the additional charge per minute because t represents the number of minutes
Step-by-step explanation:
Step-by-step explanation:
Given that the initial charge/fee for the first 5 minutes is $6
and also the additional rate per minutes is $0.6
we can model the total charges after the equation of a straight
that y= mx+c
now using the required notation
C= 0.6t+ 6
comparing this with the equation of a straight line
the constant term c is $6 flat rate for the first 5 minutes
the gradient 0.6 is m
the dependent variable x is t
and the cost C is y
C(t) = 0.4t + 4
Step-by-step explanation:
Let t represent the total number of minutes of using a computer at the internet cafe.
The cafe charges an initial fee to use the computer and then an additional price per minute of usage. The initial charge to use the computers is $4 and the total charge would be $6 for 5 minutes of use. This is expressed as
5t + 4 = 6
5t = 6 - 4 = 2
t = 2/5 = 0.4
It means that the charge per minute would be $0.4
Therefore, the equation for the function C(t), representing the total cost of using a computer for t minutes at the internet cafe is
C(t) = 0.4t + 4
The equation is .
Step-by-step explanation:
Given:
Initial Charge = $3
Total Cost = $6
Number of minutes used = 5 minutes
Let the additional charge applied per minute be 'x'.
Solution:
Now we can say that;
Total cost to use Computer will be equal to Initial Charge plus additional charge applied per minute multiplied by number of minutes.
framing in equation form we get;
Now Subtracting both side by 3 using subtraction property of equality we get;
Now Dividing both side by 5 using Division property of equality we get;
Hence Additional charge is $0.6.
Now we need to write the equation for the C(t).
Where C(t) ⇒ Total cost using computer
t ⇒ time in minutes at the cafe
Now we know that;
Total cost to use Computer will be equal to Initial Charge plus additional charge applied per minute multiplied by number of minutes.
So with data given equation can be framed as;
Hence, The equation is .
Step-by-step explanation:
Given that the initial charge/fee for the first 5 minutes is $6
and also the additional rate per minutes is $0.6
we can model the total charges after the equation of a straight
that y= mx+c
now using the required notation
C= 0.6t+ 6
comparing this with the equation of a straight line
the constant term c is $6 flat rate for the first 5 minutes
the gradient 0.6 is m
the dependent variable x is t
and the cost C is y
C(t) = 0.4t + 4
Step-by-step explanation:
Let t represent the total number of minutes of using a computer at the internet cafe.
The cafe charges an initial fee to use the computer and then an additional price per minute of usage. The initial charge to use the computers is $4 and the total charge would be $6 for 5 minutes of use. This is expressed as
5t + 4 = 6
5t = 6 - 4 = 2
t = 2/5 = 0.4
It means that the charge per minute would be $0.4
Therefore, the equation for the function C(t), representing the total cost of using a computer for t minutes at the internet cafe is
C(t) = 0.4t + 4
The equation is .
Step-by-step explanation:
Given:
Initial Charge = $3
Total Cost = $6
Number of minutes used = 5 minutes
Let the additional charge applied per minute be 'x'.
Solution:
Now we can say that;
Total cost to use Computer will be equal to Initial Charge plus additional charge applied per minute multiplied by number of minutes.
framing in equation form we get;
Now Subtracting both side by 3 using subtraction property of equality we get;
Now Dividing both side by 5 using Division property of equality we get;
Hence Additional charge is $0.6.
Now we need to write the equation for the C(t).
Where C(t) ⇒ Total cost using computer
t ⇒ time in minutes at the cafe
Now we know that;
Total cost to use Computer will be equal to Initial Charge plus additional charge applied per minute multiplied by number of minutes.
So with data given equation can be framed as;
Hence, The equation is .
Cost of 7 gallons=$24.50
Cost of 1 gallon=24.50/7=3.5
Cost of 15 gallons=15*3.5=52.5
Cost of 15 gallons will be $52.5
The total nom of code that can be used is equal to 5+3 = 8
F=ma
where F=force
m=mass
a=acceleration
Here,
F=4300
a=3.3m/s2
m=F/a
=4300/3.3
=1303.03kg
It will provide an instant answer!