Which of the following fur colors are possible in females

I have the correct answer for gizmos. but it should apply to any plaform

The all fur colour is correct answer and possible in females.

Explaination:

All fur colors can be possible in male calicos except for white orange and black together.

Explanation: Having three colors (white, orange, and black) on the same cat requires two X chromosomes, male calicos only have one.

I have the correct answer for gizmos. but it should apply to any plaform

I have the correct answer for gizmos. but it should apply to any plaform

# include<iostream>

# include<stdio.h>

# include<stdlib.h>

using namespace::std;

int main()

{

   int *a=NULL;

   int n; int score=0;

   cout<<"Enter the value of N";

   cin>>n;

   a=new int[n];

   cout<<"Enter the elements of a";

   for(int i=0;i<=n;i++)

   {

       cin>>a[i];

   }

   int num=n;int k=n;int j=num;

   while(j>=num)

   {

   if(n%2==0)

   {

     for(int i=0;i<=k;i++)

     {

         score+=a[i];cout<<score;      }

     if(a[0]>a[n])

       {

             a[n]=0;

             n--;

         }

     else if(a[0]<a[n])

     {

           a[0]=0;

           n--;

     }

     else if(n==1)

     {

         exit(0);

     }

   }

   else

   {

       for(int i=0;i<=n;i++)

       {

           score-=a[i];

       }

       if(a[0]>a[n])

       {

             a[n]=0;

             n--;

       }

     else if(a[0]<a[n])

     {

           a[0]==0;

           n--;

     }

     else

     {

         exit(0);

     }

   }

   j--;

   }

   cout<<"score"<<score;

   return 0;

}

Explanation:

The array above is created dynamically, and rest is as mentioned in question.

# include<iostream>

# include<stdio.h>

# include<stdlib.h>

using namespace::std;

int main()

{

   int *a=NULL;

   int n; int score=0;

   cout<<"Enter the value of N";

   cin>>n;

   a=new int[n];

   cout<<"Enter the elements of a";

   for(int i=0;i<=n;i++)

   {

       cin>>a[i];

   }

   int num=n;int k=n;int j=num;

   while(j>=num)

   {

   if(n%2==0)

   {

     for(int i=0;i<=k;i++)

     {

         score+=a[i];cout<<score;      }

     if(a[0]>a[n])

       {

             a[n]=0;

             n--;

         }

     else if(a[0]<a[n])

     {

           a[0]=0;

           n--;

     }

     else if(n==1)

     {

         exit(0);

     }

   }

   else

   {

       for(int i=0;i<=n;i++)

       {

           score-=a[i];

       }

       if(a[0]>a[n])

       {

             a[n]=0;

             n--;

       }

     else if(a[0]<a[n])

     {

           a[0]==0;

           n--;

     }

     else

     {

         exit(0);

     }

   }

   j--;

   }

   cout<<"score"<<score;

   return 0;

}

Explanation:

The array above is created dynamically, and rest is as mentioned in question.