Ques 1)
The student whose measurement might be in centimeters is:
Jim
Ques 2)
C. 5,000
Step-by-step explanation:Ques 1)
We know that the standard unit centimeters or meters is used to represent the length of some object.
Here Jim measured an object's length.
Hence, he would represent his measurement in centimeters.
Ques 2)
We know that 1 m=100 cm
and 1 km=1000 m
Hence,
1 km=100000 cm
Hence,
0.05 km=0.05×100000 cm
Hence, we have:
0.05 km=5000 cm.
Hence, the correct answer is: Option: C
Ques 1)
The student whose measurement might be in centimeters is:
Jim
Ques 2)
C. 5,000
Step-by-step explanation:Ques 1)
We know that the standard unit centimeters or meters is used to represent the length of some object.
Here Jim measured an object's length.
Hence, he would represent his measurement in centimeters.
Ques 2)
We know that 1 m=100 cm
and 1 km=1000 m
Hence,
1 km=100000 cm
Hence,
0.05 km=0.05×100000 cm
Hence, we have:
0.05 km=5000 cm.
Hence, the correct answer is: Option: C
A- The amount will grow.
B- "The more we rely on advanced technology, the more likely it is that we will send additional satellites into space."
Explanation:
Space junk is the name given to inoperable objects in Earth's orbit. These include rocket stages, unusable satellites, rubbish from the destruction of spacecraft and satellites, and other objects dangerous to spacecraft in orbit. 95% of the observed objects in orbit are junk.
Particularly those pieces that continue to orbit around the earth can be a problem, depending on the orbit. The fact that a flaky paint can be a problem is due to the enormous speeds: in a low orbit the speed is about 8 km / s, and the relative speed in a collision can be even higher. An artificial moon can be damaged by colliding with a small object.
A- The amount will grow.
B- "The more we rely on advanced technology, the more likely it is that we will send additional satellites into space."
Explanation:
Space junk is the name given to inoperable objects in Earth's orbit. These include rocket stages, unusable satellites, rubbish from the destruction of spacecraft and satellites, and other objects dangerous to spacecraft in orbit. 95% of the observed objects in orbit are junk.
Particularly those pieces that continue to orbit around the earth can be a problem, depending on the orbit. The fact that a flaky paint can be a problem is due to the enormous speeds: in a low orbit the speed is about 8 km / s, and the relative speed in a collision can be even higher. An artificial moon can be damaged by colliding with a small object.
Explanation:
All space junk is the result of us launching objects from Earth, and it remains in orbit until it re-enters the atmosphere. Some objects in lower orbits of a few hundred kilometres can return quickly. ... When two satellites collide, they can smash apart into thousands of new pieces, creating lots of new debris.
How does space junk get into space?
How does space junk get into space? All space junk is the result of us launching objects from Earth, and it remains in orbit until it re-enters the atmosphere. Some objects in lower orbits of a few hundred kilometres can return quickly. ... Some space junk results from collisions or anti-satellite tests in orbit. (it will decrease overtime)
PART B
"The weight could swing around and basically knock debris out of orbit."
any more help just ask ;)
D
Step-by-step explanation:
You calculate the percentual error as:
abs(1 - actual / measured)* 100%
So if actual = measured, the error is 0%
From below table, you can see that the percentual difference between 2.1 and 1.6 is the largest.
D
Step-by-step explanation:
You calculate the percentual error as:
abs(1 - actual / measured)* 100%
So if actual = measured, the error is 0%
From below table, you can see that the percentual difference between 2.1 and 1.6 is the largest.
Answer:
AStep-by-step explanation:
The input force is 50 N. But it will not create not any change. No mechanical advantage is observed.
Answer:
52.6 gramStep-by-step explanation:
It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm
It will provide an instant answer!