Okay, so let's start by setting up this problem: (original number=x)(percentage=.06)=(percentage of original number) So it should look like this: (x)(.06)=51 Now we should divide .06 from each side x=850 And there we go! 850 is the answer. i hope this help
C(m) = 0.10m + 41 (Speedy charges a flat rate of $41 plus an additional fee of $0.10 per mile(m) driven)
T(m) = 0.25m (Tom's Car Rentals charges a fee of $0.25 per mile driven)
Since you know:
m = 200 miles Substitute/plug it into the equations to see the total cost for each company
C(m) = 0.10m + 41 Plug in 200 for "m"
C(200) = 0.10(200) + 41
C(200) = 20 + 41
C(200) = 61 They charge $61 for 200 miles
T(m) = 0.25m Plug in 200 for "m"
T(200) = 0.25(200)
T(200) = 50 They charge $50 for 200 miles
Tom's Car Rentals offers a better price for a one-day rental because for 200 miles, they charge $50 while Speedy's charges $61, which is $11 more expensive.
Okay, so let's start by setting up this problem: (original number=x)(percentage=.06)=(percentage of original number) So it should look like this: (x)(.06)=51 Now we should divide .06 from each side x=850 And there we go! 850 is the answer. i hope this help
C(m) = 0.10m + 41 (Speedy charges a flat rate of $41 plus an additional fee of $0.10 per mile(m) driven)
T(m) = 0.25m (Tom's Car Rentals charges a fee of $0.25 per mile driven)
Since you know:
m = 200 miles Substitute/plug it into the equations to see the total cost for each company
C(m) = 0.10m + 41 Plug in 200 for "m"
C(200) = 0.10(200) + 41
C(200) = 20 + 41
C(200) = 61 They charge $61 for 200 miles
T(m) = 0.25m Plug in 200 for "m"
T(200) = 0.25(200)
T(200) = 50 They charge $50 for 200 miles
Tom's Car Rentals offers a better price for a one-day rental because for 200 miles, they charge $50 while Speedy's charges $61, which is $11 more expensive.
For part a, y < x y > -2x Point B: (3,1) plugin x=3, y=1 y < x 1 < 3 which is true, so point B satisfies the first inequalityYou can graph the inequality y > 2x+5 and see which schools are in the shaded region (this should work)
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