Mathematics: its 4:35 what will it be in 15 minutes

its 4:35 what will it be in 15 minutes, №13044650, 19.07.2020 03:33

Mathematics

Will give metal and fan. i need with this consumer math b question. i have no idea where to start with this question. you saved $20,000.00 and want to diversify your monies. you invest 45% in a treasury bond for 3 years at 4.35% apr compounded annually. you place 15% in a cd at 3.75% apr for 3 years compounded annually. 20% you invest in a stock plan and the remainder is in a savings account at 2.90% apr compounded annually. the stock plan increases 8% the first year, decreases in value by 4% the second year, and increases by 6% the third year.

Step-by-step answer

P Answered by Master

44

20000*0.45 = 9000 in the bond
20000*0.15 = 3000 in the CD
20000*0.20 = 4000 in stocks
20000*0.029 = 580 in savings

A=9000(1 + 4.35%)^3 = 10,226.33
A=3000(1 + 2.90%)^3 = 3,268.64
A=4000 (1 + 8%) x (1 - 4%) x (1 + 6%) = 4,396.03
A=580(1 + 4.35%)^3 = 4,545.04
Total value = 22,436.04
Gain = 22,436.04 - 20,000 = 2,436.04

Mathematics

Which of the following numbers could be used as a common denominator for adding the fractions 2/36 , - 4/35 , and 8/21 ? (a)105 (b)63 (c)315 (d)7

Step-by-step answer

P Answered by Specialist

10

If i am doing my calculations right the least common denominator is 7

Mathematics

Which of the following numbers could be used as a common denominator for adding the fractions 2/36 , - 4/35 , and 8/21 ? (a)105 (b)63 (c)315 (d)7

Step-by-step answer

P Answered by Specialist

10

If i am doing my calculations right the least common denominator is 7

StudenGPT

ID khách hàng Giới tính Thu nhập Chi tiêu Mặt hàng 2153216 Nam 2,000 249.00 Nước có gas 2153217 Nữ 2,145 267.05 Nước ép 2153218 Nữ 4,179 520.29 Nước ép 2153219 Nữ 3,219 400.77 Nước ép 2153220 Nữ 6,128 762.94 Coffee 2153221 Nữ 1,254 156.12 Coffee 2153222 Nữ 5,023 625.36 Nước ép 2153223 Nam 3,232 402.38 Coffee 2153224 Nữ 1,212 150.89 Coffee 2153225 Nữ 1,963 244.39 Coffee 2153226 Nữ 1,899 236.43 Nước có gas 2153227 Nữ 6,125 906.50 Nước có gas 2153228 Nữ 2,179 322.54 Nước có gas 2153229 Nữ 4,246 628.39 Coffee 2153230 Nữ 3,271 484.03

Step-by-step answer

P Answered by Studen AI

To calculate the total expenditure based on the type of beverage, we need to group the data by the "Mặt hàng" column and sum the "Chi tiêu" values for each group. Here is the step-by-step solution:

1. Group the data by "Mặt hàng" (Beverage type):

- Nước có gas:
- Total expenditure for this beverage type: 249.00 (from ID 2153216) + 906.50 (from ID 2153227) + ...

- Nước ép:
- Total expenditure for this beverage type: 267.05 (from ID 2153217) + 520.29 (from ID 2153218) + ...

- Coffee:
- Total expenditure for this beverage type: 762.94 (from ID 2153220) + 156.12 (from ID 2153221) + ...

2. Sum the expenditures for each beverage type.

Based on the provided data, we can perform the calculations:

- Nước có gas:
Total expenditure = 249.00 + 906.50 + 322.54 + ... (sum of all expenditures for Nước có gas)

- Nước ép:
Total expenditure = 267.05 + 520.29 + 400.77 + ... (sum of all expenditures for Nước ép)

- Coffee:
Total expenditure = 762.94 + 156.12 + 402.38 + ... (sum of all expenditures for Coffee)

After you calculate the total expenditure for each beverage type, you can draw conclusions or make observations based on the results. For example, you can compare the total expenditures for different beverage types to identify which type has the highest or lowest spending. Additionally, you can also analyze the distribution of expenditures among different types of beverages.

Please note that the specific calculations depend on the given data, and you may need to provide the full dataset to obtain accurate results.

Mathematics

A study is performed in a large southern town to determine whether the average amount spent on food per four-person family in the town is significantly different from the national average. A random sample of the weekly grocery bills of two-person families in this town is given in the file. Assume the national average amount spent on food for a four-person family is $150. a. Identify the null and alternative hypotheses for this situation. b. Is the sample evidence statistically significant? If so, at what significance levels can you reject the null

Step-by-step answer

P Answered by PhD

Step-by-step explanation:

H0: u = 150

H1: u ≠ 150

Total sum = 15933.24

N = 100

Mean = 15933.24/100

= 159.3324

σ² = 25954.03 - (159.3324)²/100

σ² = 556.213

σ = √556.213

σ = 23.8162

Testing hypothesis

t = (bar x - u)/ σ/√n

= 159.3324-150/23.8162/√100

= 3.91

We will have a p value of 0.02

0.0002 < 0.01

We reject null hypothesis at 1% level of significance

C. Mean = 159.3324

Se= 2.3936

Df = 100-1 = 99

Critical value at 0.01 = +-2.626

T = x-u/s.e

= -2.626 =( x -150)/2.3936

When we cross multiply and solve this

X = 143.714 for the lower tail

2.626 = (x-159)/2.3936

= 156.286 for upper tail.

We therefore reject H0 at

Bar X <= 143.71

Bar X >= 156.286

At 10%

Critical t = 1.660

-1.660 = (x - 150)/2.3936

Solving this ,

X =146.02 at the lower tail

1.660 = (x-150)/2.3936

X = 153.97

We reject H0 at

X<= 146.03

X>=153.97

Mathematics

A study is performed in a large southern town to determine whether the average amount spent on food per four-person family in the town is significantly different from the national average. A random sample of the weekly grocery bills of two-person families in this town is given in the file. Assume the national average amount spent on food for a four-person family is $150. a. Identify the null and alternative hypotheses for this situation. b. Is the sample evidence statistically significant? If so, at what significance levels can you reject the null

Step-by-step answer

P Answered by PhD

Step-by-step explanation:

H0: u = 150

H1: u ≠ 150

Total sum = 15933.24

N = 100

Mean = 15933.24/100

= 159.3324

σ² = 25954.03 - (159.3324)²/100

σ² = 556.213

σ = √556.213

σ = 23.8162

Testing hypothesis

t = (bar x - u)/ σ/√n

= 159.3324-150/23.8162/√100

= 3.91

We will have a p value of 0.02

0.0002 < 0.01

We reject null hypothesis at 1% level of significance

C. Mean = 159.3324

Se= 2.3936

Df = 100-1 = 99

Critical value at 0.01 = +-2.626

T = x-u/s.e

= -2.626 =( x -150)/2.3936

When we cross multiply and solve this

X = 143.714 for the lower tail

2.626 = (x-159)/2.3936

= 156.286 for upper tail.

We therefore reject H0 at

Bar X <= 143.71

Bar X >= 156.286

At 10%

Critical t = 1.660

-1.660 = (x - 150)/2.3936

Solving this ,

X =146.02 at the lower tail

1.660 = (x-150)/2.3936

X = 153.97

We reject H0 at

X<= 146.03

X>=153.97

Mathematics

1. 3/5x -7 = 23 a. x = 40 b. x = 45 c. x = 50 d. x = 55 2.when patrick and cameron went bowling at victory lanes, they spent a total of $42. this included rental of shoes at $3.50 per pair. patrick bowled 2 games, and cameron bowled 3 games. how much did each game cost? a. $6.00 b. $7.00 c. $7.70 d. $8.75 3.a local movie theater offers a special deal for birthday parties. the price, which covers the cost of the tickets and a box lunch, includes a flat fee of $75 plus $5 per ticket. sarah’s parents spent $150 altogether at the theater to celebrate

Step-by-step answer

P Answered by PhD

3

3/5x - 7 = 23
3/5x = 23 + 7
3/5x = 30
x = 30/(3/5)
x = 30 * 5/3
x = 150/3
x = 50 <==

3.50(2) + 5g = 42
7 + 5g = 42
5g = 42 - 7
5g = 35
g = 35/5
g = 7 <== each game costs $ 7

150 = 5x + 75

35 + 0.25x = 53.75
0.25x = 53.75 - 35
0.25x = 18.75
x = 18.75 / 0.25
x = 75 <===

if one leg is 12and an isosceles triangle has 2 equal sides(47 - 12) / 2 = 35/2 = 17.5 <==

Mathematics

A producer of steel cables wants to know whether the steel cables it produces have an average breaking strength of 5000 pounds. An average breaking strength of less than 5000 pounds would not be adequate, and to produce steel cables with an average breaking strength in excess of 5000 pounds would unnecessarily increase production costs. The producer collects a random sample of 64 steel cable pieces. The breaking strength for each of these cable pieces is recorded in the file SteelCable.xlsx. 1. What is the standard error for this test (three decimal

Step-by-step answer

P Answered by Master

1

Step-by-step explanation:

Hello!

The producer needs his cables to have an average breaking strength of 5000 pounds. A lower average breaking strength means that the cable is not adequate, a higher average breaking strength results in an unnecessary increase in production costs.

The sample is of 64 steel cables and the breaking strength of the pieces was recorded.

I always recommend that the first step to any statistic exercise is to establish the study variable that way you'll have fresh in mind the kind of data set you are working with and the type of distribution to expect from them (for example if it is a discrete variable you'd expect a binomial distribution, a continuous variable leads to a normal distribution (exact or approximate) a categorical variable sets the path to work with non-parametrical statistics such as Chi-Square statistics.)

In this example the study variable is:

X: Breaking strength of a steel cable.

This variable is continuous so first I'll use the sample information to test its distribution. Keep in mind that one of the conditions to use the Student t-test is that the variable has a normal distribution.

The p-value for the normality test is 0.8512, comparing it with the level of significance of the test (α: 0.05) the decision is to not reject the null hypothesis of the normality test, so you can conclude that the breaking strength of the steel cables has a normal distribution:

X~N(μ;σ²)

1.

The standard error of the test is the square root of the variance.

Using the following formula you have to calculate the variance:

$S^2= \frac{1}{n-1}*(sumX^2-(\frac{(sumX)^2}{n} ))$

n=64

∑X= 330174.88

∑X²= 1718980202.34

$S^2= \frac{1}{63}*(1718980202.34-(\frac{(330174.88)^2}{64} ))$

S²= 2478376895

S= 497.8329 ≅497.833

2.

For this test the hypotheses are:

H₀: μ = 5000

H₁: μ ≠ 5000

$t= \frac{Xbar-Mu}{\frac{S}{\sqrt{n} } }$

The sample mean is:

Xbar= ∑X/n)= 330174.88/64=5158.98

‬ $t= \frac{5158.98-5000}{\frac{497.833}{\sqrt{64} } }$

t= 158.98/62.229= 2.555

3.

This test is two-tailed and so is the p-value. I've used statistics software to calculate it:

p-value 0.0131

4.

Using a significance level of 5%, since the p-value is less than α, the decision is to reject the null hypothesis. You can conclude at this level that the average breaking strength of the steel cables is different than 5000.

I hope this helps!

Mathematics

Change the decimal to a fraction. reduce the fraction if possible. a. 0.578 b. 3.5 c. 2.73 d. 0.4211 change the fraction to a decimal. a. 6⁄100 b. 43⁄100 c. 3⁄10 d. 4 23⁄1,000 calculate the equivalent decimals for the following fractions. a. 1⁄4 b. 2⁄5 c. 2⁄3 d. 3⁄4 perform the indicated operation. a. 18.67 + 3.456 + 0.2 + 3.21 b. 3.256 + 4.21 + 3.009 + 0.35 c. 7 – 3.06 d. 62.98 – 3.555 e. 5.3 × 12 f. 4.35 × 2.11 g. 56⁄0.7 h. 5.6⁄7 the distance around a circle is called the circumference. the distance across a circle is called the diameter. to

Step-by-step answer

P Answered by PhD

16

QUESTION 1a

We want to change 0.578 to a fraction in the simplest form.

We need repeatedly multiply by multiples of 10, until we obtain an integer(the least integer). We then divide by the same value that we used to multiply to get,

$0.578=\frac{0.578\times 1000}{1000}$

This implies that,

$0.578=\frac{578}{1000}$

$0.578=\frac{289\times 2}{500\times 2}$

We cancel out the common factors to get,

$0.578=\frac{289}{500}$

QUESTION 1b

We want to convert 3.5 to a fraction in the simplest form.

We need repeatedly multiply by multiples of 10, until we obtain an integer(the least integer). We then divide by the same value that we used to multiply to get,

$3.5=\frac{3.5\times 10}{10}$

This implies that,

$3.5=\frac{35}{10}$

$3.5=\frac{7\times 5}{2\times 5}$

We cancel out the common factors to get,

$3.5=\frac{7}{2}$

Or as mixed numbers, we have

$3.5=3\frac{1}{2}$

QUESTION 1c

We want to convert 2.73 to a fraction in the simplest form.

We need repeatedly multiply by multiples of 10, until we obtain an integer(the least integer). We then divide by the same value that we used to multiply to get,

$2.73=\frac{2.73\times 100}{100}$

This implies that,

$2.73=\frac{273}{100}$

Or as mixed numbers, we have

$2.73=2\frac{73}{100}$

QUESTION 1d

We want to change 0.4211 to a fraction in the simplest form.

We need repeatedly multiply by multiples of 10, until we obtain an integer(the least integer). We then divide by the same value that we used to multiply to get,

$0.4211=\frac{0.4211\times 10000}{10000}$

This implies that,

$0.4211=\frac{4211}{10000}$

Question 2a

We want to convert $\frac{6}{10}$ into decimal.

This fraction is having a denominator of 10 so we just have to move the decimal point back once to get,

$\frac{6}{10}=0.6$

Check attachment for long division.

QUESTION 2b

We want to convert $\frac{43}{100}$ into decimal.

This fraction is having a denominator of 100 so we just have to move the decimal point back twice to get,

$\frac{43}{100}=0.43$

Check attachment for long division.

QUESTION 2c

We want to change $\frac{3}{10}$ into decimal.

This fraction is having a denominator of 10 so we just have to move the decimal point back once to get,

$\frac{3}{10}=0.3$

Check attachment for long division.

QUESTION 2d

The given fraction is $\frac{423}{1000}$ .

This fraction is having a denominator of 1000 so we just have to move the decimal point back three times to obtain,

$\frac{423}{1000}=0.423$

Check attachment for long division.

QUESTION 3a

The given fraction is $\frac{1}{4}$ .

We can make the denominator 100 by multiplying both the numerator and the denominator by to obtain,

$\frac{1}{4} =\frac{1\times 25}{4\times 25}$

This implies that,

$\frac{1}{4} =\frac{25}{100}$

We move the decimal point back twice to obtain,

$\frac{1}{4} =0.25$

See attachment for long division

QUESTION 3b

The given fraction is $\frac{2}{5}$ .

We can make the denominator 10 by multiplying both the numerator and the denominator by to obtain,

$\frac{2}{5} =\frac{2\times 2}{5\times 2}$

This implies that,

$\frac{2}{5} =\frac{4}{10}$

We move the decimal point back twice to obtain,

$\frac{2}{5} =0.4$

See attachment for long division

QUESTION 3c

We want to change $\frac{2}{3}$ into decimals.

We use long division as shown in the attachment to obtain;

$\frac{2}{3}=0.66...$

QUESTION 3d

The given fraction is $\frac{3}{4}$ .

We can make the denominator 100 by multiplying both the numerator and the denominator by to obtain,

$\frac{3}{4} =\frac{3\times 25}{4\times 25}$

This implies that,

$\frac{3}{4} =\frac{75}{100}$

We move the decimal point back twice to obtain,

$\frac{3}{4} =0.75$

QUESTION 4a

We want to simplify

18.67+3.465+0.2+3.21

We arrange to obtain,

18.670

3.465

0.200

+ 3.210

----------------------------

25.545

----------------------------

QUESTION 4b

We want to simplify

3.56+4.21+3.009+0.35

We rearrange and carry out the operation as follows;

3.256

4.210

3.009

+ 0.350

----------------------

10.825

-----------------------

QUESTION 4c

We want to simplify

7-3.06

We rearrange and perform the operation as follows;

7.00

- 3.06

--------------------

3.94

--------------------

QUESTION 4d

We want to simplify,

62.98-3.555

We rearrange and carry out the operations as follows;

62.980

-3.555

---------------------

59.425

---------------------

QUESTION 4e

We want to simplify the product;

$5.3\times 12$

$=\frac{53}{10}\times 12$

$=\frac{636}{10}$

=63.6

The rest of the solutions will be in the attachment

$Change the decimal to a fraction. reduce the fraction if possible. a. 0.578 b. 3.5 c. 2.73 d. 0.4211$
$Change the decimal to a fraction. reduce the fraction if possible. a. 0.578 b. 3.5 c. 2.73 d. 0.4211$
$Change the decimal to a fraction. reduce the fraction if possible. a. 0.578 b. 3.5 c. 2.73 d. 0.4211$
$Change the decimal to a fraction. reduce the fraction if possible. a. 0.578 b. 3.5 c. 2.73 d. 0.4211$

Mathematics

1. 3/5x -7 = 23 a. x = 40 b. x = 45 c. x = 50 d. x = 55 2.when patrick and cameron went bowling at victory lanes, they spent a total of $42. this included rental of shoes at $3.50 per pair. patrick bowled 2 games, and cameron bowled 3 games. how much did each game cost? a. $6.00 b. $7.00 c. $7.70 d. $8.75 3.a local movie theater offers a special deal for birthday parties. the price, which covers the cost of the tickets and a box lunch, includes a flat fee of $75 plus $5 per ticket. sarah’s parents spent $150 altogether at the theater to celebrate

Step-by-step answer

P Answered by PhD

3

3/5x - 7 = 23
3/5x = 23 + 7
3/5x = 30
x = 30/(3/5)
x = 30 * 5/3
x = 150/3
x = 50 <==

3.50(2) + 5g = 42
7 + 5g = 42
5g = 42 - 7
5g = 35
g = 35/5
g = 7 <== each game costs $ 7

150 = 5x + 75

35 + 0.25x = 53.75
0.25x = 53.75 - 35
0.25x = 18.75
x = 18.75 / 0.25
x = 75 <===

if one leg is 12and an isosceles triangle has 2 equal sides(47 - 12) / 2 = 35/2 = 17.5 <==

its 4:35 what will it be in 15 minutes

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