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 30.04.2023

1.34 milligrams is the same as kg and g

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30.05.2023, solved by verified expert
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1 g = 1000 mg
1000 g = 1 kg

1.34 mg = 1.34 mg * 1g / 1000 mg = 0.00134 g

1.34 mg = 1.34 mg * 1g / 1000 mg * 1 kg / 1000 g = 0.00000134 kg
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Chemistry
Step-by-step answer
P Answered by Specialist

Answer : The 1.34 milligrams is the same as 1.34\times 10^{-6}kg and 1.34\times 10^{-3}g

Explanation :

The conversion used for mass from milligram to kilogram is:

1mg=10^{-6}kg

The conversion used for mass from milligram to gram is:

1mg=10^{-3}g

As we are given that the mass 1.34 mg. Now we have to determine the mass in kg and g.

Mass of 'kg' :

1mg=10^{-6}kg

1.34mg=\frac{1.34mg}{1mg}\times 10^{-6}kg=1.34\times 10^{-6}kg

Mass of 'g' :

1mg=10^{-3}g

1.34mg=\frac{1.34mg}{1mg}\times 10^{-3}g=1.34\times 10^{-3}g

Therefore, the 1.34 milligrams is the same as 1.34\times 10^{-6}kg and 1.34\times 10^{-3}g

Chemistry
Step-by-step answer
P Answered by Master

Answer : The 1.34 milligrams is the same as 1.34\times 10^{-6}kg and 1.34\times 10^{-3}g

Explanation :

The conversion used for mass from milligram to kilogram is:

1mg=10^{-6}kg

The conversion used for mass from milligram to gram is:

1mg=10^{-3}g

As we are given that the mass 1.34 mg. Now we have to determine the mass in kg and g.

Mass of 'kg' :

1mg=10^{-6}kg

1.34mg=\frac{1.34mg}{1mg}\times 10^{-6}kg=1.34\times 10^{-6}kg

Mass of 'g' :

1mg=10^{-3}g

1.34mg=\frac{1.34mg}{1mg}\times 10^{-3}g=1.34\times 10^{-3}g

Therefore, the 1.34 milligrams is the same as 1.34\times 10^{-6}kg and 1.34\times 10^{-3}g

Mathematics
Step-by-step answer
P Answered by PhD
1.34 milligrams is the same as 0.00000134 kg and 0.00134 gram.
There are 1000000 milligrams in one kilogram, so you just need to divide 1.34 milligrams to see how many there are in one kilogram. And there are 1000 milligrams in one gram, so you do the same thing.
History
Step-by-step answer
P Answered by PhD
1 g = 1000 mg
1000 g = 1 kg

1.34 mg = 1.34 mg * 1g / 1000 mg = 0.00134 g

1.34 mg = 1.34 mg * 1g / 1000 mg * 1 kg / 1000 g = 0.00000134 kg
Medicine
Step-by-step answer
P Answered by PhD

1.342 litres to millilitres=1,342

1,342 centigrams to grams=13.42

1,342 micrograms to milligrams=1.342

13.42 centiliters to microliters=1.342

Explanation:

hope this helps^_^

Medicine
Step-by-step answer
P Answered by PhD

1.342 litres to millilitres=1,342

1,342 centigrams to grams=13.42

1,342 micrograms to milligrams=1.342

13.42 centiliters to microliters=1.342

Explanation:

hope this helps^_^

StudenGPT
Step-by-step answer
P Answered by Studen AI
To find out how many palladium atoms there are in 341 milligrams of palladium, we can follow these steps:

Step 1: Convert the mass of a single palladium atom to grams.
Given: The mass of a single palladium atom is 1.77×10^(-22) grams.
To convert this value to grams, we can write it as 1.77×10^(-22) g.

Step 2: Calculate the number of atoms in 1 gram of palladium.
Since the mass of 1 mole of any element in grams is equal to its atomic mass, we can calculate the number of atoms in 1 gram using Avogadro's number, 6.022×10^(23) atoms/mol.
Number of atoms in 1 gram of palladium = Avogadro's number / Atomic mass of palladium
The atomic mass of palladium (Pd) is 106.42 g/mol.
Number of atoms in 1 gram of palladium = 6.022×10^(23) atoms/mol / 106.42 g/mol

Step 3: Calculate the number of atoms in 341 milligrams (0.341 grams) of palladium.
Number of atoms in 341 milligrams of palladium = (Number of atoms in 1 gram) x (0.341 grams)

Using the information above, let's calculate the number of atoms in 341 milligrams of palladium:

Step 1: Convert the mass of a single palladium atom to grams.
1.77×10^(-22) grams

Step 2: Calculate the number of atoms in 1 gram of palladium.
Number of atoms in 1 gram of palladium = (6.022×10^(23) atoms/mol) / (106.42 g/mol)
≈ 5.67×10^(21) atoms/g

Step 3: Calculate the number of atoms in 341 milligrams (0.341 grams) of palladium.
Number of atoms in 341 milligrams of palladium = (5.67×10^(21) atoms/g) x (0.341 grams)
≈ 1.93×10^(21) atoms

Therefore, there are approximately 1.93×10^(21) palladium atoms in 341 milligrams of palladium.
StudenGPT
Step-by-step answer
P Answered by Studen AI
To find out how many palladium atoms there are in 341 milligrams of palladium, we can follow these steps:

Step 1: Convert the mass of a single palladium atom to grams.
Given: The mass of a single palladium atom is 1.77×10^(-22) grams.
To convert this value to grams, we can write it as 1.77×10^(-22) g.

Step 2: Calculate the number of atoms in 1 gram of palladium.
Since the mass of 1 mole of any element in grams is equal to its atomic mass, we can calculate the number of atoms in 1 gram using Avogadro's number, 6.022×10^(23) atoms/mol.
Number of atoms in 1 gram of palladium = Avogadro's number / Atomic mass of palladium
The atomic mass of palladium (Pd) is 106.42 g/mol.
Number of atoms in 1 gram of palladium = 6.022×10^(23) atoms/mol / 106.42 g/mol

Step 3: Calculate the number of atoms in 341 milligrams (0.341 grams) of palladium.
Number of atoms in 341 milligrams of palladium = (Number of atoms in 1 gram) x (0.341 grams)

Using the information above, let's calculate the number of atoms in 341 milligrams of palladium:

Step 1: Convert the mass of a single palladium atom to grams.
1.77×10^(-22) grams

Step 2: Calculate the number of atoms in 1 gram of palladium.
Number of atoms in 1 gram of palladium = (6.022×10^(23) atoms/mol) / (106.42 g/mol)
≈ 5.67×10^(21) atoms/g

Step 3: Calculate the number of atoms in 341 milligrams (0.341 grams) of palladium.
Number of atoms in 341 milligrams of palladium = (5.67×10^(21) atoms/g) x (0.341 grams)
≈ 1.93×10^(21) atoms

Therefore, there are approximately 1.93×10^(21) palladium atoms in 341 milligrams of palladium.
Mathematics
Step-by-step answer
P Answered by PhD

z=-2.33

And if we solve for a we got

a=188 -2.33*41.3=91.771

The highest total cholesterol level a woman in this 20–34 age group can have and still be in the bottom 1% is 91.771 mg per deciliter

Step-by-step explanation:

Let X the random variable that represent the cholesterol level of a population of women between 20-34, and for this case we know the distribution for X is given by:

X \sim N(188,41.3)  

Where \mu=188 and \sigma=41.3

We want to find the highest value for the bottom 1% in the distribution, so we need to find a value a who satisfy the following conditions:

P(Xa)=0.99   (a)

P(X   (b)

We can find a z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. And we can verify that on this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.099

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-2.33

And if we solve for a we got

a=188 -2.33*41.3=91.771

The highest total cholesterol level a woman in this 20–34 age group can have and still be in the bottom 1% is 91.771 mg per deciliter

Mathematics
Step-by-step answer
P Answered by Specialist

Hello i hope you are having a good day :)

Question 1 : A cooking show currently has about 223,000 regular viewers. The number of regular viewers has been decreasing at a rate of 4.7% per year. Which is the best prediction for the number of regular viewers the show will have in 6 years? = y = 223000(1-0.047)⁶ = 223000(0.953)⁶ = 167,056.

Question 2 : A population of 30,000 fish is expected to shrink at a rate of 7.5% per year.  Which is the best prediction for the fish population in 8 years?       = 30,000(1−7.5/100)8≈ 16078.9

Question 3 : Bromine-82 has a half-life of about 35 hours.  After 140 hours, how many millilitres of an 80 ml sample will remain?  = Divide 80(1/2)^4 to get 5.

Question 4 : Polonium-218 has a half-life of about 3 minutes.  After 15 minutes, how many milligrams of a 120 mg sample will remain? = 3.75 mg

Question 8 : Pippa is holding the end of her kite string 1.4 m above the ground. The kite string rises at a 63° angle of elevation. Pippa has let out all 75 m of string.  To the nearest tenth of a meter, how high above the ground is the kite? = 68.2 m

Question 9 : Using his telescope, Tommy watches a bald eagle as it sits on the top of a cliff. The telescope is positioned so that the line of sight to the eagle forms a 38° angle of elevation. The telescope sits 1.3 m above the ground and the base of the telescope is 116 m from the base of the cliff.  To the nearest tenth of a meter, how high above the ground is the eagle? = 91.9 m

Question 10 : A photographer's camera sits on a tripod that is 1.8 m above the ground. The base of the tripod is 44 m from the base of a tree. The photographer spots a woodpecker in the tree at a 39° angle of elevation. To the nearest tenth of a meter, how high above the ground is the woodpecker? =  37.4 m

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