Classify each of these reactions. ba(clo3)2(s)⟶bacl2(s)+3o2(g)ba(clo3)2(s)⟶bacl2(s)+3o2(g) acid–base neutralization precipitation redox none of the above 2nacl(aq)+k2s(aq)⟶na2s(aq)+2kcl(aq)2nacl(aq)+k2s(aq)⟶na2s(aq)+2kcl(aq) acid–base neutralization precipitation redox none of the above cao(s)+co2(g)⟶caco3(s)cao(s)+co2(g)⟶caco3(s) acid–base neutralization precipitation redox none of the above koh(aq)+agno3(aq)⟶kno3(aq)+agoh(s)koh(aq)+agno3(aq)⟶kno3(aq)+agoh(s) acid–base neutralization precipitation redox none of the above

1- Ba(ClO3)2(s) > BaCl2(s) +3O2(g) -Redox

2- 2NaCl(aq) +K2S(aq) > Na2S(aq) + 2KCl(aq)  - None of the above

3- CaO(s) + CO2(g) > CaCO3(s)  -None of the above

4- KOH(aq)+ AgNO3(aq) > KNO3(aq) + AgOH(s)  - Precipitation

5- Ba(OH)2(aq) + 2HNO2(aq) > Ba(NO2)2(aq) +2H2O(l) -Neutralization.

Explanation;

1) Redox, because it involves bith reduction and oxidation

2) I suppose would be "none of the above" for this chemical reaction, from the choices given.

3) It is a synthesis reaction, thus the correct answer should be "none of the above" from the asker's choices.

4) It is a precipitation reaction, also called double decomposition reaction where two soluble salts react to form an insoluble salt and a soluble salt.  

5) It is acid-base neutralization, as such reactions form both a salt and water.

The reactions below can be classified as:

We will classify the reactions below using one of the following criteria.

Let's classify each of these reactions.

Ba(ClO₃)₂(s) ⟶ BaCl₂(s) + 3 O₂(g)

None of the above. This is a decomposition reaction, in which a compound decomposes into smaller substances.

2 NaCl(aq) + K₂S(aq) ⟶ Na₂S(aq) + 2 KCl(aq)

None of the above. This is a double displacement reaction, in which both compounds exchange their cations and anions.

CaO(s) + CO₂(g) ⟶ CaCO₃(s)

None of the above. This is a synthesis or combination reaction, in which 2 compounds combine to form a bigger one.

KOH(aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH(s)

Precipitation. Solid AgOH is formed.

The reactions below can be classified as:

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Answer:

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 ×328 K

Solving:

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.