Mathematics: Find the radius of the smaller section formed by

Find the radius of the smaller section formed, №13451368, 23.01.2021 05:55

Mathematics

For the diagram, calculate; the radius of the smaller section and the perimeter of the shape of the and;

Step-by-step answer

P Answered by PhD

1

a). Radius r of the small sector= 12cm

b). Perimeter of the shape= 68 cm

c). Angle= 47.7°

Step-by-step explanation:

a). Radius of the big sector= 24 cm

Arc if the big sector= 20 cm

Arc of the small sector= 10 cm

For the radius r of the small sector

r/10 = 24/20

r=(10*24)/20

r= 24/2

r= 12 cm

Radius r of the small sector= 12cm

b). Perimeter of the shape

= Total length of the shape

Let's note that the other side of the sector is also the radius= 24 cm

Perimeter= 20+24+24

Perimeter of the shape= 68 cm

c) the angle

Length of arc = 2πr*(angle/360)

Let angle = b

Length of arc = 20cm

20= 2*3.14*24*(b/360)

(20*360)/(2*3.14*24)= b

47.7°= b

Angle= 47.7°

Mathematics

For the diagram, calculate; the radius of the smaller section and the perimeter of the shape of the and;

Step-by-step answer

P Answered by PhD

1

a). Radius r of the small sector= 12cm

b). Perimeter of the shape= 68 cm

c). Angle= 47.7°

Step-by-step explanation:

a). Radius of the big sector= 24 cm

Arc if the big sector= 20 cm

Arc of the small sector= 10 cm

For the radius r of the small sector

r/10 = 24/20

r=(10*24)/20

r= 24/2

r= 12 cm

Radius r of the small sector= 12cm

b). Perimeter of the shape

= Total length of the shape

Let's note that the other side of the sector is also the radius= 24 cm

Perimeter= 20+24+24

Perimeter of the shape= 68 cm

c) the angle

Length of arc = 2πr*(angle/360)

Let angle = b

Length of arc = 20cm

20= 2*3.14*24*(b/360)

(20*360)/(2*3.14*24)= b

47.7°= b

Angle= 47.7°

Mathematics

Describe a circular cross-section of a sphere that does not pass through the center. Select All that apply The radius will be equal to the radius of the sphere The radius will be larger than the radius of the sphere The radius will be smaller than the radius of the sphere The area of the circular cross-section will be 2piR squared The sphere will be divided into 2 equal sections The volume of the 2pieces of the sphere will not be the same

Step-by-step answer

P Answered by PhD

9

The radius will be smaller than the radius of the sphere

The volume of the 2 pieces of the sphere will not be the same

Step-by-step explanation:

A sphere is a three-dimensional geometrical figure. It is a set of all points equidistant from a fixed point in space.

A circle is a two-dimensional figure. It is the locus of all points equidistant from a central point.

For a circular cross-section of a sphere that does not pass through the center,

the radius will be smaller than the radius of the sphere, the volume of the 2 pieces of the sphere will not be the same

Mathematics

Describe a circular cross-section of a sphere that does not pass through the center. Select All that apply The radius will be equal to the radius of the sphere The radius will be larger than the radius of the sphere The radius will be smaller than the radius of the sphere The area of the circular cross-section will be 2piR squared The sphere will be divided into 2 equal sections The volume of the 2pieces of the sphere will not be the same

Step-by-step answer

P Answered by PhD

9

The radius will be smaller than the radius of the sphere

The volume of the 2 pieces of the sphere will not be the same

Step-by-step explanation:

A sphere is a three-dimensional geometrical figure. It is a set of all points equidistant from a fixed point in space.

A circle is a two-dimensional figure. It is the locus of all points equidistant from a central point.

For a circular cross-section of a sphere that does not pass through the center,

the radius will be smaller than the radius of the sphere, the volume of the 2 pieces of the sphere will not be the same

Engineering

Calculate the fatigue stress concentration for a steel filleted shaft that is loaded in bending. given data: sut = 440 mpa d (for larger cross-section) = 64 mm d (for smaller cross-section) = 32 mm r(fillet radius) = 4 mm

Step-by-step answer

P Answered by PhD

K_f = 1.422

Explanation:

We know that relationship between fatigue and stress concentration factor

K_f = 1+q(K_t-1)

Where

K_f =fatigue concentration factor

K_t =stress concentration factor

q=Notch sensitivity

Here D/d=2 and r/d=0.125

Now from standard design data book K_t=1.79

For Sut=440 MPa and r= 4 mm

q=0.8

Now by putting the values

K_f = 1+q(K_t-1)

K_f = 1.8(1.79-1)

K_f = 1.422

Engineering

Calculate the fatigue stress concentration for a steel filleted shaft that is loaded in bending. given data: sut = 440 mpa d (for larger cross-section) = 64 mm d (for smaller cross-section) = 32 mm r(fillet radius) = 4 mm

Step-by-step answer

P Answered by PhD

K_f = 1.422

Explanation:

We know that relationship between fatigue and stress concentration factor

K_f = 1+q(K_t-1)

Where

K_f =fatigue concentration factor

K_t =stress concentration factor

q=Notch sensitivity

Here D/d=2 and r/d=0.125

Now from standard design data book K_t=1.79

For Sut=440 MPa and r= 4 mm

q=0.8

Now by putting the values

K_f = 1+q(K_t-1)

K_f = 1.8(1.79-1)

K_f = 1.422

Mathematics

Suppose a tank leaks toxic chemical. The area affected is a circle centered on the tank. When the spill is first noticed, the circle has a radius of 5000 feet. A response team arrives 30 minutes later, by which time the affected area has grown to a circle with a radius of 5050 feet. How rapidly was the radius of the spill changing between the time the spill was noticed and the arrival of the response team? How rapidly was the area of the spill changing between the time the spill was noticed and the arrival of the response team? The response team

Step-by-step answer

P Answered by Master

Step-by-step explanation:

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Mathematics

Suppose a tank leaks toxic chemical. The area affected is a circle centered on the tank. When the spill is first noticed, the circle has a radius of 5000 feet. A response team arrives 30 minutes later, by which time the affected area has grown to a circle with a radius of 5050 feet. How rapidly was the radius of the spill changing between the time the spill was noticed and the arrival of the response team? How rapidly was the area of the spill changing between the time the spill was noticed and the arrival of the response team? The response team

Step-by-step answer

P Answered by Specialist

Step-by-step explanation:

did u know fifteen minutes could save you fifteen percent or more on car insurance.

Mathematics

SIX PART QUESTION! SEEKING A DETAILED ANSWER! WILL GIVE BRAINLIEST! 8.06 Activity A theme park company is opening a marine-inspired park in your city. They are in the process of designing the theatre where a killer whale show will take place. The following design is already under construction and will house the whales that perform in the show: (Please view the image attached). Main Show Tank Calculation: 1. The main tank has a radius of 70 feet. What is the volume of the quarter-sphere sized tank? Round your answer to the nearest whole number.

Step-by-step answer

P Answered by Specialist

see the attached pictures

Step-by-step explanation:

SIX PART QUESTION! SEEKING A DETAILED ANSWER! WILL GIVE BRAINLIEST! 8.06 Activity A theme park compa

Business

Astring or rope will break apart if it is placed under too much tensile stress. thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. one type of steel has density 7890 kg/m3 and will break if the tensile stress exceeds 7.0×108n/m2. you want to make a guitar string from a mass of 4.0 g of this type of steel. in use, the guitar string must be able to withstand a tension of 900 n without breaking. your job is to determine (a) the maximum length and

Step-by-step answer

P Answered by Master

2

a. radius = 0.0006m = 0.6mm and length =0.393m = 393mm

b. frequency =377.86Hz

Explanation:

Given:

mass of steel= 4g = 0.004kg

density of steel = 7890kg/m3

tensile stress of steel 7.0x10⁸

tension load =900N

from the density, we will calculate for the Volume of the steel string

density = mass/volume

volume = mass/density = 0.004/7890 = 5.07 x 10⁻⁷ m³

from the tensile stress will can get the maximum base Area of the string ,

tensile stress = load/area =

7x10⁸ = 900/A

A = 900/7x10⁸ = 1.29x10⁻⁶ m²

Area = πr²

area/pi = 4.105x10-7

radius = 0.0006m = 0.6mm

volume = Area x length

length = vol/area =(5.07 x 10⁻⁷ m³)/1.29x10⁻⁶ m² = 0.393m

b. the highest possible frequency is given by:

F = $\frac{\sqrt{\frac{T}{m/L} }}{2L}$

where T= tension, m=mass, L=length

F = $\frac{\sqrt{\frac{900}{0.004kg/0.393m} }}{2*0.393m}$

= 297.04/0.786

frequency =377.86Hz

Find the radius of the smaller section formed by

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