Mathematics: What’s the radius of the pond ?

What’s the radius of the pond ?, №12486012, 13.09.2021 17:11

Computers and Technology

1. write a tostring method for this class. the method should return a string containing the radius and area of the circle. 2. write an equals method for this class. the method should accept a circle object as an argument. it should return true if the argument object contains the same data as the calling object, or false otherwise. 3. write a greaterthan method for this class. the method should accept a circle object as an argument. it should return true if the argument object has an area that is greater than the area of the calling object, or false

Step-by-step answer

P Answered by Master

4

public class Circle {

private double radius;

public Circle(double r)

{

radius = r;

}

public double getArea()

{

return Math.PI * radius * radius;

}

public double getRadius()

{

return radius;

}

public String toString()

{

String str;

str = "Radius: " + radius +

"Area: " + getArea();

return str;

}

public boolean equals(Circle c)

{

boolean status;

if(c.getRadius() == radius)

status = true;

else

status = false;

return status;

}

public boolean greaterThan(Circle c)

{

boolean status;

if(c.getArea() > getArea())

status = true;

else

status = false;

return status;

}

Explanation:

There is nothing with the logic of your code it work fine the problem is with the structure of your code you added an extra curly brace before declaring (r)

Am talking about this section

public class Circle {

{

private double radius;

It should be

public class Circle {

private double radius;

Computers and Technology

1. write a tostring method for this class. the method should return a string containing the radius and area of the circle. 2. write an equals method for this class. the method should accept a circle object as an argument. it should return true if the argument object contains the same data as the calling object, or false otherwise. 3. write a greaterthan method for this class. the method should accept a circle object as an argument. it should return true if the argument object has an area that is greater than the area of the calling object, or false

Step-by-step answer

P Answered by Master

4

public class Circle {

private double radius;

public Circle(double r)

{

radius = r;

}

public double getArea()

{

return Math.PI * radius * radius;

}

public double getRadius()

{

return radius;

}

public String toString()

{

String str;

str = "Radius: " + radius +

"Area: " + getArea();

return str;

}

public boolean equals(Circle c)

{

boolean status;

if(c.getRadius() == radius)

status = true;

else

status = false;

return status;

}

public boolean greaterThan(Circle c)

{

boolean status;

if(c.getArea() > getArea())

status = true;

else

status = false;

return status;

}

Explanation:

There is nothing with the logic of your code it work fine the problem is with the structure of your code you added an extra curly brace before declaring (r)

Am talking about this section

public class Circle {

{

private double radius;

It should be

public class Circle {

private double radius;

Computers and Technology

Write a program that takes the radius of a sphere (a floating-point number) as input and then outputs the sphere’s: diameter (2 × radius) circumference (diameter × π) surface area (4 × π × radius × radius) volume (4/3 × π × radius × radius × radius)

Step-by-step answer

P Answered by PhD

1

#include<iostream>

using namespace std;

int main(){

float radius;

cout<<"Enter the radius of the sphere: ";

cin>>radius;

float diameter = 2*radius;

float circumference = diameter * 3.14;

float surface_area = 4*3.14*radius*radius;

float volume = (4/3)*3.14*radius*radius*radius;

cout<<"The diameter is: "<<diameter<<endl;

cout<<"The circumference is: "<<circumference<<endl;

cout<<"The surface area is: "<<surface_area<<endl;

cout<<"The volume is: "<<volume<<endl;

}

Explanation:

First include the library iostream for input/output in c++ programming.

then, create the main function and declare the variable radius as floating type.

Use cout to print the message on the screen.

Use cin to store the value in the variable.

After that, write the formula to calculate the values and store the results in the variables.

and finally print the result with message.

Computers and Technology

Write a program that takes the radius of a sphere (a floating-point number) as input and then outputs the sphere’s: diameter (2 × radius) circumference (diameter × π) surface area (4 × π × radius × radius) volume (4/3 × π × radius × radius × radius)

Step-by-step answer

P Answered by PhD

1

#include<iostream>

using namespace std;

int main(){

float radius;

cout<<"Enter the radius of the sphere: ";

cin>>radius;

float diameter = 2*radius;

float circumference = diameter * 3.14;

float surface_area = 4*3.14*radius*radius;

float volume = (4/3)*3.14*radius*radius*radius;

cout<<"The diameter is: "<<diameter<<endl;

cout<<"The circumference is: "<<circumference<<endl;

cout<<"The surface area is: "<<surface_area<<endl;

cout<<"The volume is: "<<volume<<endl;

}

Explanation:

First include the library iostream for input/output in c++ programming.

then, create the main function and declare the variable radius as floating type.

Use cout to print the message on the screen.

Use cin to store the value in the variable.

After that, write the formula to calculate the values and store the results in the variables.

and finally print the result with message.

Computers and Technology

Define a function drawCircle. This function should expect a Turtle object, the coordinates of the circle s center point, and the circle s radius as arguments.The function should draw the specified circle. The pen color should be changed to yellow before drawing a circle and the width of the pen to 5 pixels. The algorithm should draw the circle s circumference by turning 3 degrees and moving a given distance 120 times. Calculate the distance moved with the formula 2.0*n*radius/120.0. Fill in the circle with blue color. After drawing the circle,

Step-by-step answer

P Answered by Specialist

4

See Explaination

Explanation:

Function drawCircle

-Expect Turtle object, coordinates of the circle's center point and

circle's radius as arguments

-Function draws circle

-Draw circle's circumference by turning 3 degrees and moving a given

distance, 120 times.

-Calculate the distance moved with formula 2.0 * 3.14 * radius /120

"""

def drawCircle (turtle, centerpoint, radius):

circumference = 2 * 3.14 * (radius/120)

print "The circumference moved is", circumference

turtle.up()

(x,y) = centerpoint[-1]

turtle.turn(3)

turtle.move(120)

turtle.down()

from turtlegraphics import Turtle

turtle=Turtle()

drawCircle(turtle, [(20,20)], 20)

Mathematics

Find the diameter of each circle given the radius. radius=6cm radius=5cm radius=9cm radius=8cm radius-1.5cm radius=18cm radius=4cm

Step-by-step answer

P Answered by PhD

1

1. 12cm.

2. 10cm.

3. 18cm.

4. 16cm.

5. 3cm. (or -3 if your question was negative.)

6. 36cm.

7. 8cm.

Explanation:

To find the radius of a circle, simply divide the diameter by 2.

With this being said we can just add on top of the given radius.

Example:

The given radius is 5cm. What is 5cm + 5cm? 10cm.

Thus, getting our answer.

Mathematics

Find the diameter of each circle given the radius. radius=6cm radius=5cm radius=9cm radius=8cm radius-1.5cm radius=18cm radius=4cm

Step-by-step answer

P Answered by PhD

1

1. 12cm.

2. 10cm.

3. 18cm.

4. 16cm.

5. 3cm. (or -3 if your question was negative.)

6. 36cm.

7. 8cm.

Explanation:

To find the radius of a circle, simply divide the diameter by 2.

With this being said we can just add on top of the given radius.

Example:

The given radius is 5cm. What is 5cm + 5cm? 10cm.

Thus, getting our answer.

Computers and Technology

Define a function drawCircle. This function should expect a Turtle object, the coordinates of the circle s center point, and the circle s radius as arguments.The function should draw the specified circle. The pen color should be changed to yellow before drawing a circle and the width of the pen to 5 pixels. The algorithm should draw the circle s circumference by turning 3 degrees and moving a given distance 120 times. Calculate the distance moved with the formula 2.0*n*radius/120.0. Fill in the circle with blue color. After drawing the circle,

Step-by-step answer

P Answered by Specialist

4

See Explaination

Explanation:

Function drawCircle

-Expect Turtle object, coordinates of the circle's center point and

circle's radius as arguments

-Function draws circle

-Draw circle's circumference by turning 3 degrees and moving a given

distance, 120 times.

-Calculate the distance moved with formula 2.0 * 3.14 * radius /120

"""

def drawCircle (turtle, centerpoint, radius):

circumference = 2 * 3.14 * (radius/120)

print "The circumference moved is", circumference

turtle.up()

(x,y) = centerpoint[-1]

turtle.turn(3)

turtle.move(120)

turtle.down()

from turtlegraphics import Turtle

turtle=Turtle()

drawCircle(turtle, [(20,20)], 20)

Mathematics

Asprinkler that sprays water in a circular area can be adjusted to spray up to 30 feet. turning the radius-reduction screw on the top of the nozzle lets people the radius by up to 25 percent. to the nearest tenth, what is the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity.

Step-by-step answer

P Answered by PhD

25

1590.4 square feet

Step-by-step explanation:

Given: The radius of the circular area = 30 feet

Now, 25% of the radius = $0.25\times30=7.5$ feet

If the we reduce the radius by 25%, then the radius of the circular area =

$30-7.5=22.5\text{ feet}$

Now, the circular area of the spray is given by :-

$\text{Area}=\pi r^2\\\\\Rightarrow\text{ Area}=(3.143.141592653)(22.5)^2\\\\\Rightarrow\text{ Area}=1590.43128088\approx1590.4\text{ ft}^2$

Therefore, the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity = 1590.4 square feet.

Mathematics

Asprinkler that sprays water in a circular area can be adjusted to spray up to 30 feet. turning the radius-reduction screw on the top of the nozzle lets people the radius by up to 25 percent. to the nearest tenth, what is the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity.

Step-by-step answer

P Answered by PhD

25

1590.4 square feet

Step-by-step explanation:

Given: The radius of the circular area = 30 feet

Now, 25% of the radius = $0.25\times30=7.5$ feet

If the we reduce the radius by 25%, then the radius of the circular area =

$30-7.5=22.5\text{ feet}$

Now, the circular area of the spray is given by :-

$\text{Area}=\pi r^2\\\\\Rightarrow\text{ Area}=(3.143.141592653)(22.5)^2\\\\\Rightarrow\text{ Area}=1590.43128088\approx1590.4\text{ ft}^2$

Therefore, the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity = 1590.4 square feet.

What’s the radius of the pond ?

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