Mathematics : asked on amoore51
 15.06.2022

In a given problem ,x= number of springs manufactured during a given day why would x>0 be a valid constraint

. 5

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Physics
Step-by-step answer
P Answered by PhD

a) E = \frac{1}{2} \cdot k \cdot x^{2} + \frac{1}{2}  \cdot m \cdot v^{2}, b) Amplitude of the motion is A = \sqrt{\frac{2\cdot E}{k} }, c) The maximum speed attained by the object during its motion is v_{max} = \sqrt{\frac{2\cdot E}{m} }.

Explanation:

a) The total energy of the object is equal to the sum of potential and kinetic energies. That is:

E = K + U

Where:

K - Kinetic energy, dimensionless.

U - Potential energy, dimensionless.

After replacing each term, the total energy of the object at any point in its motion is:

E = \frac{1}{2} \cdot k \cdot x^{2} + \frac{1}{2}  \cdot m \cdot v^{2}

b) The amplitude of the motion occurs when total energy is equal to potential energy, that is, when objects reaches maximum or minimum position with respect to position of equilibrium. That is:

E = U

E = \frac{1}{2} \cdot k \cdot A^{2}

Amplitude is finally cleared:

A = \sqrt{\frac{2\cdot E}{k} }

Amplitude of the motion is A = \sqrt{\frac{2\cdot E}{k} }.

c) The maximum speed of the motion when total energy is equal to kinetic energy. That is to say:

E = K

E = \frac{1}{2}\cdot m \cdot v_{max}^{2}

Maximum speed is now cleared:

v_{max} = \sqrt{\frac{2\cdot E}{m} }

The maximum speed attained by the object during its motion is v_{max} = \sqrt{\frac{2\cdot E}{m} }.

Physics
Step-by-step answer
P Answered by PhD

a) E = \frac{1}{2} \cdot k \cdot x^{2} + \frac{1}{2}  \cdot m \cdot v^{2}, b) Amplitude of the motion is A = \sqrt{\frac{2\cdot E}{k} }, c) The maximum speed attained by the object during its motion is v_{max} = \sqrt{\frac{2\cdot E}{m} }.

Explanation:

a) The total energy of the object is equal to the sum of potential and kinetic energies. That is:

E = K + U

Where:

K - Kinetic energy, dimensionless.

U - Potential energy, dimensionless.

After replacing each term, the total energy of the object at any point in its motion is:

E = \frac{1}{2} \cdot k \cdot x^{2} + \frac{1}{2}  \cdot m \cdot v^{2}

b) The amplitude of the motion occurs when total energy is equal to potential energy, that is, when objects reaches maximum or minimum position with respect to position of equilibrium. That is:

E = U

E = \frac{1}{2} \cdot k \cdot A^{2}

Amplitude is finally cleared:

A = \sqrt{\frac{2\cdot E}{k} }

Amplitude of the motion is A = \sqrt{\frac{2\cdot E}{k} }.

c) The maximum speed of the motion when total energy is equal to kinetic energy. That is to say:

E = K

E = \frac{1}{2}\cdot m \cdot v_{max}^{2}

Maximum speed is now cleared:

v_{max} = \sqrt{\frac{2\cdot E}{m} }

The maximum speed attained by the object during its motion is v_{max} = \sqrt{\frac{2\cdot E}{m} }.

Physics
Step-by-step answer
P Answered by PhD

A) E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2

Explanation:

The total energy of the system at any point in the motion is equal to the sum of the elastic potential energy of the spring, U, and of the kinetic energy of the mass, K:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2

where

k is the spring constant

x is the compression/stretching of the spring with respect to its equilibrium position

m is the mass of the block attached to the spring

v is the speed of the block

B) A=\sqrt{\frac{2E}{k}}

Explanation:

The amplitude of the motion corresponds to the maximum displacement of the mass-spring system. The displacement of the system, x(t), at time t, for a simple harmonic oscillator is given by

x=A sin(\omega t + \phi)

where

A is the amplitude

\omega=\sqrt{\frac{k}{m}} is the angular frequency of the motion

t is the time

\phi is the phase (we can take \phi=0 for simplicity)

The amplitude of the motion occurs when the displacement of the motion is maximum: x=A. In terms of energy, the mass-spring system is at its maximum displacement (x=A) when all the mechanical energy of the system is elastic potential energy, so when the kinetic energy is zero:

K=\frac{1}{2}mv^2=0

E=\frac{1}{2}kA^2\\A=\sqrt{\frac{2E}{k}} (1)

C) v_{max}=\omega A

The maximum speed of the system occurs when the elastic potential energy is zero: U=0 and the kinetic energy is maximum, so:

U=0\\E=\frac{1}{2}mv_{max}^2

Due to the law of conservation of the mechanical energy, this energy must be equal to the energy of the system at its maximum displacement (1), so we can write

\frac{1}{2}kA^2=\frac{1}{2}mv_{max}^2

and solving for v_{max} we find an expression for the maximum speed:

v_{max}=\sqrt{\frac{kA^2}{m}}=\sqrt{\frac{k}{m}}A=\omega A

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

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