Mathematics : asked on wibi1963
 26.10.2020

In one hour, Ed used 2/5 of the time to complete his homework and 1/4 of the time to check his email. How much time did he spend completing homework and checking email? Write your answer as a fraction (Extension: Write the answer in minutes.)

. 6

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Mathematics
Step-by-step answer
P Answered by PhD

\dfrac{13}{20}

Step-by-step explanation:

He used \dfrac{2}{5} of an hour to complete his homework and \dfrac{1}{4} of an hour to check his email. In total, he spent

\dfrac{2}{5}+\dfrac{1}{4}=\dfrac{2\cdot 4+1\cdot 5}{5\cdot 4}=\dfrac{13}{20}

of an hour completing homework anf checking email.

Mathematics
Step-by-step answer
P Answered by PhD

\dfrac{13}{20}

Step-by-step explanation:

He used \dfrac{2}{5} of an hour to complete his homework and \dfrac{1}{4} of an hour to check his email. In total, he spent

\dfrac{2}{5}+\dfrac{1}{4}=\dfrac{2\cdot 4+1\cdot 5}{5\cdot 4}=\dfrac{13}{20}

of an hour completing homework anf checking email.

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

The solution is in the following image

The solution is in the following image
Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

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