The moment of inertia must be taken about an axis through the center of mass
Explanation:
c.The moment of inertia must be taken about an axis through the center of mass.
Explanation:
The movements of rigid bodies can always be divided into the translation movement of the center of mass and that of rotation around the center of mass. However, we can demonstrate that this is true for the kinetic energy of a rigid body that has both translational and rotational movement.
In this case the kinetic energy of the body is the sum of a part associated with the movement of the center of mass and another part associated with the rotation about an axis passing through the center of mass. This is all represented by the form Ktot = Kr + Kt, however we must consider that the moment of inertia must be taken around an axis through the center of mass, since rigid bodies at rest tend to remain at rest.
The answer is in the image
The total nom of code that can be used is equal to 5+3 = 8
The solution is in the following image
F=ma
where F=force
m=mass
a=acceleration
Here,
F=4300
a=3.3m/s2
m=F/a
=4300/3.3
=1303.03kg
Approximately it is aqual to 1300kg
The solution is given in the image below
The wood before starting =12 feet
Left wood=6 feet
Wood used till now=12-6=6 feet
Picture frame built till now= 6/(3/4)
=8 pieces
Therefore, till now 8 pieces have been made.
The wood before starting =12 feet
Left wood=6 feet
Wood used till now=12-6=6 feet
Picture frame built till now= 6/(3/4)
=8 pieces
Therefore, till now 8 pieces have been made.
30% of 420 are first year students
first year students = (30/100 )*420
=126 students
Student who are not in first year = 420-126
=294 students
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