D. In a low-pressure system, air sinks, creating fair weather. In a high-pressure system, air rises, creating storms.
Explanation :A low-pressure system usually brings clouds and precipitation, while a high-pressure system brings cool dry air and clear skies. A low-pressure system usually brings warm dry air and clear skies, while a high-pressure system usually brings warm moist air and precipitation. In low pressure system air rises while in a high pressure system air sinks
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.
D. In a low-pressure system, air sinks, creating fair weather. In a high-pressure system, air rises, creating storms.
Explanation :A low-pressure system usually brings clouds and precipitation, while a high-pressure system brings cool dry air and clear skies. A low-pressure system usually brings warm dry air and clear skies, while a high-pressure system usually brings warm moist air and precipitation. In low pressure system air rises while in a high pressure system air sinks
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.
Explanation:
A) Pressure at which HPLC procedure is running = P =
1 Torr = 133.322 Pascal
The running pressure in Torr is 1,530.13.
B)Initial temperature if the gas in balloon =
Initial volume of the gas in the balloon =
Final temperature if the gas in balloon =
Final volume of the gas in the balloon =
Using Charles law:
(constant pressure)
is the new volume of the gas.
C) Initial temperature if the gas in balloon =
Initial volume of the gas in the balloon =
Initial pressure of the gas in the balloon =
Final temperature if the gas in balloon =
Final volume of the gas in the balloon =
Final pressure of the gas in the balloon =
Using combine gas law:
38.06 liters is the new volume of the balloon.
D) Initial temperature if the gas in container=
Initial volume of the gas in the container =
Initial pressure of the gas in the container=
Final temperature if the gas in container=
Final volume of the gas in the container=
Final pressure of the gas in the container=
Using combine gas law:
723.45 mmHg is the new pressure inside the container.
Explanation:
A) Pressure at which HPLC procedure is running = P =
1 Torr = 133.322 Pascal
The running pressure in Torr is 1,530.13.
B)Initial temperature if the gas in balloon =
Initial volume of the gas in the balloon =
Final temperature if the gas in balloon =
Final volume of the gas in the balloon =
Using Charles law:
(constant pressure)
is the new volume of the gas.
C) Initial temperature if the gas in balloon =
Initial volume of the gas in the balloon =
Initial pressure of the gas in the balloon =
Final temperature if the gas in balloon =
Final volume of the gas in the balloon =
Final pressure of the gas in the balloon =
Using combine gas law:
38.06 liters is the new volume of the balloon.
D) Initial temperature if the gas in container=
Initial volume of the gas in the container =
Initial pressure of the gas in the container=
Final temperature if the gas in container=
Final volume of the gas in the container=
Final pressure of the gas in the container=
Using combine gas law:
723.45 mmHg is the new pressure inside the container.
Cool air near surface forms high-pressure areas
Cool air near surface forms high-pressure areas
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