Mathematics: Evaluate the expression below when x = 3. If needed, answer as a fraction or a decimal. x3+6x+8

Evaluate the expression below when x = 3. If, №13467715, 23.05.2020 03:55

Mathematics

Worth 99 points if you answer all! question 5(multiple choice worth 1 points) (06.04 mc) what is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2? a. 13.4 b. 16.4 c. 19.4 d. 28.4 question 6(multiple choice worth 1 points) (06.01 mc) what is the value of the expression 9 − (fraction 1 over 2)4 ⋅ 48? a. 1 b. 3 c. 6 d. 9 question 7(multiple choice worth 1 points) (06.02 lc) which statement best describes the expression 2y ÷ 7? a. 2 times y divided by 7 b. 7 divided by 2 times y c. 7 times y divided by 2 d. 2 divided by 7 times y question

Step-by-step answer

P Answered by Master

12

1) C. 19.4
1/3(3)^3 + 5.2(2)
1/3(27) + 10.4
9 + 10.4
= 19.4

2) C. 6
9 - (1/2)^4 * 48
9 - 0.0625 * 48
9 - 3
= 6

3) A. 2 times y divided by 7
4) C. 5p - 4
5) C. Step 2; 4(2) + 4(4x)

Hope this helps!

Mathematics

Worth 99 points if you answer all! question 5(multiple choice worth 1 points) (06.04 mc) what is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2? a. 13.4 b. 16.4 c. 19.4 d. 28.4 question 6(multiple choice worth 1 points) (06.01 mc) what is the value of the expression 9 − (fraction 1 over 2)4 ⋅ 48? a. 1 b. 3 c. 6 d. 9 question 7(multiple choice worth 1 points) (06.02 lc) which statement best describes the expression 2y ÷ 7? a. 2 times y divided by 7 b. 7 divided by 2 times y c. 7 times y divided by 2 d. 2 divided by 7 times y question

Step-by-step answer

P Answered by Master

12

1) C. 19.4
1/3(3)^3 + 5.2(2)
1/3(27) + 10.4
9 + 10.4
= 19.4

2) C. 6
9 - (1/2)^4 * 48
9 - 0.0625 * 48
9 - 3
= 6

3) A. 2 times y divided by 7
4) C. 5p - 4
5) C. Step 2; 4(2) + 4(4x)

Hope this helps!

Mathematics

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Baseline) (y Superscript negative 2 Baseline) Over 2 (x Superscript 4 Baseline) (y superscript negative 4 Baseline) EndFraction) Superscript negative 3, when x = negative 1 and y = 2. Step 1: Substitute x = negative 1 and y = 2 into the expression. (StartFraction (negative 1) Superscript negative 3 Baseline (2) Superscript negative 2 Baseline Over 2 (negative 1) Superscript 4 Baseline (2) superscript negative 4 Baseline) EndFraction)

Step-by-step answer

P Answered by PhD

6

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

__

We expect your answer is supposed to be Step 4.

Mathematics

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Baseline) (y Superscript negative 2 Baseline) Over 2 (x Superscript 4 Baseline) (y superscript negative 4 Baseline) EndFraction) Superscript negative 3, when x = negative 1 and y = 2. Step 1: Substitute x = negative 1 and y = 2 into the expression. (StartFraction (negative 1) Superscript negative 3 Baseline (2) Superscript negative 2 Baseline Over 2 (negative 1) Superscript 4 Baseline (2) superscript negative 4 Baseline) EndFraction)

Step-by-step answer

P Answered by PhD

6

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

__

We expect your answer is supposed to be Step 4.

Mathematics

Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Baseline) (y Superscript negative 2 Baseline) Over 2 (x Superscript 4 Baseline) (y superscript negative 4 Baseline) EndFraction) Superscript negative 3, when x = negative 1 and y = 2. Step 1: Substitute x = negative 1 and y = 2 into the expression. (StartFraction (negative 1) Superscript negative 3 Baseline (2) Superscript negative 2 Baseline Over 2 (negative 1) Superscript 4 Baseline (2) superscript negative 4 Baseline) EndFraction) Superscript negative

Step-by-step answer

P Answered by PhD

38

9514 1404 393

Step 4

Step-by-step explanation:

Step 4 should look like ...

$\dfrac{2^3\cdot(-1)^{21}}{2^6}=\dfrac{-8}{64}=-\dfrac{1}{8}$

All steps up to that point are correct. Step 4 has the first error.

_____

Comment on the question

It took about 15 minutes to translate the mishmash provided in this problem statement into something sensible. A picture or math symbols are much preferred. At the very least, some line spacing or formatting of the text would be useful.

Mathematics

Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Baseline) (y Superscript negative 2 Baseline) Over 2 (x Superscript 4 Baseline) (y superscript negative 4 Baseline) EndFraction) Superscript negative 3, when x = negative 1 and y = 2. Step 1: Substitute x = negative 1 and y = 2 into the expression. (StartFraction (negative 1) Superscript negative 3 Baseline (2) Superscript negative 2 Baseline Over 2 (negative 1) Superscript 4 Baseline (2) superscript negative 4 Baseline) EndFraction) Superscript negative

Step-by-step answer

P Answered by PhD

1

Step 3

Step-by-step explanation:

Mathematics

You can buy jars of the same jam in 2 sizes large jar:440g for £1.54 small jar:340g for £1.26 By considering the price per gram, work out which jar is the best value for money. Working must be shown

Step-by-step answer

P Answered by PhD

Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram

Mathematics

Anthony received $150 for his birthday this year. This was $10 less than half the amount he received last year. How much money did Anthony receive for his birthday last year?

Step-by-step answer

P Answered by PhD

The answer is in the image

Mathematics

A 4300-N force from a car s engines produces an acceleration of 3.3 m/s2. What is the mass of the car? A. 4300 kg B. 1300 kg C. 14,000 kg D. 390 kg

Step-by-step answer

P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

=4300/3.3

=1303.03kg

Mathematics

A 4300-N force from a car s engines produces an acceleration of 3.3 m/s2. What is the mass of the car? A. 4300 kg B. 1300 kg C. 14,000 kg D. 390 kg

Step-by-step answer

P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

=4300/3.3

=1303.03kg

Approximately it is aqual to 1300kg

Evaluate the expression below when x = 3. If needed, answer as a fraction or a decimal.
x3+6x+8

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