(1/3,-7); x=1/3; translated to the right 1/3 unit and down 7 units
Step-by-step explanation:
The parent function is:
g(x) = IxI
And we have:
f(x) = I6x - 2I - 7
We canr rewrite f to get:
f(x) = 6*Ix - 1/3I - 7
Then, now let's define some transformations:
If we start with g(x), a translation of N units to the right is:
f(x) = g(x - N)
if we start with g(x), a translation of N units up is:
f(x) = g(x) + N
A translation down would be:
f(x) = g(x) - N
And a vertical dilation of scale factor A is written as:
f(x) = A*g(x)
Then in this case we have:
A translation to the right of 1/3 units.
A dilation of scale factor 6.
A translation down of 7 units.
And the axis of symmetry will be when the absolute value part is equal to zero, or when
6*Ix - 1/3I = 0
And that is when x = 1/3.
Then the correct option is:
(1/3,-7); x=1/3; translated to the right 1/3 unit and down 7 units
(1/3,-7); x=1/3; translated to the right 1/3 unit and down 7 units
Step-by-step explanation:
The parent function is:
g(x) = IxI
And we have:
f(x) = I6x - 2I - 7
We canr rewrite f to get:
f(x) = 6*Ix - 1/3I - 7
Then, now let's define some transformations:
If we start with g(x), a translation of N units to the right is:
f(x) = g(x - N)
if we start with g(x), a translation of N units up is:
f(x) = g(x) + N
A translation down would be:
f(x) = g(x) - N
And a vertical dilation of scale factor A is written as:
f(x) = A*g(x)
Then in this case we have:
A translation to the right of 1/3 units.
A dilation of scale factor 6.
A translation down of 7 units.
And the axis of symmetry will be when the absolute value part is equal to zero, or when
6*Ix - 1/3I = 0
And that is when x = 1/3.
Then the correct option is:
(1/3,-7); x=1/3; translated to the right 1/3 unit and down 7 units
f(x) = x^2 -3
Step-by-step explanation:
A function is translated down 3 units by subtracting 3 from the function value. For the parent function f(x) = x^2, the translated function is ...
f(x) = x^2 -3
Comment on vertex form
The full "vertex form" has the values of the vertex coordinates in the equation explicitly. For vertex (h, k), the form is ...
f(x) = a(x -h)^2 +k
We have moved the vertex from (0, 0) to (0, -3). The vertical scale factor (a) remains 1. So, we could write the equation as ...
f(x) = 1(x -0)^2 -3 . . . . vertex form with unnecessary parts shown
Removing the identity elements doesn't change anything (though it requires a little practice to see them when they aren't there). So, with minor simplification, this becomes ...
f(x) = x^2 -3
Since the function is vertically compressed by a factor of 0.5 then the function is transformed in
Now, is translated 1 unit right, obtaining the function
Then, is translated 3 units down, obtaining the function
that is in vertex form and the vertex of is the point
Since the function is vertically compressed by a factor of 0.5 then the function is transformed in
Now, is translated 1 unit right, obtaining the function
Then, is translated 3 units down, obtaining the function
that is in vertex form and the vertex of is the point
SI=(P*R*T)/100
P=2000
R=1.5
T=6
SI=(2000*1.5*6)/100
=(2000*9)/100
=180
Neil will earn interest of 180
Cost of 7 gallons=$24.50
Cost of 1 gallon=24.50/7=3.5
Cost of 15 gallons=15*3.5=52.5
Cost of 15 gallons will be $52.5
It will provide an instant answer!