Answer:
Step-by-step explanation:
Principal amount p = $375000
Per annum interest I = $28125
Let r is the rate of interest.
Time t = 1
We know, I = prt/100
28125 = 375000×r×1/100
28125 = 3750r
r = 28125/3750
r = 7.5
So he can afford 7.5% interest rate
The interest rate can he afford to pay on his | loan =7.5%
Given: Principal amount = 375,000
Interest amount per year = $28,125
Interest percentage =
Hence, The interest rate can he afford to pay on his | loan =7.5%
The total nom of code that can be used is equal to 5+3 = 8
F=ma
where F=force
m=mass
a=acceleration
Here,
F=4300
a=3.3m/s2
m=F/a
=4300/3.3
=1303.03kg
30% of 420 are first year students
first year students = (30/100 )*420
=126 students
Student who are not in first year = 420-126
=294 students
Area of rectangle= L*b
here,
L=12.4 cm
b= 8.8 cm
A= L*b
= 12.4 * 8.8 = 109.12 cm^2
Let the father's age be x and son's be y
10 years before-
Father age=x-10
sons age=y-10
Given,
x-10=10(y-10)
x-10=10y-100
Given present age of father=40
therefore,
x=40
40-10=10y-100
10y-100=30
10y=130
y=130/10
y=13
Therefore present age of son=13years
The solution is given below
The answer is in the image
Decrease in bikes sale = 650 - 572 = 78
%Decrease = (change)/old value * 100
%Decrease in sale = 78/650 * 100 = 12%
Decrease in sale = 12%
It will provide an instant answer!