06.05.2020

By rounding each number to 1 significant figure estimate:
23.4x13.9 divided by 0.18

. 67

Step-by-step answer

02.01.2023, solved by verified expert

Faq

Mathematics
Step-by-step answer
P Answered by PhD

100

Step-by-step explanation:

Round off each number to 1 significant figure first.

(39×52)/(3.8×4.9) = (40×50)/(4×5)

Evaluate numbers in brackets.

(40×50)/(4×5) = 2000/20

Evaluate.

2000/20 = 100

Mathematics
Step-by-step answer
P Answered by PhD

100

Step-by-step explanation:

Round off each number to 1 significant figure first.

(39×52)/(3.8×4.9) = (40×50)/(4×5)

Evaluate numbers in brackets.

(40×50)/(4×5) = 2000/20

Evaluate.

2000/20 = 100

Mathematics
Step-by-step answer
P Answered by PhD

the estimated answer is 2,000

Step-by-step explanation:

The computation is shown below;

Given that

985 \times \frac{22.6}{9.79}

If we rounded each number to the one significant figure

So,

= 1000 \times \frac{20}{10} \\\\= 1000 \times 2

= 2,000

Hence, the estimated answer is 2,000

Mathematics
Step-by-step answer
P Answered by Master

1000

Step-by-step explanation:

23.4 to 1 sf gives 20

13.9 to 1 sf gives 10

0.18 to 1 sf gives 0.2

Therefore it becomes 20 × 10 ÷ 0.2 = 200 ÷ 0.2 = 1000

Mathematics
Step-by-step answer
P Answered by Specialist

ansewr is 391

Mathematics
Step-by-step answer
P Answered by PhD
400.

Step-by-step explanation:

The given expression is

\frac{763 \times 42}{82}

First, we multiply the product in the numerator, then we divide.

\frac{763 \times 42}{82}=\frac{32,046}{82} \approx 390.8

However, this result has more than one significant figures, it has 4 significant figures.

Remember that significant figures refers to those numbers that offer impotant information about a measurement. For example, if we measured a length of 0.00623 kilometers, the digits that gives information about the measurement are 623, so the number has 3 significant numbers.

So. if we want to do an estimation with 1 significant number, we need to round the number to 400, because it's closer to 400 than 300.

Therefore, the estimation of the answer with 1 significant number is 400.

Mathematics
Step-by-step answer
P Answered by PhD
400.

Step-by-step explanation:

The given expression is

\frac{763 \times 42}{82}

First, we multiply the product in the numerator, then we divide.

\frac{763 \times 42}{82}=\frac{32,046}{82} \approx 390.8

However, this result has more than one significant figures, it has 4 significant figures.

Remember that significant figures refers to those numbers that offer impotant information about a measurement. For example, if we measured a length of 0.00623 kilometers, the digits that gives information about the measurement are 623, so the number has 3 significant numbers.

So. if we want to do an estimation with 1 significant number, we need to round the number to 400, because it's closer to 400 than 300.

Therefore, the estimation of the answer with 1 significant number is 400.

Mathematics
Step-by-step answer
P Answered by Master
1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10

2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50

3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112

3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000
Mathematics
Step-by-step answer
P Answered by Specialist
1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10

2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50

3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112

3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000
Physics
Step-by-step answer
P Answered by PhD

1) q = 83.4 C

2)52.13 × 10^(19) electrons

Explanation:

1) To calculate the total charge q on the cloud when the breakdown of the surrounding air begins, we will use the formula;

E = kq/r²

Making q the subject, we have;

q = Er²/k

Where k is a constant = 1/(4πε_o)

We are given;

ε_o = 8.85 × 10^(-12)) C²/N.m²

Thus;

k = 1/(4 × π × 8.85 × 10^(-12)) N.m²/C²

k = 8.99 × 10^(9)

Also,we are given E = 3 × 10^(6) N/C

Diameter = 1km = 1000 m

Radius(r) = diameter/2 = 1000/2 = 500 m

Thus;

q = (3 × 10^(6) × 500²)/(8.99 × 10^(9))

q = 83.4 C

2) To get the number of Excess electrons, we will divide the charge gotten in Part 1 above by the charge of a single electron.

Now, charge of a single electron = 1.6 × 10^(-19) C

Thus, number of Excess elecrons = 83.4/(1.6 × 10^(-19)) = 52.13 × 10^(19) electrons

Try asking the Studen AI a question.

It will provide an instant answer!

FREE