In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
Explanation:
Step 1: Data given
Mass of Al2S3 = 21.0 grams
Molar mass of Al2S3 = 150.158 g/mol
Number of Avogadro = 6.022 * 10^23 / moles
Step 2: Calculate moles of Al2S3
Moles Al2S3 = mass Al2S3 / molar mass Al2S3
Moles Al2S3 = 21.0 grams / 150.158 g/mol
Moles Al2S3 = 0.140 moles
Step 3: Calculate moles sulfur
For 1 mol Al2S3 we have 3 moles S
For 0.140 moles Al2S3 we have 3*0.140 = 0.420 moles S
Step 4: Calculate sulfur atoms
Number of sulfur atoms = moles * Number of Avogadro
Number of sulfur atoms = 0.420 moles * 6.022 * 10^23 / moles
Number of sulfur atoms = 2.53 *10^23 S atoms
In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
Explanation:
Step 1: Data given
Mass of Al2S3 = 21.0 grams
Molar mass of Al2S3 = 150.158 g/mol
Number of Avogadro = 6.022 * 10^23 / moles
Step 2: Calculate moles of Al2S3
Moles Al2S3 = mass Al2S3 / molar mass Al2S3
Moles Al2S3 = 21.0 grams / 150.158 g/mol
Moles Al2S3 = 0.140 moles
Step 3: Calculate moles sulfur
For 1 mol Al2S3 we have 3 moles S
For 0.140 moles Al2S3 we have 3*0.140 = 0.420 moles S
Step 4: Calculate sulfur atoms
Number of sulfur atoms = moles * Number of Avogadro
Number of sulfur atoms = 0.420 moles * 6.022 * 10^23 / moles
Number of sulfur atoms = 2.53 *10^23 S atoms
In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
Explanation:
We are given this compound with the formula: C₃H₂O
According the subscripts, 1 molecule contains 3 carbon atoms, 2 hydrogen atoms, and 1 oxygen atom.
We can make a ratio. There are 3 carbon atoms for every 1 molecule of C₃H₂O.
Since we want to calculate the number of atoms in 200 molecules, we can multiply the ratio by 200.
200 molecules of C₃H₂O contains 600 atoms of carbon.
Answer:
52.6 gramStep-by-step explanation:
It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm
Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)
glycoproteins
Explanation:
A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).
Answer:
Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.
Explanation:
In this case, you know:
P= 0.884 atm
V= ?
n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)
R=0.082
T= 328 K
Replacing in the ideal gas law:
0.884 atm×V= 0.857 moles× 0.082 ×328 K
Solving:
V= 26.07 L
The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.
It will provide an instant answer!