What is an equation that represents the function for 72x+12y=60?
A.120y+720x=600
B. y=5-6x
C. 2y+12x=10

The equivalent equations to  72x+12y=60 are:

The given equation is:

72x+12y=60

To find the equivalent equations, follow the steps below

Multiply the equation 72x+12y=60 by 10

10(72x) + 10(12y) = 10(60)

720x  +  120y   =  600

Divide the equation 72x+12y=60 by 12

(72x/12)  +  (12y/12) = 60/12

6x  +  y   =  5

y  =  5  -  6x

Divide the equation 72x+12y=60 by 72

(72x/72)  +  (12y/72) = 60/72

x  +  y/6  =  5/6

x  =  5/6  -  y/6

The equivalent equations to  72x+12y=60 are:

Learn more on equivalent functions here: link

The equivalent equations to  72x+12y=60 are:

The given equation is:

72x+12y=60

To find the equivalent equations, follow the steps below

Multiply the equation 72x+12y=60 by 10

10(72x) + 10(12y) = 10(60)

720x  +  120y   =  600

Divide the equation 72x+12y=60 by 12

(72x/12)  +  (12y/12) = 60/12

6x  +  y   =  5

y  =  5  -  6x

Divide the equation 72x+12y=60 by 72

(72x/72)  +  (12y/72) = 60/72

x  +  y/6  =  5/6

x  =  5/6  -  y/6

The equivalent equations to  72x+12y=60 are:

Learn more on equivalent functions here: link

The answer is in the image 

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

The total nom of  code that can be used is equal to 5+3 = 8

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The answer is in the image