20.06.2021

one of the legs of a right triangle measures 6 cm and it’s hypotenuse measures 10 find the measuring of the other leg

. 4

Faq

Mathematics
Step-by-step answer
P Answered by Specialist
I'm assuming you have or are taking trigonometry because that is how I solved this.  First find the angle between the hypotenuse and the horizontal leg.  To do this I took the inverse tangent of 5/2 (opposite/adjacent).  Notice how I took the inverse tangent of the vertical leg/ horizontal leg.  My calculator showed the answer to be about 68 degrees.  Because of some angle laws (I'm not sure which ones, just trust me) that angle in each triangle on that line (the one between the horizontal component and the hypotenuse) must all have the same degree measure.  Thus, test each answer by finding the inverse tangent of the vertical leg/horizontal leg.  If the answer is about 68 degrees, that triangle could be on the line as well.

A.  invtan(10/8)≈51
B. invtan(10/4)≈68
C. invtan(15/6)≈68
D. invtan(25/10)≈68
Mathematics
Step-by-step answer
P Answered by Specialist
I'm assuming you have or are taking trigonometry because that is how I solved this.  First find the angle between the hypotenuse and the horizontal leg.  To do this I took the inverse tangent of 5/2 (opposite/adjacent).  Notice how I took the inverse tangent of the vertical leg/ horizontal leg.  My calculator showed the answer to be about 68 degrees.  Because of some angle laws (I'm not sure which ones, just trust me) that angle in each triangle on that line (the one between the horizontal component and the hypotenuse) must all have the same degree measure.  Thus, test each answer by finding the inverse tangent of the vertical leg/horizontal leg.  If the answer is about 68 degrees, that triangle could be on the line as well.

A.  invtan(10/8)≈51
B. invtan(10/4)≈68
C. invtan(15/6)≈68
D. invtan(25/10)≈68
Mathematics
Step-by-step answer
P Answered by PhD
Answer: is correct B. the ratios are both identical (five thirteenths and five thirteenths).
First you have to find what cosine and sine are equal to. Sine is equal to Opposite/Hypotenuse and Co sine I adjecant/hypotenuse. And if you take the Sine from X you would get 5/13 because the opposite side is 5 and the hypotenuse is 13. And if you are going to get cosine from the Y you would see the adjecant is 5 and the hypotenuse is 13. So the Cosine is 5/13. That means they are identical.
Mathematics
Step-by-step answer
P Answered by Master

The answer is C. 2\sqrt{13}in^2.

Step-by-step explanation:

In order to determine the length of the hypotenuse, we have to know the pythagoras theorem.

The Pythagorean Theorem is a formula relating the lengths of the three sides of a right triangle.

If we take the length of the hypotenuse to be "m" and the length of the legs to be "h" and "k" then:

h^2+k^2=m^2

So, according to the problem, we have a right triangle and the values of both legs. Therefore it is possible to determine the hypotenuse:

h=4 in

k=6 in

(4)^2+(6)^2=m^2\\16+36=m^2\\m^2=52\\m=\sqrt{52}\\m=\sqrt{4*13} \\m=2\sqrt{13}

Finally, the length of the hypotenuse in inches is C. 2\sqrt{13}in^2.

Mathematics
Step-by-step answer
P Answered by Master

The answer is C. 2\sqrt{13}in^2.

Step-by-step explanation:

In order to determine the length of the hypotenuse, we have to know the pythagoras theorem.

The Pythagorean Theorem is a formula relating the lengths of the three sides of a right triangle.

If we take the length of the hypotenuse to be "m" and the length of the legs to be "h" and "k" then:

h^2+k^2=m^2

So, according to the problem, we have a right triangle and the values of both legs. Therefore it is possible to determine the hypotenuse:

h=4 in

k=6 in

(4)^2+(6)^2=m^2\\16+36=m^2\\m^2=52\\m=\sqrt{52}\\m=\sqrt{4*13} \\m=2\sqrt{13}

Finally, the length of the hypotenuse in inches is C. 2\sqrt{13}in^2.

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