To execute a program on a cluster with 6 nodes and the 80% of the program can be parallel, what’s the system
efficiency? If we using 12 nodes, what’s the system efficiency and why?

The correct answer to the following question will be "Auto-encoder".

Explanation:

It is indeed a form of artificial neural net that utilizes in an unmonitored way to practice successful information coding.

A code in C++ follows:

Explanation:

#include<iostream>

using namespace std;

int calculate_area(int width, int length)

{

int area;

area=width*length;

return area;

}

int main()

{

int a,b,ar,c,d,ar1,n;

cout<<"\nEnter length of room:";

cin>>a;

cout<<"\nEnter width of room:";

cin>>b;

ar=calculate_area(a,b);

cout<<"\nArea of room:"<<ar<<" units";

cout<<"\nEnter length of mat:";

cin>>c;

cout<<"\nEnter width of mat:";

cin>>d;

ar1=calculate_area(c,d);

n=ar/ar1;

cout<<"\nNumber of mats required are:"<<n;

return 0;

}

boolean rsvp;

int selection;

String option1;

String option2;

(a) if(rsvp){

System.out.println("Attending");

} else {

System.out.println("Not attending");

}

(b) if (selection == 1){

System.out.println("Beef");

} else if (selection == 2){

System.out.println("Chicken");

} else if (selection == 3) {

System.out.println("Pasta");

} else {

System.out.println("Fish");

}

(c) switch(selection){

case 1:

if(rsvp){

option1 = "Thanks for attending. You will be served beef.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 2:

if(rsvp){

option1 = "Thanks for attending. You will be served chicken.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 3:

if(rsvp){

option1 = "Thanks for attending. You will be served pasta.";

} else{

option1 = "Sorry you can't make it";

}

break;

default:

if(rsvp){

option1 = "Thanks for attending. You will be served fish.";

} else{

option1 = "Sorry you can't make it";

}

break;

}

(d) if (option1 == option2){

System.out.println("True");

} else {

System.out.println("False");

}

Explanation:

This code snippet is written in Java.

a) Uses if statement to print "attending" if rsvp is true and "not attending" if rsvp is false.

b) Uses if-else statement to print the variety of food based on user selection. If selection is 1, it print beef. If selection is 2, it print chicken. If selection is 3, it prints pasta else it print fish for any other value of selection.

c) Uses switch statement to determine the value of selection and then uses inner if statement to assign "Thanks for attending. You will be served beef." if rsvp is true to option1. The value of beef changes depending on the value of selection. If rsvp is false, then "Sorry you can't make it." is assigned to option1.

d) Uses if statement to print true if option1 and option2 are equal else it print false.

def get_word(sentence, n):

# Only proceed if n is positive

   if n > 0:

       words = sentence.split()

# Only proceed if n is not more than the number of words

       if n <= len(words):

           return words[n-1]

   return (" ")

print(get_word("This is a lesson about lists", 4)) # Should print: lesson

print(get_word("This is a lesson about lists", -4)) # Nothing

print(get_word("Now we are cooking!", 1)) # Should print: Now

print(get_word("Now we are cooking!", 5)) # Nothing

Explanation:

Added parts are highlighted.

If n is greater than 0, split the given sentence using split method and set it to the words.

If n is not more than the number of words, return the (n-1)th index of the words. Since the index starts at 0, (n-1)th index corresponds to the nth word

I think that 3 would be the correct answer

Question:

When multiple team members are working on a related feature, how often should they integrate their work

Select only one answer.

A) Do the integration midway through the iteration.

B) After they reach a logical end of creating the functionality.

C) In a scheduled daily (or multiple times in a day) frequency.

D) In a scheduled weekly (or multiple times in a week) frequency.

The best option is D.

Explanation:

Multiple integrations per day may become too cumbersome. Leaving the various parts of the project until a logical end for a functionality has been reached may create room for a lot of errors thus resulting in time wasted.

To ensure regular course correction (if required), twice a week would suffice.

Cheers!

Yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.

Given that,

Based on the above information, the calculation is as follows:

= $25 × 8 months

= $200

Therefore we can conclude that yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.

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