One lap around a standard high-school running track is exactly 0.25 miles. Write the function miles_to_laps() that takes a number of miles as an argument and returns the number of laps. Complete the program to output the number of laps. Output each floating-point value with two digits after the decimal point, which can be achieved as follows: print('{:.2f}'.format(your_value)) Ex: If the input is: 1.5 the output is: 6.00 Ex: If the input is: 2.2 the output is: 8.80 Your program must define and call the following function: def miles_to_laps(user_miles)

The program converts the number of miles enters by the user to an equivalent measure in laps is written in python 3 thus :

def miles_to_laps(miles):

#initialize the function which takes in a single parameter

return (miles/0.25)

mile_value= eval(input("Number of Miles: "))

#allows user to input a value representing distance in miles

print("Number of laps: ",end="")

#display Number o laps with cursor on th same line

print('{:.2f}'.format(miles_to_laps(mile_value)))

#pass user's vlaue to the function to Obtain the lap value.

A sample run of the program is attached.

The program converts the number of miles enters by the user to an equivalent measure in laps is written in python 3 thus :

def miles_to_laps(miles):

#initialize the function which takes in a single parameter

return (miles/0.25)

mile_value= eval(input("Number of Miles: "))

#allows user to input a value representing distance in miles

print("Number of laps: ",end="")

#display Number o laps with cursor on th same line

print('{:.2f}'.format(miles_to_laps(mile_value)))

#pass user's vlaue to the function to Obtain the lap value.

A sample run of the program is attached.

def miles_to_laps(mi):

   return f"{mi} mile(s) is {mi/0.25} lap(s)"

print(miles_to_laps(1))

I wrote my code in python 3.8. I hope this helps!

The python program to define a function def miles_to_laps() that takes a number of miles as an function argument and returns the number of laps is given below:

Program:

#defining the function miles_to_laps

def miles_to_laps(num_miles):

#returns the value

   return num_miles/0.25

#defining the variable num_miles for user-input

num_miles=float(input("Please enter the number of miles: "))

#x1 holds the function value

x1=miles_to_laps(num_miles)

#format function is used to display the results in the given format

print("{0:.2f} miles is {1:.2f} laps".format(num_miles,x1) )

Output:

Please enter the number of miles: 7.60

7.60 miles is 30.40 laps

Explanation:

True, a retractable service pit cover can help other shop employees from falling into the pit while another technician is in the pit servicing a car.

Retractable service pit cover is a special cover made to cover service pit which aid inspection and repair of vehicle in an auto workshop.

In conclusion, the retractable service pit cover help other shop employees from falling into the pit even if they are aware of the structure.

Learn more about retractable service pit in picture attached

"Test Phase " is the correct choice.

Explanation:

NTQ

Explanation:

The given sequence is

BHE : FLI : JPM

If is clear that, alphabets on first places are B, F, J. Difference between their place vales is 4.

B+4=F,F+4=J ; so alphabet on first place of next term of sequence is J+4=N.

Similarly, alphabets on second places are H, L, P. Difference between their place vales is 4.

H+4=L,L+4=P ; so alphabet on second place of next term of sequence is P+4=T.

Alphabets on third places are E, I, M. Difference between their place vales is 4.

E+4=I,I+4=M ; so alphabet on third place of next term of sequence is M+4=Q.

Therefore, the next term is NTQ.

The following code or the program will be used

Explanation:

def readFile(filename):

   dict = {}

   with open(filename, 'r') as infile:

       lines = infile.readlines()

       for index in range(0, len(lines) - 1, 2):

           if lines[index].strip()=='':continue

           count = int(lines[index].strip())

           name = lines[index + 1].strip()

           if count in dict.keys():

               name_list = dict.get(count)

               name_list.append(name)

               name_list.sort()

           else:

               dict[count] = [name]

           print(count,name)

   return dict

def output_keys(dict, filename):

   with open(filename,'w+') as outfile:

       for key in sorted(dict.keys()):

           outfile.write('{}: {}\n'.format(key,';'.join(dict.get(key

           print('{}: {}\n'.format(key,';'.join(dict.get(key  

def output_titles(dict, filename):

   titles = []

   for title in dict.values():

       titles.extend(title)

   with open(filename,'w+') as outfile:

       for title in sorted(titles):

           outfile.write('{}\n'.format(title))

           print(title)

def main():

   filename = input('Enter input file name: ')

   dict = readFile(filename)

   if dict is None:

       print('Error: Invalid file name provided: {}'.format(filename))

       return

   print(dict)

   output_filename_1 ='output_keys.txt'

   output_filename_2 ='output_titles.txt'

   output_keys(dict,output_filename_1)

   output_titles(dict,output_filename_2)  

main()

Energy equation from this week’s notes, your answer from #5, and Plank’s constant (6.63E-34) to find the approximate energy of this photon

Explanation:

1.The amount of energy in those photons is calculated by this equation, E = hf, where E is the energy of the photon in Joules; h is Planck's constant, which is always 6.63 * 10^-34 Joule seconds; and f is the frequency of the light in hertz

2.The first is Planck's equation, which was proposed by Max Planck to describe how energy is transferred in quanta or packets. Planck's equation makes it possible to understand blackbody radiation and the photoelectric effect. The equation is:

E = hν

where

E = energy

h = Planck's constant = 6.626 x 10-34 J·s

ν = frequency