17.03.2021

Help hère to answer this question please

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Chemistry
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P Answered by Master

answers in order C,A,B,D,because the reactants only partially ionize in the solution,none of these( SO4 2- is a strong one),none of these( all are weak),same(beacause both Ka and Kb values are equal in those subtances),di,mono,tri,mono,mono,mono,di,di,mono,Na2Be(OH)4(aq)...

Explanation:

this quiz doesnt worth my time...but have a nice day.

Chemistry
Step-by-step answer
P Answered by Specialist

answers in order C,A,B,D,because the reactants only partially ionize in the solution,none of these( SO4 2- is a strong one),none of these( all are weak),same(beacause both Ka and Kb values are equal in those subtances),di,mono,tri,mono,mono,mono,di,di,mono,Na2Be(OH)4(aq)...

Explanation:

this quiz doesnt worth my time...but have a nice day.

Chemistry
Step-by-step answer
P Answered by PhD

See below  

Explanation:

a) Adding HCl

HBTB is yellow in acid solution.

b) Adding NaOH

HBTB is blue in basic solution.

c) Explanation

HBTB is a weak acid in which the undissociated and ionized forms have different colours.

\underbrace{\hbox{\text{HBTB }}}_{\hbox{\text{yellow}}} + \text{{ H$_{2}$O}}\rightleftharpoons \text{H$_{3}$O$^{+}$} +\underbrace{\hbox{\text{ BTB$^{-}$}}}_{\hbox{\text{blue}}}

Around pH 7 , the indicator consists of roughly equal amounts of the yellow and blue forms, so it appears green

According to Le Châtelier's Principle, if you apply a stress to a system at equilibrium, it will respond in a way that will relieve the stress.

When you added HCl, you increased the concentration of H₃O⁺. The system responded in a way that would decrease the H₃O⁺. That is, the position of equilibrium shifted to the left and produced more of the yellow form.

When you added NaOH, the base removed some of the H₃O⁺. The system responded in a way that would increase the H₃O⁺. That is, the position of equilibrium shifted to the right and produced more of the blue form

Chemistry
Step-by-step answer
P Answered by PhD

See below  

Explanation:

a) Adding HCl

HBTB is yellow in acid solution.

b) Adding NaOH

HBTB is blue in basic solution.

c) Explanation

HBTB is a weak acid in which the undissociated and ionized forms have different colours.

\underbrace{\hbox{\text{HBTB }}}_{\hbox{\text{yellow}}} + \text{{ H$_{2}$O}}\rightleftharpoons \text{H$_{3}$O$^{+}$} +\underbrace{\hbox{\text{ BTB$^{-}$}}}_{\hbox{\text{blue}}}

Around pH 7 , the indicator consists of roughly equal amounts of the yellow and blue forms, so it appears green

According to Le Châtelier's Principle, if you apply a stress to a system at equilibrium, it will respond in a way that will relieve the stress.

When you added HCl, you increased the concentration of H₃O⁺. The system responded in a way that would decrease the H₃O⁺. That is, the position of equilibrium shifted to the left and produced more of the yellow form.

When you added NaOH, the base removed some of the H₃O⁺. The system responded in a way that would increase the H₃O⁺. That is, the position of equilibrium shifted to the right and produced more of the blue form

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