History: What is the perimeter of this rectangle

What is the perimeter of this rectangle, №13223811, 16.08.2020 21:18

Advanced Placement (AP)

11. given the following class import java.util.arraylist; public class rectangletester { public static void main(string[ ] args) { arraylist rectangle shapes = new arraylist rectangle (); shapes.add(new rectangle(1, 1)); shapes.add(new rectangle(2, 2)); shapes.add(new rectangle(3, 3)); shapes.add(new rectangle(4, 4)); rectangle datarecord; for(int index = 0; index shapes.size(); index++) { datarecord = shapes.get(index); datarecord.calcrectarea(); datarecord.calcrectperimeter(); system.out.println(area = + datarecord.; system.out.println(perimeter

Step-by-step answer

P Answered by PhD

8

There are 4 rectangles in the ArrayList shapes. ArrayLists start counting at 0 so when index is 3, dataRecord will be the 4th rectangle. The length and width of the 4th rectangle in shapes are both 4 so the area is 16 and the perimeter is 16. The answer is 3.

Advanced Placement (AP)

11. given the following class import java.util.arraylist; public class rectangletester { public static void main(string[ ] args) { arraylist rectangle shapes = new arraylist rectangle (); shapes.add(new rectangle(1, 1)); shapes.add(new rectangle(2, 2)); shapes.add(new rectangle(3, 3)); shapes.add(new rectangle(4, 4)); rectangle datarecord; for(int index = 0; index shapes.size(); index++) { datarecord = shapes.get(index); datarecord.calcrectarea(); datarecord.calcrectperimeter(); system.out.println(area = + datarecord.; system.out.println(perimeter

Step-by-step answer

P Answered by PhD

8

There are 4 rectangles in the ArrayList shapes. ArrayLists start counting at 0 so when index is 3, dataRecord will be the 4th rectangle. The length and width of the 4th rectangle in shapes are both 4 so the area is 16 and the perimeter is 16. The answer is 3.

Mathematics

Which statement best describes the areas and perimeters of the figures below? Figures 1 and 2 both have the same perimeter, but have different numbers of units inside of the shape. They have the same area and same perimeter. They have the same area but different perimeters. They have different areas but the same perimeter. They have different areas and different perimeters.

Step-by-step answer

P Answered by Specialist

5

they have different areas and different perimeters

Mathematics

In the figure, . if the ratio of the perimeter of to that of is 3: 5 and the sum of the perimeters is 320, find the perimeter of each triangle. a. perimeter of = 192 perimeter of = 128 b. perimeter of = 120 perimeter of = 200 c. perimeter of = 200 perimeter of = 120 d. perimeter of = 128 perimeter of = 192 select the best answer from the choices provided a b c d

Step-by-step answer

P Answered by PhD

2

3x + 5x = 320

8x = 320

x = 40

3(40) : 5(40) = 120 : 200

The best answer would be Option C.

Mathematics

Nthe figure, 2004-02-04-06-00_files/i0250000.jpg. if the ratio of the perimeter of to that of is 3: 2 and the sum of the perimeters of the two triangles is 110, find the perimeter of each triangle. a. perimeter of = 66 perimeter of = 44 b. perimeter of = 73 perimeter of = 37 c. perimeter of = 37 perimeter of = 73 d. perimeter of = 44 perimeter of = 66

Step-by-step answer

P Answered by PhD

8

I assume you needed to add the diagram. However, I'll assume that we have triangle 1 and triangle 2 and solve the problem.
You can then follow the same steps on the triangles you have.
Let perimeter of triangle 1 be p1 and that of triangle 2 be p2

First, we know that the ratio between p1 : p2 is 3:2, this means that:
p1/p2 = 3/2
p1 = (3/2) p2 > equation I

We also know that the sum of perimeters is 110, this means that:
p1 + p2 = 110 > equation II

Substitute by equation I in equation II as follows:
(3/2) p2 + p2 = 110
(5/2) p2 = 110
p2 = 44

Substitute by p2 in equation I to get p1 as follows:
p1 = (3/2) (44) = 66

Therefore:
perimeter of triangle 1 = p1 = 66
perimeter of triangle 2 = p2 = 44

Mathematics

In the figure, . if the ratio of the perimeter of to that of is 3: 5 and the sum of the perimeters is 320, find the perimeter of each triangle. a. perimeter of = 192 perimeter of = 128 b. perimeter of = 120 perimeter of = 200 c. perimeter of = 200 perimeter of = 120 d. perimeter of = 128 perimeter of = 192 select the best answer from the choices provided a b c d

Step-by-step answer

P Answered by PhD

2

3x + 5x = 320

8x = 320

x = 40

3(40) : 5(40) = 120 : 200

The best answer would be Option C.

Mathematics

Which statement best describes the areas and perimeters of the figures below? Figures 1 and 2 both have the same perimeter, but have different numbers of units inside of the shape. They have the same area and same perimeter. They have the same area but different perimeters. They have different areas but the same perimeter. They have different areas and different perimeters.

Step-by-step answer

P Answered by Specialist

5

they have different areas and different perimeters

Mathematics

Which of the following statements are true? check all that apply. the perimeter of a square depends on the length of its sides. a square with a side length of 4 meters has a perimeter of 16 meters. a square with a side length of 6 meters has a perimeter of 24 meters. a. perimeter(16) = 4 b. perimeter(6) = 24 c. perimeter(24) = 6 d. perimeter(4) = 16

Step-by-step answer

P Answered by Master

6

It's hard to tell what the numbers are the way it is written out. B and D are correct if the number in parentheses is supposed to be the side length, since those numbers multiplied by four equal what it shows. If the number in parentheses is supposed to show the perimeter, then A and C are correct.

Mathematics

Nthe figure, 2004-02-04-06-00_files/i0250000.jpg. if the ratio of the perimeter of to that of is 3: 2 and the sum of the perimeters of the two triangles is 110, find the perimeter of each triangle. a. perimeter of = 66 perimeter of = 44 b. perimeter of = 73 perimeter of = 37 c. perimeter of = 37 perimeter of = 73 d. perimeter of = 44 perimeter of = 66

Step-by-step answer

P Answered by PhD

8

I assume you needed to add the diagram. However, I'll assume that we have triangle 1 and triangle 2 and solve the problem.
You can then follow the same steps on the triangles you have.
Let perimeter of triangle 1 be p1 and that of triangle 2 be p2

First, we know that the ratio between p1 : p2 is 3:2, this means that:
p1/p2 = 3/2
p1 = (3/2) p2 > equation I

We also know that the sum of perimeters is 110, this means that:
p1 + p2 = 110 > equation II

Substitute by equation I in equation II as follows:
(3/2) p2 + p2 = 110
(5/2) p2 = 110
p2 = 44

Substitute by p2 in equation I to get p1 as follows:
p1 = (3/2) (44) = 66

Therefore:
perimeter of triangle 1 = p1 = 66
perimeter of triangle 2 = p2 = 44

Mathematics

25 pts to who ever can with this question: a. find the perimeter of the square b. find the perimeter of the rectangle c. find the sum of the perimeters of the two figures if s=5 d. the perimeter of the rectangle is greater than the perimeter of the square. find the difference between the perimeters of the two figures if s=7

Step-by-step answer

P Answered by Specialist

A. 5s+2

B. 8s+8

C. 75

D. 27

Step-by-step explanation:

Is difficult to read the exact expressions. If a mistake is present then fix the number and use the same method.

A. The perimeter of the square is all 4 equal sides added together. The length of a side is $\frac{5s+2}{4}$ . Since there are four sides then: