Mathematics : asked on Ruby8342
 15.03.2020

If p:q = 2/3 : 3 and p:r = 3/4 : 2/3, calculate the ratio p:q:r

. 5

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Mathematics
Step-by-step answer
P Answered by Master

Given  

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3  = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2  = 3/2  

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

p/q = 2/9 x 3/3 = 6/27 and

p/r = 2/3 x 3/2 = 6/4

Therefore p : q : r = 6 : 27 : 4

Mathematics
Step-by-step answer
P Answered by Specialist

Given  

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3  = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2  = 3/2  

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

p/q = 2/9 x 3/3 = 6/27 and

p/r = 2/3 x 3/2 = 6/4

Therefore p : q : r = 6 : 27 : 4

Mathematics
Step-by-step answer
P Answered by PhD
P:q = ⅔:3
p/q = 2/9 = 6/27

p:r = ¾:½
p/r = 3/2 = 6/4

p:q:r = 6:27:4
Mathematics
Step-by-step answer
P Answered by PhD
P:q = ⅔:3
p/q = 2/9 = 6/27

p:r = ¾:½
p/r = 3/2 = 6/4

p:q:r = 6:27:4
Mathematics
Step-by-step answer
P Answered by Master

p : q : r = 2 : 12 : 3

Step-by-step explanation:

p : q = 1/3 : 2

p : q = 1/3 ÷ 2

p : q = 1/3 × 1/2

p : q = 1/6

p : q = 1:6 (a)

p : r = 1/2 : 3/4

p : r = 1/2 : 3/4

p : r = 1/2 × 4/3

p : r = 2/3

p : r = 2 : 3 (b)

For p in equation (a) to be the same as equation (b) so, multiply equation (a) by 2 and multiply equation (b) by 1

p : q = 1 × 2 : 6 × 2

p : q = 2 : 12

p : r = 2 × 1 : 3 × 1

p : r = 2 : 3

p = 2 : , q = 12 , r = 3

Hope it help

p : q : r = 2 : 12 : 3

Mathematics
Step-by-step answer
P Answered by Specialist

p : q : r = 2 : 12 : 3

Step-by-step explanation:

p : q = 1/3 : 2

p : q = 1/3 ÷ 2

p : q = 1/3 × 1/2

p : q = 1/6

p : q = 1:6 (a)

p : r = 1/2 : 3/4

p : r = 1/2 : 3/4

p : r = 1/2 × 4/3

p : r = 2/3

p : r = 2 : 3 (b)

For p in equation (a) to be the same as equation (b) so, multiply equation (a) by 2 and multiply equation (b) by 1

p : q = 1 × 2 : 6 × 2

p : q = 2 : 12

p : r = 2 × 1 : 3 × 1

p : r = 2 : 3

p = 2 : , q = 12 , r = 3

Hope it help

p : q : r = 2 : 12 : 3

Mathematics
Step-by-step answer
P Answered by PhD

p : q : r = 2 : 12 : 3

Step-by-step explanation:

Biology
Step-by-step answer
P Answered by PhD

Option D, Generation 1 has fewer purple flowers than generation 3 is correct.

Explanation:

Given -

Ration of color flower to white flower in generation I = 0.5:0.5

Total Number of color flowers in generation I

= 0.5 * 200\\= 100

Total Number of white flowers in generation I

= 0.5 * 200\\= 100

Ration of color flower to white flower in generation II = 0.6:0.4

Total Number of color flowers in generation II

= 0.6 * 400\\= 240

Total Number of white flowers in generation II

= 0.4 * 400\\= 160

Ration of color flower to white flower in generation III = 0.7:0.3

Total Number of color flowers in generation III

= 0.7 * 400\\= 280

Total Number of white flowers in generation III

= 0.3 * 400\\= 120

Option D, Generation 1 has fewer purple flowers than generation 3 is correct.

Mathematics
Step-by-step answer
P Answered by PhD

Q2. (16,8)

Q3. k=\frac{2}{3}, ratio=5:1

Q4. Ratio=2:1

Q5. Ratio=1:1

Step-by-step explanation:

Q2. Let (2a,a) be the coordinates of P.

Since P is equidistant  from Q (2,-5) and R (-3, 6), we have

|PQ|=|PR|

This gives us:

\sqrt{(2a-2)^2+(a+5)^2}=\sqrt{(2a+3)^2+(6-a)^2}

\implies (2a-2)^2+(a+5)^2=(2a+3)^2+(6-a)^2

Expand:

4a^2-8a+4+a^2+10a+25=4a^2+12a+9+a^2 -12a+36

2a=16

a=8

The coordinates of P are (16,8)

Q.3  The equation of the line segment joining the points

A (5.-6) and B (-1,-4) is x+3y=-13.

The x-coordinate of the point that divides AB in the ratio m:n is

x=\frac{mx_2+nx_1}{m+n}

The y-axis meets this line at (0,-\frac{13}{3})

We substitute x_2=-1,x_1=5,x=0 into this equation and solve for m and n.

0=\frac{-m+5n}{m+n}

m=5n

\frac{m}{n}=\frac{5}{1}

Therefore the ratio is m:n=5:1

Q.4 The equation of the line segment joining

the points (-5,-4) and (-2,3) is -7x+3y=23.

The point (-3, k) must satisfy this line because it lies on it.

-7(-3)+3k=23.

\implies k=\frac{2}{3}

We again use the equation x=\frac{mx_2+nx_1}{m+n} to find the given ratio.

Substitute: x_2=-2,x_1=-5

4=\frac{-2m+-5n}{m+n}

\implies m=2n

\frac{m}{n}= \frac{2}{1}

The ratio is m:n=2:1

Q. 5 The equation of the line joining A (2,3) and B(6,-3) is 3x+2y=12.

We substitute (4,m) to get:

12+4m=12

4m=0

m=0

It is obvious that: (4,0) is the midpoint of A(2,3) and B(6,-3).

Hence the ratio is 1:1

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