Mathematics : asked on skylarschumacher7

03.06.2021

The distance from point A (0.12,0.56) and point B (0.44,0.81) in decimals form

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Mathematics

Find the distance from point a(0.12, 0.56) to point b (0.44, 0.81)

Step-by-step answer

P Answered by Specialist

The distance bertween points (x1,y1) and (x2,y2) is
D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

we have
(0.12,0.56) to (0.44,0.81)

x1=0.12
y1=0.56
x2=0.44
y2=0.81

D= $\sqrt{(0.44-0.12)^2+(0.81-0.56)^2}$
D= $\sqrt{(0.32)^2+(0.0.25)^2}$
D= $\sqrt{0.1024+0.0625}$
D= $\sqrt{0.1649}$
aprox
D=0.40607881008

the distance is

D= $\sqrt{0.1649}$ or aprox
D=0.40607881008

Mathematics

Find the distance from point a(0.12, 0.56) to point b (0.44, 0.81)

Step-by-step answer

P Answered by Master

The distance bertween points (x1,y1) and (x2,y2) is
D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

we have
(0.12,0.56) to (0.44,0.81)

x1=0.12
y1=0.56
x2=0.44
y2=0.81

D= $\sqrt{(0.44-0.12)^2+(0.81-0.56)^2}$
D= $\sqrt{(0.32)^2+(0.0.25)^2}$
D= $\sqrt{0.1024+0.0625}$
D= $\sqrt{0.1649}$
aprox
D=0.40607881008

the distance is

D= $\sqrt{0.1649}$ or aprox
D=0.40607881008

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Step-by-step answer

P Answered by PhD

The answer is in the image

The answer is in the image

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The last time Robert filled up his car with gas, he paid $24.50 for 7 gallons. This time, he needs 15 gallons. If the price is the same, how much will he pay?

Step-by-step answer

P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

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Step-by-step answer

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The answer is in the image

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Step-by-step answer

P Answered by PhD

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

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The value of a collectible coin can be represented by the equation y = 2 x + 15, where x represents its age in years and y represents its total value in dollars. What is the value of the coin after 19 years? $2 $23 $38 $53

Step-by-step answer

P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

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Step-by-step answer

P Answered by PhD

The answer is in the image

The answer is in the image

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A 4300-N force from a car s engines produces an acceleration of 3.3 m/s2. What is the mass of the car? A. 4300 kg B. 1300 kg C. 14,000 kg D. 390 kg

Step-by-step answer

P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

=4300/3.3

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Approximately it is aqual to 1300kg

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Step-by-step answer

P Answered by PhD

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

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