9514 1404 393
7. (x, y) = (0, 1)
10. (x, y) ={((7+√97)/2, (-1-√97)/2) and ((7-√97)/2, (-1+√97)/2)
6. (x, y) = (-3+√6, -1+√6) and (-3-√6, -1-√6)
Step-by-step explanation:
7. It is convenient to subtract the second equation from the first:
(y) -(y) = (x^2 +5x +1) -(x^2 +2x +1)
0 = 3x . . . . simplify
0 = x . . . . . divide by 3
y = 0 + 0 + 1 . . . . substitute x=0 into either equation
The solution is (x, y) = (0, 1). The first attachment shows this solution.
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10. It can work to subtract the first equation from the second.
(y) -(x +y) = (x^2 -8x -9) -(3)
-x = x^2 -8x -12 . . . . simplify
x^2 -7x = 12 . . . . . . . add x+12, swap sides
x^2 -7x +49/4 = 12 +49/4 . . . . complete the square
(x -7/2)^2 = 97/4 . . . . . . . . write as a square
x -7/2 = (±√97)/2 . . . . . . . square root
x = (7±√97)/2 . . . . . add 7/2
y = 3 -x = (-1±√97)/2 . . . . find corresponding y
Solutions are (x, y) = {((7+√97)/2, (-1-√97)/2), ((7-√97)/2, (-1+√97)/2)}. The second attachment shows the solution.
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6. For this one, it can work well to subtract the first equation from the second.
(y) -(y) = (x +2) - (-x^2 -5x -1)
0 = x^2 +6x +3
Adding 6 to both sides completes the square.
x^2 +6x +9 = 6
(x +3)^2 = 6
x +3 = ±√6
x = -3±√6
y = x +2 = -1±√6
Solutions are (x, y) = (-3+√6, -1+√6) and (-3-√6, -1-√6). The third attachment shows the solution.
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About completing the square
In general, completing the square starts with ...
x^2 +ax = b
Then the square is completed by adding the square of a/2.
x^2 +ax +(a/2)^2 = b + (a/2)^2
Then you can write the left side as a square.
(x +a/2)^2 = (b +a^2/4)
Finally, take the square root and subtract the left-side constant.
x = -a/2 ± √(b +a^2/4)
About a week ago this question was not answered. And today, I'm asking if you got your answers and if so, pass the answers. -#- plz?
9514 1404 393
7. (x, y) = (0, 1)
10. (x, y) ={((7+√97)/2, (-1-√97)/2) and ((7-√97)/2, (-1+√97)/2)
6. (x, y) = (-3+√6, -1+√6) and (-3-√6, -1-√6)
Step-by-step explanation:
7. It is convenient to subtract the second equation from the first:
(y) -(y) = (x^2 +5x +1) -(x^2 +2x +1)
0 = 3x . . . . simplify
0 = x . . . . . divide by 3
y = 0 + 0 + 1 . . . . substitute x=0 into either equation
The solution is (x, y) = (0, 1). The first attachment shows this solution.
__
10. It can work to subtract the first equation from the second.
(y) -(x +y) = (x^2 -8x -9) -(3)
-x = x^2 -8x -12 . . . . simplify
x^2 -7x = 12 . . . . . . . add x+12, swap sides
x^2 -7x +49/4 = 12 +49/4 . . . . complete the square
(x -7/2)^2 = 97/4 . . . . . . . . write as a square
x -7/2 = (±√97)/2 . . . . . . . square root
x = (7±√97)/2 . . . . . add 7/2
y = 3 -x = (-1±√97)/2 . . . . find corresponding y
Solutions are (x, y) = {((7+√97)/2, (-1-√97)/2), ((7-√97)/2, (-1+√97)/2)}. The second attachment shows the solution.
__
6. For this one, it can work well to subtract the first equation from the second.
(y) -(y) = (x +2) - (-x^2 -5x -1)
0 = x^2 +6x +3
Adding 6 to both sides completes the square.
x^2 +6x +9 = 6
(x +3)^2 = 6
x +3 = ±√6
x = -3±√6
y = x +2 = -1±√6
Solutions are (x, y) = (-3+√6, -1+√6) and (-3-√6, -1-√6). The third attachment shows the solution.
_____
About completing the square
In general, completing the square starts with ...
x^2 +ax = b
Then the square is completed by adding the square of a/2.
x^2 +ax +(a/2)^2 = b + (a/2)^2
Then you can write the left side as a square.
(x +a/2)^2 = (b +a^2/4)
Finally, take the square root and subtract the left-side constant.
x = -a/2 ± √(b +a^2/4)
Explanation:
The force is a vector magnitude, it has direction, course and intensity.
Suppose that you have given two forces at a certain angle and that you need to find the resultant force then you apply the Parallelogram of force low.
You represent the two forces in the drawing as vectors and connect their origin to the same point and then construct a parallelogram over them.
The longer diagonal represents the resultant force.
God is with you!!!
I don't know exactly how chromebook work, but on windows I would go to device manager, disable the driver for the pen for 10 sec, then re-enable it.
About a week ago this question was not answered. And today, I'm asking if you got your answers and if so, pass the answers. -#- plz?
It will provide an instant answer!