The correct answer to the following question will be "Auto-encoder".
Explanation:
It is indeed a form of artificial neural net that utilizes in an unmonitored way to practice successful information coding.
The objective of such an auto-encoder seems to be to acquire a specification (encoding) for a collection of information, usually for reducing degrees of freedom, by teaching the channel to overlook the "noise" message.Learn a few things of endogenous model representation and then use it to recreate the object.boolean rsvp;
int selection;
String option1;
String option2;
(a) if(rsvp){
System.out.println("Attending");
} else {
System.out.println("Not attending");
}
(b) if (selection == 1){
System.out.println("Beef");
} else if (selection == 2){
System.out.println("Chicken");
} else if (selection == 3) {
System.out.println("Pasta");
} else {
System.out.println("Fish");
}
(c) switch(selection){
case 1:
if(rsvp){
option1 = "Thanks for attending. You will be served beef.";
} else{
option1 = "Sorry you can't make it";
}
break;
case 2:
if(rsvp){
option1 = "Thanks for attending. You will be served chicken.";
} else{
option1 = "Sorry you can't make it";
}
break;
case 3:
if(rsvp){
option1 = "Thanks for attending. You will be served pasta.";
} else{
option1 = "Sorry you can't make it";
}
break;
default:
if(rsvp){
option1 = "Thanks for attending. You will be served fish.";
} else{
option1 = "Sorry you can't make it";
}
break;
}
(d) if (option1 == option2){
System.out.println("True");
} else {
System.out.println("False");
}
Explanation:
This code snippet is written in Java.
a) Uses if statement to print "attending" if rsvp is true and "not attending" if rsvp is false.
b) Uses if-else statement to print the variety of food based on user selection. If selection is 1, it print beef. If selection is 2, it print chicken. If selection is 3, it prints pasta else it print fish for any other value of selection.
c) Uses switch statement to determine the value of selection and then uses inner if statement to assign "Thanks for attending. You will be served beef." if rsvp is true to option1. The value of beef changes depending on the value of selection. If rsvp is false, then "Sorry you can't make it." is assigned to option1.
d) Uses if statement to print true if option1 and option2 are equal else it print false.
def get_word(sentence, n):
# Only proceed if n is positive
if n > 0:
words = sentence.split()
# Only proceed if n is not more than the number of words
if n <= len(words):
return words[n-1]
return (" ")
print(get_word("This is a lesson about lists", 4)) # Should print: lesson
print(get_word("This is a lesson about lists", -4)) # Nothing
print(get_word("Now we are cooking!", 1)) # Should print: Now
print(get_word("Now we are cooking!", 5)) # Nothing
Explanation:
Added parts are highlighted.
If n is greater than 0, split the given sentence using split method and set it to the words.
If n is not more than the number of words, return the (n-1)th index of the words. Since the index starts at 0, (n-1)th index corresponds to the nth word
I think that 3 would be the correct answer
Question:
When multiple team members are working on a related feature, how often should they integrate their work
Select only one answer.
A) Do the integration midway through the iteration.
B) After they reach a logical end of creating the functionality.
C) In a scheduled daily (or multiple times in a day) frequency.
D) In a scheduled weekly (or multiple times in a week) frequency.
The best option is D.
Explanation:
Multiple integrations per day may become too cumbersome. Leaving the various parts of the project until a logical end for a functionality has been reached may create room for a lot of errors thus resulting in time wasted.
To ensure regular course correction (if required), twice a week would suffice.
Cheers!
Data Security
Yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.
Given that,
The charge for the plane ticket for the last month is $200.The minimum balance required is $25.And, the number of months given is 8.Based on the above information, the calculation is as follows:
= $25 × 8 months
= $200
Therefore we can conclude that yes, Bob is correct that only 8 months is required to pay off the amount of $200 for the ticket.
Learn more: link
(1)
public int getPlayer2Move(int round)
{
int result = 0;
//If round is divided by 3
if(round%3 == 0) {
result= 3;
}
//if round is not divided by 3 and is divided by 2
else if(round%3 != 0 && round%2 == 0) {
result = 2;
}
//if round is not divided by 3 or 2
else {
result = 1;
}
return result;
}
(2)
public void playGame()
{
//Initializing player 1 coins
int player1Coins = startingCoins;
//Initializing player 2 coins
int player2Coins = startingCoins;
for ( int round = 1 ; round <= maxRounds ; round++) {
//if the player 1 or player 2 coins are less than 3
if(player1Coins < 3 || player2Coins < 3) {
break;
}
//The number of coins player 1 spends
int player1Spends = getPlayer1Move();
//The number of coins player 2 spends
int player2Spends = getPlayer2Move(round);
//Remaining coins of player 1
player1Coins -= player1Spends;
//Remaining coins of player 2
player2Coins -= player2Spends;
//If player 2 spends the same number of coins as player 2 spends
if ( player1Spends == player2Spends) {
player2Coins += 1;
continue;
}
//positive difference between the number of coins spent by the two players
int difference = Math.abs(player1Spends - player2Spends) ;
//if difference is 1
if( difference == 1) {
player2Coins += 1;
continue;
}
//If difference is 2
if(difference == 2) {
player1Coins += 2;
continue;
}
}
// At the end of the game
//If player 1 coins is equal to player two coins
if(player1Coins == player2Coins) {
System.out.println("tie game");
}
//If player 1 coins are greater than player 2 coins
else if(player1Coins > player2Coins) {
System.out.println("player 1 wins");
}
//If player 2 coins is grater than player 2 coins
else if(player1Coins < player2Coins) {
System.out.println("player 2 wins");
}
}
It will provide an instant answer!