23.10.2020

a system of two equations has no solution if the graphs of the two equations are coincident line .

. 5

Faq

Mathematics
Step-by-step answer
P Answered by Master

 The answer is NO.


Step-by-step explanation: The given statement is -

If the graph of two equations are coincident lines, then that system of equations will have no solution.

We are to check whether the above statement is correct or not.

Any two equations having graphs as coincident lines are of the form -

ax+by=c,\\\\dax+dby=dc,\\\\\textup{where}~~d\neq 1.

If we take d = 1, then both the equations will be same.

Now, subtracting the second equation from first, we have

a(1-d)x+b(1-d)y=c(1-d)\\\\\Rightarrow ax+by=c,~\textup{since}~d\neq 1,~\textup{so}~1-d\neq 0.

Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.

For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.

2x+5y=10,\\\\6x+15y=30.

Thus, the given statement is not correct.



Is the following statement correct?  explain.  a system of two equations has no solution if the grap
Mathematics
Step-by-step answer
P Answered by Master

 The answer is NO.


Step-by-step explanation: The given statement is -

If the graph of two equations are coincident lines, then that system of equations will have no solution.

We are to check whether the above statement is correct or not.

Any two equations having graphs as coincident lines are of the form -

ax+by=c,\\\\dax+dby=dc,\\\\\textup{where}~~d\neq 1.

If we take d = 1, then both the equations will be same.

Now, subtracting the second equation from first, we have

a(1-d)x+b(1-d)y=c(1-d)\\\\\Rightarrow ax+by=c,~\textup{since}~d\neq 1,~\textup{so}~1-d\neq 0.

Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.

For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.

2x+5y=10,\\\\6x+15y=30.

Thus, the given statement is not correct.



Is the following statement correct?  explain.  a system of two equations has no solution if the grap
Mathematics
Step-by-step answer
P Answered by PhD

(A) y - 7 = 2(x -2)

(B) y = -x + 6; y - 5 = -1(x + 1)

(C) Consistent independent

(D) (1, 5)

Step-by-step explanation:

(A) Road 1

(a) Slope

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)     Insert the points  

 3 - 7 = m(0 - 2)

     -4 = m(-2)           Divide each side by -2

     m = -4/(-2)          Divide numerator and denominator by-2,

      m = 2

=====

(b) y-intercept

y₂ - y₁ = m(x₂ - x₁)

y₂ - 7 = 2(x₂ -2)

y - 7 = 2(x -2)

===============

(B) Road 2

(a) Slope

y = mx + b

Choose point (3,3)

m = (3 - 5)/(3 - 1)

m = -2/2

m = -1

=====

(b) y-intercept

y = mx +b

Choose point (3,3).

3 = -3 + b      Add 3 to each side

b = 6

=====

(c) Equation of line (point-slope form)

y = mx + b

y = -x + 6

=====

(d) Equation of line (slope-intercept form)

y - 5 = -1(x - 1)

===============

(C) Consistency

The two roads intersect.

There is only one point of intersection, so this is a consistent, independent system of equations

===============

(D) Point of intersection

(1)      y - 7 = 2(x -  2)

(2)          y =   -x + 6     Substitute (2) into (1)

-x + 6 – 7 = 2(x – 2)    Remove parentheses

       -x - 1 = 2x – 4      Add 4 to each side

       -x +3 = 2x            Add x to each side

             3 = 3x            Divide each side by 3

             x = 1               Substitute into 2

=====

            y = -1 + 6

           y = 5

The point of intersection is (1, 5).


Two roads are represented by lines on a coordinate grid. two points on each of the roads are shown i
Mathematics
Step-by-step answer
P Answered by PhD

(A) y - 7 = 2(x -2)

(B) y = -x + 6; y - 5 = -1(x + 1)

(C) Consistent independent

(D) (1, 5)

Step-by-step explanation:

(A) Road 1

(a) Slope

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)     Insert the points  

 3 - 7 = m(0 - 2)

     -4 = m(-2)           Divide each side by -2

     m = -4/(-2)          Divide numerator and denominator by-2,

      m = 2

=====

(b) y-intercept

y₂ - y₁ = m(x₂ - x₁)

y₂ - 7 = 2(x₂ -2)

y - 7 = 2(x -2)

===============

(B) Road 2

(a) Slope

y = mx + b

Choose point (3,3)

m = (3 - 5)/(3 - 1)

m = -2/2

m = -1

=====

(b) y-intercept

y = mx +b

Choose point (3,3).

3 = -3 + b      Add 3 to each side

b = 6

=====

(c) Equation of line (point-slope form)

y = mx + b

y = -x + 6

=====

(d) Equation of line (slope-intercept form)

y - 5 = -1(x - 1)

===============

(C) Consistency

The two roads intersect.

There is only one point of intersection, so this is a consistent, independent system of equations

===============

(D) Point of intersection

(1)      y - 7 = 2(x -  2)

(2)          y =   -x + 6     Substitute (2) into (1)

-x + 6 – 7 = 2(x – 2)    Remove parentheses

       -x - 1 = 2x – 4      Add 4 to each side

       -x +3 = 2x            Add x to each side

             3 = 3x            Divide each side by 3

             x = 1               Substitute into 2

=====

            y = -1 + 6

           y = 5

The point of intersection is (1, 5).


Two roads are represented by lines on a coordinate grid. two points on each of the roads are shown i
Physics
Step-by-step answer
P Answered by Master

a) The sketch is attached.

b) The angular speed of the new system is 3 rad/s

c) The angular speed of the new system is 2 rad/s

Explanation:

b) The angular speed of the system is:

I_{i} w_{i} =I_{f} w_{f}

Where

Ii = I

If = I + I

wi = 6 rad/s

Replacing:

I*6=(I+I)w_{f} \\w_{f} =\frac{6I}{2I} =3rad/s

c) If a third disk is dropped, the angular speed is:

I*6=(I+I+I)w_{f} \\w_{f} =\frac{6I}{3I} =2rad/s


(3 points) A disk is spinning freely with angular speed 6.0 rad/s when a second identical disk, init
Mathematics
Step-by-step answer
P Answered by Specialist

If a graph of a system of two equations shows two lines that coincide on a coordinate plan there would be C.)Infinitely many solutions

I hope this helps, have a great day.

Physics
Step-by-step answer
P Answered by Specialist

a) The sketch is attached.

b) The angular speed of the new system is 3 rad/s

c) The angular speed of the new system is 2 rad/s

Explanation:

b) The angular speed of the system is:

I_{i} w_{i} =I_{f} w_{f}

Where

Ii = I

If = I + I

wi = 6 rad/s

Replacing:

I*6=(I+I)w_{f} \\w_{f} =\frac{6I}{2I} =3rad/s

c) If a third disk is dropped, the angular speed is:

I*6=(I+I+I)w_{f} \\w_{f} =\frac{6I}{3I} =2rad/s


(3 points) A disk is spinning freely with angular speed 6.0 rad/s when a second identical disk, init
Mathematics
Step-by-step answer
P Answered by Specialist

If a graph of a system of two equations shows two lines that coincide on a coordinate plan there would be C.)Infinitely many solutions

I hope this helps, have a great day.

Mathematics
Step-by-step answer
P Answered by Master
Rewrite the first equation: 3y=-2x-17. The equations are coincidental and -17 is one sixth of -102 so the other coefficients need to be multiplied by 6: 18y=-12x-102.

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