03.06.2020

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Write and solve an absolute value inequality to represent the weight of a 5 foot male who would not meet the minimum or maximum weight requirement allowed to enlist the Army.

. 58

Step-by-step answer

14.11.2022, solved by verified expert

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Mathematics
Step-by-step answer
P Answered by PhD

Given that :

Median weight for a 5-foot-tall male to enlist in the US Army = 114.5 lbs

Variation in weight can be 17.5 lbs

Thus, considering the weight of a 5-foot male as x lbs, the absolute value inequality can be given as :

|x - 114.5| < 17.5

So, 

x - 114.5 > -17.5 or x - 114.5 < 17.5

Adding 114.5 to both sides, 

x > 114.5 - 17.5 or x < 114.5 + 17.5

x > 97 or x < 132

Thus, 97 < x < 132

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

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