10.12.2020

The first and second question I need help with :(

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Mathematics
Step-by-step answer
P Answered by PhD

(a) There are 45 ways to answer exactly 8 questions correctly.

(b) There are 16 ways to answer exactly 8 questions correctly such that either 1st or 2nd is correct.

(c) There are 10 ways to answer exactly 8 questions correctly such that the 3 of the first 5 questions are correct.

Step-by-step explanation:

(a)

Combination is the procedure to select k items from n distinct objects.

{n\choose k}=\frac{n!}{k!(n-k)!}

The total number of questions in the test is, 10.

The number of questions answered correctly is, 8.

Compute the combination of 8 questions from 10 as follows:

{10\choose 8}=\frac{10!}{8!(10-8)!}=\frac{10!}{8!\times 2!}=\frac{9\times10}{2\times1}=45

Thus, there are 45 ways to answer exactly 8 questions correctly.

(b)

Now a condition is applied that of the first two questions only one is correct not both.

The sample space of selecting 8 correctly answered questions from 10 is:

S = {1st is correct and remaining 7 can be selected from the rest 8,

      2nd is correct and remaining 7 can be selected from the rest 8}

Number of ways to select 7 correct questions from the remaining 8 given that the 1st question is correct and 2nd is wrong is:

        {8\choose 7}=\frac{8!}{7!(8-7)!}=8

Number of ways to select 7 correct questions from the remaining 8 given that the 1st question is wrong and 2nd is correct is:

        {8\choose 7}=\frac{8!}{7!(8-7)!}=8

The total number of ways to select 8 correctly answered questions such that either 1st or 2nd is correct is = 8 + 8 = 16.

Thus, there are 16 ways to answer exactly 8 questions correctly such that either 1st or 2nd is correct.

(c)

The condition now applied is that the 3 of the first 5 questions are correct.

Number of ways to select 3 correct answers from the first 5 questions is:

{5\choose 3}=\frac{5!}{3!(5-3)!}=\frac{5!}{3!\times2!}=10

Number of ways to select 5 correct answers from the last 5 questions is:

{5\choose 5}=\frac{5!}{5!(5-5)!}=\frac{5!}{5!\times0!}=1

The total number of ways to select 8 correctly answered questions such that the 3 of the first 5 questions are correct is = 10 × 1 = 10.

Thus, there are 10 ways to answer exactly 8 questions correctly such that the 3 of the first 5 questions are correct.

Mathematics
Step-by-step answer
P Answered by PhD

(a) There are 45 ways to answer exactly 8 questions correctly.

(b) There are 16 ways to answer exactly 8 questions correctly such that either 1st or 2nd is correct.

(c) There are 10 ways to answer exactly 8 questions correctly such that the 3 of the first 5 questions are correct.

Step-by-step explanation:

(a)

Combination is the procedure to select k items from n distinct objects.

{n\choose k}=\frac{n!}{k!(n-k)!}

The total number of questions in the test is, 10.

The number of questions answered correctly is, 8.

Compute the combination of 8 questions from 10 as follows:

{10\choose 8}=\frac{10!}{8!(10-8)!}=\frac{10!}{8!\times 2!}=\frac{9\times10}{2\times1}=45

Thus, there are 45 ways to answer exactly 8 questions correctly.

(b)

Now a condition is applied that of the first two questions only one is correct not both.

The sample space of selecting 8 correctly answered questions from 10 is:

S = {1st is correct and remaining 7 can be selected from the rest 8,

      2nd is correct and remaining 7 can be selected from the rest 8}

Number of ways to select 7 correct questions from the remaining 8 given that the 1st question is correct and 2nd is wrong is:

        {8\choose 7}=\frac{8!}{7!(8-7)!}=8

Number of ways to select 7 correct questions from the remaining 8 given that the 1st question is wrong and 2nd is correct is:

        {8\choose 7}=\frac{8!}{7!(8-7)!}=8

The total number of ways to select 8 correctly answered questions such that either 1st or 2nd is correct is = 8 + 8 = 16.

Thus, there are 16 ways to answer exactly 8 questions correctly such that either 1st or 2nd is correct.

(c)

The condition now applied is that the 3 of the first 5 questions are correct.

Number of ways to select 3 correct answers from the first 5 questions is:

{5\choose 3}=\frac{5!}{3!(5-3)!}=\frac{5!}{3!\times2!}=10

Number of ways to select 5 correct answers from the last 5 questions is:

{5\choose 5}=\frac{5!}{5!(5-5)!}=\frac{5!}{5!\times0!}=1

The total number of ways to select 8 correctly answered questions such that the 3 of the first 5 questions are correct is = 10 × 1 = 10.

Thus, there are 10 ways to answer exactly 8 questions correctly such that the 3 of the first 5 questions are correct.

Mathematics
Step-by-step answer
P Answered by PhD

Option D). 1.37

Step-by-step explanation:

According to the question, a five-question quiz is taken in which the first and second questions have four answer choices, the third and fourth questions have three answer choices, and the last question has five answer choices. If a student randomly marks an answer for each question, what is the expected number of questions he will answer correctly?

If the first 2 questions have four options,then the probability of getting the 2 of them correctly will be 2/4

The same applies for the third and fourth question that has 3 options for the person to choose from.

The probability of getting the third and fourth questions correct is 2/3

And lastly, for the last question which as an option of 5 to choose from, the probability of getting that one question correct out of five options is 1/5

If a student randomly marks an answer for each question, the expected number of questions he will answer correctly will be

2/4 + 2/3 + 1/5

= 1.37

English
Step-by-step answer
P Answered by PhD

Question and answer

The transition that this passage uses is that of question and answer. In order to introduce an idea, the author first asks a question (how does one find these answers we are looking for?). Afterwards, the author continues with the text by providing an answer to the question (The answer to finding the answer, of course, is to first ask the question). In this way, the author is able to encourage the audience to think about the topic, helping them engage with the ideas he is presenting in a deeper way.

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