Mathematics: what is the probability of the compact cars please help me

what is the probability of the compact cars please, №12749972, 30.08.2022 23:09

Mathematics

Acar rental agency has 9 midsized and 16 compact cars on its lot, from which 6 will be selected. assuming that each car is equally likely to be selected and the cars are selected at random, determine the probability that the cars selected consist of 3 midsized cars and 3 compact cars. what is the probability that the cars selected consist of 3 midsized cars and 3 compact cars?

Step-by-step answer

P Answered by PhD

9C6 / 25C6 = 84/177100

Step-by-step explanation:

Here 9 mid sized

16 compact cars

selected = 6

9C6 / 25C6 = 84/177100

for 3 mid sized

3 compact cars

then

3Cx/9Cx

divide by 3 we get

Cx/3Cxtaking Cx coomon

it become Cx =1/3 hence the probability is 1/3

Mathematics

Acar rental agency has 9 midsized and 16 compact cars on its lot, from which 6 will be selected. assuming that each car is equally likely to be selected and the cars are selected at random, determine the probability that the cars selected consist of 3 midsized cars and 3 compact cars. what is the probability that the cars selected consist of 3 midsized cars and 3 compact cars?

Step-by-step answer

P Answered by PhD

9C6 / 25C6 = 84/177100

Step-by-step explanation:

Here 9 mid sized

16 compact cars

selected = 6

9C6 / 25C6 = 84/177100

for 3 mid sized

3 compact cars

then

3Cx/9Cx

divide by 3 we get

Cx/3Cxtaking Cx coomon

it become Cx =1/3 hence the probability is 1/3

Mathematics

Alucky customer at used car charlie s lot will get to randomly select one key from a barrel of keys. the barrel contains the keys to all of the cars on charlie s lot. the inventory lists 80 cars, of which: 38 are foreign models 50 compact models 22 foreign compact models what is the probability that the lucky customer will win a nonforeign compact car?

Step-by-step answer

P Answered by PhD

0.625

Step-by-step explanation:

Given

A lucky customer will get to randomly select a key among 80 cars

There are 38 foreign models

50 compact models

22 Foreign compact models

Probability that the lucky customer will win a non foreign compact car $=\frac{no.\ of\ non\ foreign\ compact\ car}{Total\ no\ of\ car}$

$=\frac{50}{80}$

Mathematics

Alucky customer at used car charlie s lot will get to randomly select one key from a barrel of keys. the barrel contains the keys to all of the cars on charlie s lot. the inventory lists 80 cars, of which: 38 are foreign models 50 compact models 22 foreign compact models what is the probability that the lucky customer will win a nonforeign compact car?

Step-by-step answer

P Answered by PhD

0.625

Step-by-step explanation:

Given

A lucky customer will get to randomly select a key among 80 cars

There are 38 foreign models

50 compact models

22 Foreign compact models

Probability that the lucky customer will win a non foreign compact car $=\frac{no.\ of\ non\ foreign\ compact\ car}{Total\ no\ of\ car}$

$=\frac{50}{80}$

Mathematics

Before i close for the night. a simple probability problem. a car rental company has 18 compact cars and 12 midsize cars. if 4 cars are to be selected at random, what is the probability of getting 2 cars of each type?

Step-by-step answer

P Answered by Master

2

The probability of getting 2 of each type is:
$P(2\ of\ each\ type)=\frac{18C2\times12C2}{30C4}=0.3685$

Mathematics

Before i close for the night. a simple probability problem. a car rental company has 18 compact cars and 12 midsize cars. if 4 cars are to be selected at random, what is the probability of getting 2 cars of each type?

Step-by-step answer

P Answered by Specialist

2

The probability of getting 2 of each type is:
$P(2\ of\ each\ type)=\frac{18C2\times12C2}{30C4}=0.3685$

Mathematics

Car rental agency has 13 midsized and 18 compact cars on its lot, from which 6 will be selected. assuming that each car is equally likely to be selected and the cars are selected at random, determine the probability that the cars selected consist of all midsized cars.

Step-by-step answer

P Answered by Master

The probability of selecting 6 cars which are midsized cars is 0.0046

Step-by-step explanation:

We have given that car rental agency has 13 midsized car

So number of midsized car = 13

Number of compact cars = 18

So total number of car = 13+18 = 31

We have to select 6 cars

And we have to find the probability that all selected car will midsized car

Probability is given by $=\frac{^{13}C_{6}}{^{31}C_6}=0.0046$

So the probability of selecting 6 cars which are midsized cars is 0.0046

Mathematics

Car rental agency has 13 midsized and 18 compact cars on its lot, from which 6 will be selected. assuming that each car is equally likely to be selected and the cars are selected at random, determine the probability that the cars selected consist of all midsized cars.

Step-by-step answer

P Answered by Specialist

The probability of selecting 6 cars which are midsized cars is 0.0046

Step-by-step explanation:

We have given that car rental agency has 13 midsized car

So number of midsized car = 13

Number of compact cars = 18

So total number of car = 13+18 = 31

We have to select 6 cars

And we have to find the probability that all selected car will midsized car

Probability is given by $=\frac{^{13}C_{6}}{^{31}C_6}=0.0046$

So the probability of selecting 6 cars which are midsized cars is 0.0046

Mathematics

Fuel economy of compact cars is normally distributed with a mean of 32.2 milesper gallon and a standard deviation of 3.7 miles per gallon. The probability that arandomly selected compact car gets at least 40 miles per gallon is about?

Step-by-step answer

P Answered by PhD

The probability that a randomly selected compact car gets at least 40 miles per gallon is about 1.74%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 32.2, \sigma = 3.7$

The probability that a randomly selected compact car gets at least 40 miles per gallon is about?

This is 1 subtracted by the pvalue of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40 - 32.2}{3.7}$

Z = 2.11

Z = 2.11 has a pvalue of 0.9826

1 - 0.9826 = 0.0174

The probability that a randomly selected compact car gets at least 40 miles per gallon is about 1.74%

Mathematics

Fuel economy of compact cars is normally distributed with a mean of 32.2 milesper gallon and a standard deviation of 3.7 miles per gallon. The probability that arandomly selected compact car gets at least 40 miles per gallon is about?

Step-by-step answer

P Answered by PhD

The probability that a randomly selected compact car gets at least 40 miles per gallon is about 1.74%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 32.2, \sigma = 3.7$

The probability that a randomly selected compact car gets at least 40 miles per gallon is about?

This is 1 subtracted by the pvalue of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40 - 32.2}{3.7}$

Z = 2.11

Z = 2.11 has a pvalue of 0.9826

1 - 0.9826 = 0.0174

The probability that a randomly selected compact car gets at least 40 miles per gallon is about 1.74%

what is the probability of the compact cars please help me

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