Mathematics: Numbers that are greater than 6

Numbers that are greater than 6, №14095974, 18.08.2021 04:41

Mathematics

I HOPE SOMEONE CAN ANSWER THIS WILL MARK BRAINLEST TOO!Which shows the correct solution to the inequality StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p? StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 7 over 10 EndFraction minus 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 28 over 40 EndFraction minus 1 and StartFraction 25 over 40 EndFraction greater-than-or-equal-to p. p less-than-or-equal-to negative

Step-by-step answer

P Answered by Master

32

The answer is B, or the second option: The sequence is recursive and can be represented by the function f(n + 1) = f(n) + f of n plus 1 equals f of n plus StartFraction 3 Over 8 EndFraction..

Mathematics

Yuto and Hila attempted to solve the same inequality. Their work is shown below. Yuto’s Work Hila’s Work Negative two-thirds x + 9 greater-than 7. Negative two-thirds x + 9 minus 9 greater-than 7 minus 9. Negative two-thirds x greater-than negative 2. (Negative three-halves) (Negative two-thirds x) less-than (Negative three-halves) (Negative StartFraction 2 over 1 EndFraction). x less-than 3. Negative two-thirds x + 9 greater-than 7. Negative two-thirds x + 9 minus 9 greater-than 7 minus 9. Negative two-thirds x greater-than 16. (Negative three-halves)

Step-by-step answer

P Answered by Master

1

A. Yuto is correct because he isolated the variable correctly and reversed the inequality symbol.

Step-by-step explanation:

Did it on edge 2020

plz mark as brainliest

Mathematics

Yuto and Hila attempted to solve the same inequality. Their work is shown below. Yuto’s Work Hila’s Work Negative two-thirds x + 9 greater-than 7. Negative two-thirds x + 9 minus 9 greater-than 7 minus 9. Negative two-thirds x greater-than negative 2. (Negative three-halves) (Negative two-thirds x) less-than (Negative three-halves) (Negative StartFraction 2 over 1 EndFraction). x less-than 3. Negative two-thirds x + 9 greater-than 7. Negative two-thirds x + 9 minus 9 greater-than 7 minus 9. Negative two-thirds x greater-than 16. (Negative three-halves)

Step-by-step answer

P Answered by Master

1

A. Yuto is correct because he isolated the variable correctly and reversed the inequality symbol.

Step-by-step explanation:

Did it on edge 2020

plz mark as brainliest

Mathematics

Marquis used the steps below to find the solution to the inequality Negative 5.6 greater-than-or-equal-to x + 3.6. Step 1 Subtract 3.6 from both sides of the inequality. Negative 5.6 greater-than-or-equal-to x + 3.6. Negative 5.6 minus 3.6 greater-than-or-equal-to x + 3.6 minus 3.6. Negative 9.2 greater-than-or-equal-to x. Step 2 Interpret the results. x greater-than-or-equal-to negative 9.2 x is greater than or equal to –9.2. Step 3 Draw a number line. A number line going from negative 9.5 to negative 8.8. A closed circle is at negative 9.2. Everything

Step-by-step answer

P Answered by PhD

1

b

- in step 2, marquis should have interpreted the results as x less-than-or-equal-to negative 9.2, which means that x is less than or equal to –9.2 .

:)))

Step-by-step explanation:

Mathematics

HURRRJuan graphed the solution to the inequality StartAbsoluteValue r minus 4 EndAbsoluteValue greater-than 8 on the number line. A number line going from negative 8 to positive 16. Open circles are at negative 4 and positive 12. Everything to the left of negative 4 and to the right of positive 12 is shaded. Which inequality statement can be used to help determine if the graph is correct? When r = negative 4, StartAbsoluteValue negative 4 minus 4 EndAbsoluteValue greater-than 8, which is true because 8 is equal to 8. When r = negative 8, StartAbsoluteValue

Step-by-step answer

P Answered by Specialist

5

c) When r = 14, StartAbsoluteValue 14 minus 4 EndAbsoluteValue greater-than 8, which is true because 10 is greater than 8.

Step-by-step explanation:

got it right on edgenuity 2020

Mathematics

Marquis used the steps below to find the solution to the inequality Negative 5.6 greater-than-or-equal-to x + 3.6. Step 1 Subtract 3.6 from both sides of the inequality. Negative 5.6 greater-than-or-equal-to x + 3.6. Negative 5.6 minus 3.6 greater-than-or-equal-to x + 3.6 minus 3.6. Negative 9.2 greater-than-or-equal-to x. Step 2 Interpret the results. x greater-than-or-equal-to negative 9.2 x is greater than or equal to –9.2. Step 3 Draw a number line. A number line going from negative 9.5 to negative 8.8. A closed circle is at negative 9.2. Everything

Step-by-step answer

P Answered by PhD

1

b

- in step 2, marquis should have interpreted the results as x less-than-or-equal-to negative 9.2, which means that x is less than or equal to –9.2 .

:)))

Step-by-step explanation:

Mathematics

Which inequalities can be used to find the solution set of the following inequality? Check all that apply. |2x – 5| Greater-than-or-equal-to 8 (2x – 5) Greater-than-or-equal-to 8 (2x – 5) Less-than-or-equal-to 8 (2x + 5) Greater-than-or-equal-to 8 –(2x – 5) Greater-than-or-equal-to 8 –(2x + 5) Greater-than-or-equal-to 8

Step-by-step answer

P Answered by Master

25

its 1 and 4

1. (2x – 5) ≥ 8

4. –(2x – 5) ≥ 8

Step-by-step explanation:

i just did the test

Mathematics

What is the solution to 3 x + 2.4 greater-than-or-equal-to 3.0? x greater-than-or-equal-to 0.2 x greater-than-or-equal-to 0.6 x greater-than-or-equal-to 1.8 x greater-than-or-equal-to 2.5

Step-by-step answer

P Answered by PhD

61

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

3x + 2.4 ≥ 3.0 First subtract 2.4 on both sides

3x + 2.4 - 2.4 ≥ 3.0 - 2.4

3x ≥ 0.6 Now divide 3 on both sides to get "x" by itself

$\frac{3x}{3} \geq \frac{0.6}{3}$

x ≥ 0.2 Your answer is the 1st option

Mathematics

Which inequalities can be used to find the solution set of the following inequality? Check all that apply. |2x – 5| Greater-than-or-equal-to 8 (2x – 5) Greater-than-or-equal-to 8 (2x – 5) Less-than-or-equal-to 8 (2x + 5) Greater-than-or-equal-to 8 –(2x – 5) Greater-than-or-equal-to 8 –(2x + 5) Greater-than-or-equal-to 8

Step-by-step answer

P Answered by Master

25

its 1 and 4

1. (2x – 5) ≥ 8

4. –(2x – 5) ≥ 8

Step-by-step explanation:

i just did the test

Mathematics

What is the solution to 3 x + 2.4 greater-than-or-equal-to 3.0? x greater-than-or-equal-to 0.2 x greater-than-or-equal-to 0.6 x greater-than-or-equal-to 1.8 x greater-than-or-equal-to 2.5

Step-by-step answer

P Answered by PhD

61

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

3x + 2.4 ≥ 3.0 First subtract 2.4 on both sides

3x + 2.4 - 2.4 ≥ 3.0 - 2.4

3x ≥ 0.6 Now divide 3 on both sides to get "x" by itself

$\frac{3x}{3} \geq \frac{0.6}{3}$

x ≥ 0.2 Your answer is the 1st option

Numbers that are greater than 6

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