefficient to 0, the less likely do the variables have a relationship with one another.

Answer Part B:

1. It contributes to the interpretation of the findings by discussing whether:

(1) The measurement used is appropriate for the research conducted,

(2) There are any limitations from the current method of measurement.

Explanation:

The operational definitions in the study are not explicitly stated, but we can come to our own conclusions from the description of the study. They are:

Academic performance is the current GPA as reported by the research subjects.

Anxiety is the anxiety score summed from the research subjects' responses to the anxiety scale.

Interpretation is usually done during the discussion part of a research journal, after the statistical results have been reported. Discussing operational definitions would help determine whether the right measurement is used. Is the method free of biases? For example, Dr. Aguilera used a 5-point scale to measure the student's anxiety levels; there is a possibility of central tendency bias occurring.

2. Cohort effects may contribute to a possible bias over the result of the research. The variations in both anxiety levels and GPA may not be due to each other's influences, but perhaps instead caused by other age-related experience variables such as social media use.

Explanation:

Cohort effects are defined as a condition shared with same-aged groups of people which affected the result of the research. It is a form of bias, when it is not controlled. Dr. Aguilera's study is at risk of being affected with this since her research subjects are all university students.

In the study, we saw that Dr. Aguilera measured social media use, however, she did not seem to control this variable. It is possible that the variation in anxiety is moderated by social media, which then affects the subjects' GPA.

Advanced Placement (AP)

Step-by-step answer

“ nothing succeeds like success “

(sorry I don’t have anything else for you but I hope that helps)

(sorry I don’t have anything else for you but I hope that helps)

Advanced Placement (AP)

Step-by-step answer

Something that is persistent remains over time; this is a key characteristic of DDT, which also happens to be a pollutant/pesticide. DDT is able to persist in an environment (as a pollutant) in part due to a phenomenon known as biological magnification. In simpler terms. once DDT enters an ecosystem/trophic structure, it gets worse as you go up the trophic levels; in other words, this means that the worst effects/concentrations of the pesticide will be felt in the uppermost trophic levels (your consumers rather than producers).

The basis for this, however, lies in the fact that organisms of a trophic structure/ecosystem consume each other; they feed on each other to survive (e.g. consumers feeding on producers, higher-level consumers feeding on lower-level consumers, etc.). Thus, once DDT gets into an ecosystem, it can only persist and spread in that ecosystem. Hope this helps :)

Advanced Placement (AP)

Step-by-step answer

The proportion of the available motorcycles that Molly can afford is 60%.

The 30th percentile for the motorcycle is $11920

It should be noted that $25,000 is considered an outlier because it is greater than $24792

Since, mean, μ = $14,000 and standard deviation, σ = $4,000, the standard variable Z or x = $15,000 will be:

Z = (x - μ)/σ

Z = (15000 - 14000)/4000

Z = 0.25

We then check the table and see that it implies that Molly can buy 60% of the available motorcycles.

The 30th percentile for the prices of motorcycles of this type corresponds to a value of Z = -0.52. This will then be:

x = μ + Z*σ

x = 14000 + (-0.52) × 4000

x = $11920

Lastly, the third quartile value when added to 1.5 x IQR will be equal to:

= 16698 + (1.5 × 5396) = $24792

Therefore, $25,000 is considered an outlier because it is greater than $24792

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Advanced Placement (AP)

Step-by-step answer

The algorithm's runtime has been divided into two main categories are given below.

Explanation:

Polynomial runtime would be defined as almost any run time that doesn't even improve quicker than , including fixed time (), logarithmic time (log2{n}), linear (), quadratic (), as well as another polynomial of higher degrees (such as ). The runtime that grows more than and contains exponential time including such (), factorial time (n!), or anything else is super polynomial runtime.It seems it is perceived that polynomial runtime seems to be rational as well as super polynomial growth in order are rendered irrational. It is not necessarily ideal to have a polynomial run time, but it's least theoretically possible.Then maybe we can easily see by the information collected that perhaps the algorithm is increasing at either the frequency of 20×n. At which, across every iteration, n seems to be the input dimension. This suggests that perhaps the runtime specified seems to be of a polynomial category, therefore means that even this technique executes within a rational period.

Advanced Placement (AP)

Step-by-step answer

To generate objective knowledge about any area it is important to use the scientific method. The scientific method uses measurement, analysis, observation, and experimentation to obtain objective data to validate the hypotheses and generate knowledge.

In this case, City University carried out a scientific investigation to verify that its students were happy throughout the time in the university. For the investigation, they used an instrument that evaluates satisfaction. The results indicate that the senior-students are happier than the first-year students, for that the university officials conclude that the students are happier when they attend university for a longer time. This is convenient to attract new students and not change to another study center.

I hope this information can help you.

Advanced Placement (AP)

Step-by-step answer

B

Explanation:

Advanced Placement (AP)

Step-by-step answer

Answer:

(a) Which island has an absolute advantage in producing coconuts? Explain.

No island has absolute advantage in producing coconuts because both Zeetopia and Freshland can produce equal number of coconuts (50 each).

(b) Which island has a comparative advantage in producing coconuts? Explain.

Freshland has a comparative advantage in producing coconuts. Freashland's opportunity cost of producing coconuts (30/50 = 0.6 mangoes) is lower than Zeetopia's 60/50 = 1.2 mangoes). So, Freshland has a comparative advantage in producing coconuts

(c) Assume Zeetopia and Freshland decide to specialize according to their comparative advantages and 1 ton of coconuts is exchanged for 1 ton of mangoes. Are specialization and trade under these terms beneficial to both Zeetopia and Freshland? Explain.

Yes, the terms of trade (1 ton of coconut = 1 ton of mangoes) are beneficial for both islands.

For Zeetopia, opportunity cost of 1 ton of coconut is1.2 tons of mangoes (60/50 = 1.2). So, when it specializes in mangoes, it should get 1 ton of coconut for less than 1.2 tons of mangoes (or, it should give up less than 1.2 tons of mangoes to obtain 1 ton of coconuts). So, 1 ton of coconut = 1 ton of mangoes is beneficial for Zeetopia.

Similarly, the opportunity cost of 1 ton of coconuts for Freshland is 0.6 tons of mangoes. So, when it specializes in coconuts, it should get more than 0.6 tons of mangoes in return for 1 ton of coconuts. So, 1 ton of coconut = 1 ton of mangoes is beneficial for Freshland.

(d) The graph:

(e) Point X is unattainable for Freshland but feasible and inefficient for Zeetopia.

(a) Which island has an absolute advantage in producing coconuts? Explain.

No island has absolute advantage in producing coconuts because both Zeetopia and Freshland can produce equal number of coconuts (50 each).

(b) Which island has a comparative advantage in producing coconuts? Explain.

Freshland has a comparative advantage in producing coconuts. Freashland's opportunity cost of producing coconuts (30/50 = 0.6 mangoes) is lower than Zeetopia's 60/50 = 1.2 mangoes). So, Freshland has a comparative advantage in producing coconuts

(c) Assume Zeetopia and Freshland decide to specialize according to their comparative advantages and 1 ton of coconuts is exchanged for 1 ton of mangoes. Are specialization and trade under these terms beneficial to both Zeetopia and Freshland? Explain.

Yes, the terms of trade (1 ton of coconut = 1 ton of mangoes) are beneficial for both islands.

For Zeetopia, opportunity cost of 1 ton of coconut is1.2 tons of mangoes (60/50 = 1.2). So, when it specializes in mangoes, it should get 1 ton of coconut for less than 1.2 tons of mangoes (or, it should give up less than 1.2 tons of mangoes to obtain 1 ton of coconuts). So, 1 ton of coconut = 1 ton of mangoes is beneficial for Zeetopia.

Similarly, the opportunity cost of 1 ton of coconuts for Freshland is 0.6 tons of mangoes. So, when it specializes in coconuts, it should get more than 0.6 tons of mangoes in return for 1 ton of coconuts. So, 1 ton of coconut = 1 ton of mangoes is beneficial for Freshland.

(d) The graph:

(e) Point X is unattainable for Freshland but feasible and inefficient for Zeetopia.

Advanced Placement (AP)

Step-by-step answer

There is a probability of 89.44% that more than 3.75 gallons are used for any wash cycle.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

From the normal distribution table, P(x > 3.75 ) = P(z > -1.25) = 1 - P(z < 1.25) = 1 - 0.1056 =89.44%

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Advanced Placement (AP)

Step-by-step answer

This question is incomplete, the complete question is;

A tube is being stretched while maintaining its cylindrical shape. The height is increasing at the rate of 2 millimeters per second. At the instant that the radius of the tube is 6 millimeters, the volume is increasing at the rate of 96π cubic millimeters per second. Which of the following statements about the surface area of the tube is true at this instant? (The volume V of a cylinder with radius r and height h is V=πr2h. The surface area Sof a cylinder, not including the top and bottom of the cylinder, is S=2πrh.)

A) The surface area is increasing at the rate of 28pi square mm per second.

B) The surface area is decreasing at the rate of 28pi square mm per second.

C) The surface area is increasing at the rate if 32pi square mm per second.

D) The surface area is decreasing at the rate of 32pi square mm per second.

Surface Area is increasing at the rate of 28π mm²/sec ( Option A )

Explanation:

Given the data in the question;

let r be the radius and h be the height of the tube

so volume V = πr²h

dv/dt = πr² dh/dt + 2nrh dr/dt

⇒ 96n = π × 36 × 2 + 2π × 6h dr/dt

⇒ 24π = 12nh dr/dt ⇒ h.dr/dt = 2

Area Surface S = 2nrh

ds/dt = 2π ( r.dh/dt + h.dr/dt )

= 2π ( 6×2 + 2)

= 2π (14)

= 28π

therefore Surface Area is increasing at the rate of 28π mm²/sec ( Option A )

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