07.02.2022

you must use at last two differents arrays- these are in effect parallel

. 4

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Computers and Technology
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P Answered by PhD
Answer: c. internet of things.

Explanation:
The technology that combines with the 5G capabilities which was used in the monitoring of the shopping trends is the Internet of Things.
- Internet of Things (IoT) simply means when there are interrelated, and internet-connected objects which collects and transfers data without human intervention through a wireless network or makes use of sensors.
- This is being used by the retailer in the example given to monitor the shopping trends. In conclusion, the correct option is Internet of Things.
Computers and Technology
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The solution that would help the client pool their data together is a data integration solution. This type of solution allows for the collection and consolidation of data from various sources into a single, unified database. This can be achieved through a variety of methods, including Extract, Transform, Load (ETL) processes, data warehousing, and master data management. By implementing a data integration solution, the client will be able to access and analyze their data more efficiently, leading to better insights and informed decision-making.

Computers and Technology
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P Answered by Master

The correct answer to the following question will be "Auto-encoder".

Explanation:

It is indeed a form of artificial neural net that utilizes in an unmonitored way to practice successful information coding.

The objective of such an auto-encoder seems to be to acquire a specification (encoding) for a collection of information, usually for reducing degrees of freedom, by teaching the channel to overlook the "noise" message.Learn a few things of endogenous model representation and then use it to recreate the object.
Computers and Technology
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When one encounters another vessel and assess the situation and believes that you are the stand-on vessel, You should still maintain your course unless the give-away vessel or vessel you have encountered is not taking appropriate actions, what you should do is, you should take action and move away from the vessel, do not go toward the vessel nor pass in front of it.
Computers and Technology
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P Answered by PhD

A code in C++ follows:

Explanation:

#include<iostream>

using namespace std;

int calculate_area(int width, int length)

{

int area;

area=width*length;

return area;

}

int main()

{

int a,b,ar,c,d,ar1,n;

cout<<"\nEnter length of room:";

cin>>a;

cout<<"\nEnter width of room:";

cin>>b;

ar=calculate_area(a,b);

cout<<"\nArea of room:"<<ar<<" units";

cout<<"\nEnter length of mat:";

cin>>c;

cout<<"\nEnter width of mat:";

cin>>d;

ar1=calculate_area(c,d);

n=ar/ar1;

cout<<"\nNumber of mats required are:"<<n;

return 0;

}


Codehs 7.4.6:  gymnastics mats calculate how many mats will be needed to fill a room given the dimen
Computers and Technology
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P Answered by Master

def get_word(sentence, n):

# Only proceed if n is positive

   if n > 0:

       words = sentence.split()

# Only proceed if n is not more than the number of words

       if n <= len(words):

           return words[n-1]

   return (" ")

print(get_word("This is a lesson about lists", 4)) # Should print: lesson

print(get_word("This is a lesson about lists", -4)) # Nothing

print(get_word("Now we are cooking!", 1)) # Should print: Now

print(get_word("Now we are cooking!", 5)) # Nothing

Explanation:

Added parts are highlighted.

If n is greater than 0, split the given sentence using split method and set it to the words.

If n is not more than the number of words, return the (n-1)th index of the words. Since the index starts at 0, (n-1)th index corresponds to the nth word

Computers and Technology
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Answer options:
a. Cleaning a data visualization to remove unwanted patterns.
b. Iteratively creating visualizations to ask and answer new questions.
c. Cleaning data to remove inconsistencies.
d. Filtering the data to look at the responses from only certain groups.

Answer: is correct d. Filtering the data to look at the responses from only certain groups.
Computers and Technology
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P Answered by Master

Yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.

Given that,

The charge for the plane ticket for the last month is $200.The minimum balance required is $25.And, the number of months given is 8.

Based on the above information, the calculation is as follows:

= $25 × 8 months

= $200

Therefore we can conclude that yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.

Learn more: link

Computers and Technology
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P Answered by Master

(1)

public int getPlayer2Move(int round)

{

  int result = 0;

 

  //If round is divided by 3

  if(round%3 == 0) {

      result= 3;

  }

  //if round is not divided by 3 and is divided by 2

  else if(round%3 != 0 && round%2 == 0) {

      result = 2;

  }

  //if round is not divided by 3 or 2

  else {

      result = 1;

  }

 

  return result;

}

(2)

public void playGame()

{

 

  //Initializing player 1 coins

  int player1Coins = startingCoins;

 

  //Initializing player 2 coins

  int player2Coins = startingCoins;

 

 

  for ( int round = 1 ; round <= maxRounds ; round++) {

     

      //if the player 1 or player 2 coins are less than 3

      if(player1Coins < 3 || player2Coins < 3) {

          break;

      }

     

      //The number of coins player 1 spends

      int player1Spends = getPlayer1Move();

     

      //The number of coins player 2 spends

      int player2Spends = getPlayer2Move(round);

     

      //Remaining coins of player 1

      player1Coins -= player1Spends;

     

      //Remaining coins of player 2

      player2Coins -= player2Spends;

     

      //If player 2 spends the same number of coins as player 2 spends

      if ( player1Spends == player2Spends) {

          player2Coins += 1;

          continue;

      }

     

      //positive difference between the number of coins spent by the two players

      int difference = Math.abs(player1Spends - player2Spends) ;

     

      //if difference is 1

      if( difference == 1) {

          player2Coins += 1;

          continue;

      }

     

      //If difference is 2

      if(difference == 2) {

          player1Coins += 2;

          continue;

      }

     

     

  }

 

  // At the end of the game

  //If player 1 coins is equal to player two coins

  if(player1Coins == player2Coins) {

      System.out.println("tie game");

  }

  //If player 1 coins are greater than player 2 coins

  else if(player1Coins > player2Coins) {

      System.out.println("player 1 wins");

  }

  //If player 2 coins is grater than player 2 coins

  else if(player1Coins < player2Coins) {

      System.out.println("player 2 wins");

  }

}

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