22.04.2021

What is the square root of 70.891

. 5

Faq

Mathematics
Step-by-step answer
P Answered by PhD
ANSWER TO QUESTION 1.

We use the Pythagoras Theorem to determine  the height of the shelf.

Let h be the height of the triangle,b the base and c the hypotenuse.

Then by the Pythagoras Theorem,

h^2+b^2=c^2

We substitute the base, b=5 and the hypotenuse c=12

h^2+5^2=12^2

h^2+25=144

h^2=144-25

h^2=119

h=\sqrt{119}

h=10.90cm.

Therefore the approximate minimum height of the shelf should be h=10.90cm.

the correct answer is A

ANSWER TO QUESTION 2

We apply the Pythagoras Theorem to find the length of the third side.

See diagram

Let the length of the third side be y.

Then

y^2+24^2=74^2

We can now solve for y.

y^2+576=5476

y^2=5476-576

y^2=4900

y=\sqrt{4900}

y=70

The correct answer is C

ANSWER TO QUESTION 3

We use the Pythagoras Theorem to find the length of PR.

Since PR is the hypotenuse .

|PR|^2=|PQ|^2+|RQ|^2

|PR|^2=36^2+48^2

|PR|^2=1296+2304

|PR|^2=3600

|PR|=\sqrt{3600}

|PR|=60cm

The correct answer is C

See diagram in attachment.

ANSWER TO QUESTION 4

The unknown length is the variable x, which is the hypotenuse of the right angle triangle.

So we use the Pythagoras theorem to find the unknown length.

x^2=24^2+7^2

\Rightarrow x^2=576+49

\Rightarrow x^2=625

\Rightarrow x=\sqrt{625}

\Rightarrow x=25

The correct answer is C

ANSWER TO QUESTION 5.

From Pythagoras Theorem, the area of the bigger square is equal to the area of the two smaller squares added together.

See diagram in attachment.

That is x^2=6^2+8^2.

This implies that,

x^2=36+64

x^2=100

x=\sqrt{100}

x=10cm

The correct answer is D

ANSWER TO QUESTION 6

Let a be the length of the unknown leg.

Then from the Pythagoras Theorem,

a^2+144^2=145^2

This implies that;

a^2=145^2-144^2

a^2=21,025-20,736

a^2=289

a=\sqrt{289}

a=17 units

The correct answer is option A.

It is incorrect because the length of the unknown side is \sqrt{289} and not 289.

ANSWER TO QUESTION 7

The diagonal is the hypotenuse of the right angle triangle created by the diagonal, the width and the length of the rectangle.

Since the diagonal is the hypotenuse and the two shorter sides are the width and the length of the rectangle, we can apply the Pythagoras Theorem to find the value of x.

x^2+63^2=65^2

x^2+3969=4225

x^2=4225-3969

x^2=256

x=\sqrt{256}

x=16

The correct answer is B.

ANSWER TO QUESTION 8

Since the width of the cups is 2 inches, it means the radius is half the width.

That is r=1 inch

The volume of a cylinder is given by;

V=\pi r^2 h

The cup with the cylindrical shape (B) will hold

=1^2\times 7 \pi

=7 \pi cubic inches of juice

The volume of a cone is:

V=\frac{1}{3} \pi r^2 h

The cup with the conical shape cup(A), will hold

V=\frac{1}{3}\times 1^2 \times 3 \pi

V=\picubic inches of juice

Hence cup B will hold 7\pi -\pi=6\pi=18.8 cubic inches than cup A.

The correct answer is A
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
Mathematics
Step-by-step answer
P Answered by PhD
ANSWER TO QUESTION 1.

We use the Pythagoras Theorem to determine  the height of the shelf.

Let h be the height of the triangle,b the base and c the hypotenuse.

Then by the Pythagoras Theorem,

h^2+b^2=c^2

We substitute the base, b=5 and the hypotenuse c=12

h^2+5^2=12^2

h^2+25=144

h^2=144-25

h^2=119

h=\sqrt{119}

h=10.90cm.

Therefore the approximate minimum height of the shelf should be h=10.90cm.

the correct answer is A

ANSWER TO QUESTION 2

We apply the Pythagoras Theorem to find the length of the third side.

See diagram

Let the length of the third side be y.

Then

y^2+24^2=74^2

We can now solve for y.

y^2+576=5476

y^2=5476-576

y^2=4900

y=\sqrt{4900}

y=70

The correct answer is C

ANSWER TO QUESTION 3

We use the Pythagoras Theorem to find the length of PR.

Since PR is the hypotenuse .

|PR|^2=|PQ|^2+|RQ|^2

|PR|^2=36^2+48^2

|PR|^2=1296+2304

|PR|^2=3600

|PR|=\sqrt{3600}

|PR|=60cm

The correct answer is C

See diagram in attachment.

ANSWER TO QUESTION 4

The unknown length is the variable x, which is the hypotenuse of the right angle triangle.

So we use the Pythagoras theorem to find the unknown length.

x^2=24^2+7^2

\Rightarrow x^2=576+49

\Rightarrow x^2=625

\Rightarrow x=\sqrt{625}

\Rightarrow x=25

The correct answer is C

ANSWER TO QUESTION 5.

From Pythagoras Theorem, the area of the bigger square is equal to the area of the two smaller squares added together.

See diagram in attachment.

That is x^2=6^2+8^2.

This implies that,

x^2=36+64

x^2=100

x=\sqrt{100}

x=10cm

The correct answer is D

ANSWER TO QUESTION 6

Let a be the length of the unknown leg.

Then from the Pythagoras Theorem,

a^2+144^2=145^2

This implies that;

a^2=145^2-144^2

a^2=21,025-20,736

a^2=289

a=\sqrt{289}

a=17 units

The correct answer is option A.

It is incorrect because the length of the unknown side is \sqrt{289} and not 289.

ANSWER TO QUESTION 7

The diagonal is the hypotenuse of the right angle triangle created by the diagonal, the width and the length of the rectangle.

Since the diagonal is the hypotenuse and the two shorter sides are the width and the length of the rectangle, we can apply the Pythagoras Theorem to find the value of x.

x^2+63^2=65^2

x^2+3969=4225

x^2=4225-3969

x^2=256

x=\sqrt{256}

x=16

The correct answer is B.

ANSWER TO QUESTION 8

Since the width of the cups is 2 inches, it means the radius is half the width.

That is r=1 inch

The volume of a cylinder is given by;

V=\pi r^2 h

The cup with the cylindrical shape (B) will hold

=1^2\times 7 \pi

=7 \pi cubic inches of juice

The volume of a cone is:

V=\frac{1}{3} \pi r^2 h

The cup with the conical shape cup(A), will hold

V=\frac{1}{3}\times 1^2 \times 3 \pi

V=\picubic inches of juice

Hence cup B will hold 7\pi -\pi=6\pi=18.8 cubic inches than cup A.

The correct answer is A
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
So, i have a bunch of math questions and if someone can answer some or all of them that would be gre
Mathematics
Step-by-step answer
P Answered by Master

79.5688 < µ < 83.1646

Step-by-step explanation:

Sample mean is the sum of all scores, divided the the total number of test takers.  In this case, the sample mean is:

(87.4 + 86.9 + 89.9 + 78.3 + 75.1 + 70.6)/6 =  488.2/2 = 81.3667

The sample standard deviation is the square root of the sample variance.  See attached photo 1 for calculation of these values...

The sample standard deviation is 3.1856

We need to make a 90% confidence interval for this data.  Since n < 30, we will use a t-value.  The degrees of freedom is always one less than the sample size so on the t-distribution chart, look under the column for Area under the curve = 0.10, and the row for 5.  The t-value you should see is t = 2.015

See attached photo 2 for the construction of the confidence interval


The principal randomly selected six students to take an aptitude test. their scores were:  87.4 86.9
The principal randomly selected six students to take an aptitude test. their scores were:  87.4 86.9
Mathematics
Step-by-step answer
P Answered by Master

79.5688 < µ < 83.1646

Step-by-step explanation:

Sample mean is the sum of all scores, divided the the total number of test takers.  In this case, the sample mean is:

(87.4 + 86.9 + 89.9 + 78.3 + 75.1 + 70.6)/6 =  488.2/2 = 81.3667

The sample standard deviation is the square root of the sample variance.  See attached photo 1 for calculation of these values...

The sample standard deviation is 3.1856

We need to make a 90% confidence interval for this data.  Since n < 30, we will use a t-value.  The degrees of freedom is always one less than the sample size so on the t-distribution chart, look under the column for Area under the curve = 0.10, and the row for 5.  The t-value you should see is t = 2.015

See attached photo 2 for the construction of the confidence interval


The principal randomly selected six students to take an aptitude test. their scores were:  87.4 86.9
The principal randomly selected six students to take an aptitude test. their scores were:  87.4 86.9
Mathematics
Step-by-step answer
P Answered by PhD

\large\boxed{d=\dfrac{31\sqrt{34}}{34}\approx5.32}

Step-by-step explanation:

The formula of a distance between a point (x₀, y₀) and a line Ax + By + C = 0:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}

We have the point D(5, 4) and the line 3x + 5y - 4 = 0.

Substitute:

x_0=5,\ y_0=4,\ A=3,\ B=5,\ C=-4

d=\dfrac{|(3)(5)+(5)(4)-4|}{\sqrt{3^2+5^2}}=\dfrac{|15+20-4|}{\sqrt{9+25}}=\dfrac{|31|}{\sqrt{34}}\cdot\dfrac{\sqrt{34}}{\sqrt{34}}=\dfrac{31\sqrt{34}}{34}

Mathematics
Step-by-step answer
P Answered by PhD

\large\boxed{d=\dfrac{31\sqrt{34}}{34}\approx5.32}

Step-by-step explanation:

The formula of a distance between a point (x₀, y₀) and a line Ax + By + C = 0:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}

We have the point D(5, 4) and the line 3x + 5y - 4 = 0.

Substitute:

x_0=5,\ y_0=4,\ A=3,\ B=5,\ C=-4

d=\dfrac{|(3)(5)+(5)(4)-4|}{\sqrt{3^2+5^2}}=\dfrac{|15+20-4|}{\sqrt{9+25}}=\dfrac{|31|}{\sqrt{34}}\cdot\dfrac{\sqrt{34}}{\sqrt{34}}=\dfrac{31\sqrt{34}}{34}

Try asking the Studen AI a question.

It will provide an instant answer!

FREE