05.08.2022

If f(x) = 2x^2 - x - 6 and g(x) = x2 -4 , find f(x ÷g(x)

. 4

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Mathematics
Step-by-step answer
P Answered by PhD

Part 1) f(6)=30

Part 2) f(4)=27

Part 3) g(-2)=6

Part 4) Part 5) Part 6) and part 7) in the procedure

Step-by-step explanation:

Part 1) we have

f(x)=2.50x+15

we know that

f(6) is the value of the function when x=6

so

substitute the value of x in the function

f(6)=2.50(6)+15=30

Part 2) we have

f(x)=42-3.75x

we know that

f(4) is the value of the function when x=4

so

substitute the value of x in the function

f(4)=42-3.75(4)=27

Part 3) we have

g(x)=5x+16

we know that

g(-2) is the value of the function when x=-2

so

substitute the value of x in the function

g(-2)=5(-2)+16=6

Part 4) Which of the following functions match these outcomes:

f(1)=6

we know that

f(1) is the value of the function when x=1

so

substitute the value of x in each of the functions and then compare

f(1)=5(1)+1=6-----> this function matches the outcome

f(1)=4(1)+2=6-----> this function matches the outcome

f(1)=(1)^{2}+4 =5-----> this function does not match the outcome

f(1)=2(1)+4=6-----> this function matches the outcome

f(1)=12-2(1)=10-----> this function does not match the outcome

Part 5) Which of the following functions match these outcomes:

f(2)=8

we know that

f(2) is the value of the function when x=2

so

substitute the value of x in each of the functions and then compare

f(2)=5(2)+1=11-----> this function does not match the outcome

f(2)=4(2)+2=10-----> this function does not match the outcome

f(2)=(2)^{2}+4 =8-----> this function matches the outcome

f(2)=2(2)+4=8-----> this function matches the outcome

f(2)=12-2(2)=6-----> this function does not match the outcome

Part 6) Which of the following functions match these outcomes:

f(3)=10

we know that

f(3) is the value of the function when x=3

so

substitute the value of x in each of the functions and then compare

f(3)=5(3)+1=16-----> this function does not match the outcome

f(3)=4(3)+2=14-----> this function does not match the outcome

f(3)=(3)^{2}+4 =13-----> this function does not match the outcome

f(3)=2(3)+4=10-----> this function matches the outcome

f(3)=12-2(3)=6-----> this function does not match the outcome

Part 7) Which of the following functions match these outcomes:

f(4)=12

we know that

f(4) is the value of the function when x=4

so

substitute the value of x in each of the functions and then compare

f(4)=5(4)+1=21-----> this function does not match the outcome

f(4)=4(4)+2=18-----> this function does not match the outcome

f(4)=(4)^{2}+4 =20-----> this function does not match the outcome

f(4)=2(4)+4=12-----> this function matches the outcome

f(4)=12-2(4)=4-----> this function does not match the outcome

Mathematics
Step-by-step answer
P Answered by PhD

Part 1) f(6)=30

Part 2) f(4)=27

Part 3) g(-2)=6

Part 4) Part 5) Part 6) and part 7) in the procedure

Step-by-step explanation:

Part 1) we have

f(x)=2.50x+15

we know that

f(6) is the value of the function when x=6

so

substitute the value of x in the function

f(6)=2.50(6)+15=30

Part 2) we have

f(x)=42-3.75x

we know that

f(4) is the value of the function when x=4

so

substitute the value of x in the function

f(4)=42-3.75(4)=27

Part 3) we have

g(x)=5x+16

we know that

g(-2) is the value of the function when x=-2

so

substitute the value of x in the function

g(-2)=5(-2)+16=6

Part 4) Which of the following functions match these outcomes:

f(1)=6

we know that

f(1) is the value of the function when x=1

so

substitute the value of x in each of the functions and then compare

f(1)=5(1)+1=6-----> this function matches the outcome

f(1)=4(1)+2=6-----> this function matches the outcome

f(1)=(1)^{2}+4 =5-----> this function does not match the outcome

f(1)=2(1)+4=6-----> this function matches the outcome

f(1)=12-2(1)=10-----> this function does not match the outcome

Part 5) Which of the following functions match these outcomes:

f(2)=8

we know that

f(2) is the value of the function when x=2

so

substitute the value of x in each of the functions and then compare

f(2)=5(2)+1=11-----> this function does not match the outcome

f(2)=4(2)+2=10-----> this function does not match the outcome

f(2)=(2)^{2}+4 =8-----> this function matches the outcome

f(2)=2(2)+4=8-----> this function matches the outcome

f(2)=12-2(2)=6-----> this function does not match the outcome

Part 6) Which of the following functions match these outcomes:

f(3)=10

we know that

f(3) is the value of the function when x=3

so

substitute the value of x in each of the functions and then compare

f(3)=5(3)+1=16-----> this function does not match the outcome

f(3)=4(3)+2=14-----> this function does not match the outcome

f(3)=(3)^{2}+4 =13-----> this function does not match the outcome

f(3)=2(3)+4=10-----> this function matches the outcome

f(3)=12-2(3)=6-----> this function does not match the outcome

Part 7) Which of the following functions match these outcomes:

f(4)=12

we know that

f(4) is the value of the function when x=4

so

substitute the value of x in each of the functions and then compare

f(4)=5(4)+1=21-----> this function does not match the outcome

f(4)=4(4)+2=18-----> this function does not match the outcome

f(4)=(4)^{2}+4 =20-----> this function does not match the outcome

f(4)=2(4)+4=12-----> this function matches the outcome

f(4)=12-2(4)=4-----> this function does not match the outcome

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

The solution is in the following image

The solution is in the following image
Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD
The answer is in the image 

The answer is in the image 

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 

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