06.11.2022

bag contains 12 red M&Ms, 12 blue M&Ms, and 12 green M&Ms. What is the probability of drawing two M&Ms of the same color in a row?

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StudenGPT
Step-by-step answer
P Answered by Studen AI
The impact of the narrator's statement "And here we aren't, so quickly" on the passage as a whole is that it reveals the narrator's reflection on their life in a nostalgic and regretful manner. It suggests that time has passed by quickly, and the narrator is contemplating missed opportunities and the things that could have been. The statement conveys a sense of longing and sadness, as the narrator expresses disappointment about the unfulfilled potentials in their life. It indicates that the passage explores themes of lost time, missed connections, and the fleeting nature of existence. The narrator's reflection on their past highlights the importance of cherishing the present moment, as it's a reminder that life passes by quickly and that we should make the most of each experience. Therefore, option D, "It reveals that the narrator is looking back on their life while grieving their partner's death," is the most accurate interpretation of the impact of the statement on the passage as a whole.
Mathematics
Step-by-step answer
P Answered by Master

0.1170 = 11.70% probability that the bag we selected contains more than 12% blue M&Ms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Mars Candy claims that 10% of all M&Ms are blue.

This means that p = 0.1

The particular bag we examine contains 320 M&Ms.

This means that n = 320

Mean and standard deviation:

\mu = p = 0.1

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.1*0.9}{320}} = 0.0168

What is the probability that the bag we selected contains more than 12% blue M&Ms?

This is 1 subtracted by the pvalue of Z when X = 0.12. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.12 - 0.1}{0.0168}

Z = 1.19

Z = 1.19 has a pvalue of 0.8830

1 - 0.8830 = 0.1170

0.1170 = 11.70% probability that the bag we selected contains more than 12% blue M&Ms.

Mathematics
Step-by-step answer
P Answered by Specialist

0.1170 = 11.70% probability that the bag we selected contains more than 12% blue M&Ms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Mars Candy claims that 10% of all M&Ms are blue.

This means that p = 0.1

The particular bag we examine contains 320 M&Ms.

This means that n = 320

Mean and standard deviation:

\mu = p = 0.1

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.1*0.9}{320}} = 0.0168

What is the probability that the bag we selected contains more than 12% blue M&Ms?

This is 1 subtracted by the pvalue of Z when X = 0.12. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.12 - 0.1}{0.0168}

Z = 1.19

Z = 1.19 has a pvalue of 0.8830

1 - 0.8830 = 0.1170

0.1170 = 11.70% probability that the bag we selected contains more than 12% blue M&Ms.

Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

15 red, 12 green, 15 blue, 18 blacktotal of 60 swimsuits

probability of picking a green ...

so there is 12 green out of 60 swimsuits

P(green) = 12/60 which reduces to 1/5 <===

Mathematics
Step-by-step answer
P Answered by Specialist
I. I am a man of God. Yes. I read the newspaper and drink holy water. Yes I wear glasses and have a very neat mustache. I wear pointy shoes and file my feet so they fit so my feet are as pointy as God’s holy sword he fought the devil on page 6 of the Bible. Yes. Yes I drink holy coffee and wear the skins of my enemies. I also know Russian and only eat Russian grapes from the deep depths of HELL
Think about tossing two coins. 1. What is a) P (H on first coin)? …………………………. b) P (H on second coin
Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

15 red, 12 green, 15 blue, 18 blacktotal of 60 swimsuits

probability of picking a green ...

so there is 12 green out of 60 swimsuits

P(green) = 12/60 which reduces to 1/5 <===

Mathematics
Step-by-step answer
P Answered by PhD

Blue

1 / n

Red

n-1 / n = 1 - 1 / n

7 red containers

Step-by-step explanation:

If there are "n" counters in total but we know that one is blue it means that there are "n - 1" red counters, which means that the probability for when one of them is:

Blue

1 / n

Red

n-1 / n = 1 - 1 / n

for part b, we have that the probability is 0.125, that is:

1 / n = 0.125

if we solve for n:

n = 1 / 0.125

n = 8

knowing that of the 8 one is blue, it means that the rest are red, that is to say that there are 7 (8 - 1) red containers

Mathematics
Step-by-step answer
P Answered by PhD

The odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

Step-by-step explanation:

Red candies = 14

Blue candies = 10

Green candies =  5

Brown candies = 11

Orange candies = 3

Yellow candies = 12

Total No. of candies = 14+10+5+11+3+12 = 55

(a) the odds of getting a green M&M

Green candies = 5

Total number of candies excluding green or unfavorable = 50

Odds of getting a green M&M  = \frac{\text{favorable outcome}}{\text{Unfavorable outcomes}}

                                                   = \frac{5}{50}

                                                   = \frac{1}{10}

(b) the probability of getting a green M&M

Green candies = 5

Total No. of candies = 55

So,  the probability of getting a green M&M =\frac{5}{55}

                                                                        =\frac{1}{11}

Hence the odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

Mathematics
Step-by-step answer
P Answered by PhD

The odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

Step-by-step explanation:

Red candies = 14

Blue candies = 10

Green candies =  5

Brown candies = 11

Orange candies = 3

Yellow candies = 12

Total No. of candies = 14+10+5+11+3+12 = 55

(a) the odds of getting a green M&M

Green candies = 5

Total number of candies excluding green or unfavorable = 50

Odds of getting a green M&M  = \frac{\text{favorable outcome}}{\text{Unfavorable outcomes}}

                                                   = \frac{5}{50}

                                                   = \frac{1}{10}

(b) the probability of getting a green M&M

Green candies = 5

Total No. of candies = 55

So,  the probability of getting a green M&M =\frac{5}{55}

                                                                        =\frac{1}{11}

Hence the odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

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