Discover ambiguities or omissions in the following statement of the requirements for part of a drone system intended for search and recovery:

The drone, a quad chopper, will be very useful in search and recovery operations, especially in remote areas or in extreme weather conditions. It will click high-resolution images. It will fly according to a path preset by a ground operator, but will be able to avoid obstacles on its own, returning to its original path whenever possible. The drone will also be able to identify various objects and match them to the target it is looking for.

Rewrite the above description using the structured approach described in this chapter. Resolve the identified ambiguities in a sensible way.

True, a retractable service pit cover can help other shop employees from falling into the pit while another technician is in the pit servicing a car.

Retractable service pit cover is a special cover made to cover service pit which aid inspection and repair of vehicle in an auto workshop.

In conclusion, the retractable service pit cover help other shop employees from falling into the pit even if they are aware of the structure.

Learn more about retractable service pit in picture attached

Code:

#include <iostream>

using namespace std;

int main()

{

  int Car_Year;

  cout<<"Please Enter the Car Model."<<endl;

  cin>>Car_Year;    

 if (Car_Year<1967)

 {

cout<<"Few safety features."<<endl;

 }

else if (Car_Year>1971 && Car_Year<=1991)

{

cout<<"Probably has head rests."<<endl;

}

else if (Car_Year>1991 && Car_Year<=2000)

{

cout<<"Probably has antilock brakes."<<endl;

}

else if (Car_Year>2000)

{

cout<<"Probably has airbags."<<endl;

  }

else

{

cout<<"Invalid Selection."<<endl;

}

  return 0;

}

Output:

Please Enter the Car Model.

1975

Probably has head rests.

Please Enter the Car Model.

1999

Probably has antilock brakes.

Please Enter the Car Model.

2005

Probably has airbags.

Please Enter the Car Model.

1955

Few safety features.

Explanation:

We were required to implement multiple If else conditions to assign car model year with the corresponding features of the car.

The code is tested with a wide range of inputs and it returned the same results as it was asked in the question.

NTQ

Explanation:

The given sequence is

BHE : FLI : JPM

If is clear that, alphabets on first places are B, F, J. Difference between their place vales is 4.

B+4=F,F+4=J ; so alphabet on first place of next term of sequence is J+4=N.

Similarly, alphabets on second places are H, L, P. Difference between their place vales is 4.

H+4=L,L+4=P ; so alphabet on second place of next term of sequence is P+4=T.

Alphabets on third places are E, I, M. Difference between their place vales is 4.

E+4=I,I+4=M ; so alphabet on third place of next term of sequence is M+4=Q.

Therefore, the next term is NTQ.

The following code or the program will be used

Explanation:

def readFile(filename):

   dict = {}

   with open(filename, 'r') as infile:

       lines = infile.readlines()

       for index in range(0, len(lines) - 1, 2):

           if lines[index].strip()=='':continue

           count = int(lines[index].strip())

           name = lines[index + 1].strip()

           if count in dict.keys():

               name_list = dict.get(count)

               name_list.append(name)

               name_list.sort()

           else:

               dict[count] = [name]

           print(count,name)

   return dict

def output_keys(dict, filename):

   with open(filename,'w+') as outfile:

       for key in sorted(dict.keys()):

           outfile.write('{}: {}\n'.format(key,';'.join(dict.get(key

           print('{}: {}\n'.format(key,';'.join(dict.get(key  

def output_titles(dict, filename):

   titles = []

   for title in dict.values():

       titles.extend(title)

   with open(filename,'w+') as outfile:

       for title in sorted(titles):

           outfile.write('{}\n'.format(title))

           print(title)

def main():

   filename = input('Enter input file name: ')

   dict = readFile(filename)

   if dict is None:

       print('Error: Invalid file name provided: {}'.format(filename))

       return

   print(dict)

   output_filename_1 ='output_keys.txt'

   output_filename_2 ='output_titles.txt'

   output_keys(dict,output_filename_1)

   output_titles(dict,output_filename_2)  

main()

B ). When cleaning a vessel, use regular  household detergents and cleaners.

Explanation:

Boat cleaning or vessel cleaning is a tedious job. It takes a lot of hard work to clean a vessel. We have to be careful while maintaining the vessel.

The products that we use to clean and maintain the vessels needs to chosen carefully. Many boat cleaning products have adverse effects on the marine life and aquatic animals. it also tends to pollute the water bodies.

These products may be corrosive in nature, toxic or poisonous.

So we must use the regular household detergents and cleaners to clean our vessels. The regular detergents do not cause any harm to the nature and the water bodies.

We can use phosphate free no detergent soaps which may include citrus based soap or vegetable based soaps.

Therefore, while cleaning or maintaining vessels , use the regular household detergents and cleaners.  

Thus option (B) is correct.

Learn more :

link

understanding others first before starting to explain your own point

Explanation:

Stephen covey believes the key to effective communication is understanding others first before starting to explain your own point. Communication is an important skill in life, in which one must have a good character in order to communicate effectively.

Here is the fractional_part() function:

def fractional_part(numerator, denominator):

   if denominator != 0:

       return (numerator % denominator)/denominator

   else:

       return 0

Explanation:

I will explain the code line by line.

The first statement it the definition of function fractional_part() which takes two parameters i.e. numerator and denominator to return the fractional part of the division.

Next is an if statement which checks if the value of denominator is 0. If this is true then the function returns 0. If this condition evaluates to false which means that the value of denominator is not 0 then return (numerator % denominator)/denominator  is executed. Now lets see how this statement works with the help of an example.

Lets say the value of numerator is 5 and denominator is 4. (numerator % denominator)/denominator will first compute the modulus of these two values. 5 % 4 is 1 because when 5 is divided by 4 , then the remainder is 1. Now this result is divided by denominator to get the fractional part. When 1 is divided by 4 the answer is 0.25. So this is how we get the fractional part which is 0.25.  

The program with output is attached.

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.