c) When r = 14, StartAbsoluteValue 14 minus 4 EndAbsoluteValue greater-than 8, which is true because 10 is greater than 8.
Step-by-step explanation:
got it right on edgenuity 2020
a line starting at -6 going to the left of this number, and with an open circle around the -6.
Step-by-step explanation:
To solve for this inequality, we need to isolate "x" on one side of the inequality symbol (<):
4 x + 8 < -16
subtract 8 from both sides:
4 x < -16 - 8
4 x < - 24
now divide both sides by 4 to get rid of the 4 that appears multiplying "x":
x < - 24/4
x < - 6
To graph this inequality one needs to highlight all the real numbers of the number line to the left of the value -6, making sure that one draws an open circle around the -6 because we don't want this number to be included (notice that x < -6 implies x-values strictly smaller than -6)
Then one would draw a line starting at -6 going to the left of this number, and with an open circle around the -6.
I would say C I dont want to mess ure grade but I say C hope I help :)
Step-by-step explanation:
I would say C I dont want to mess ure grade but I say C hope I help :)
Step-by-step explanation:
a line starting at -6 going to the left of this number, and with an open circle around the -6.
Step-by-step explanation:
To solve for this inequality, we need to isolate "x" on one side of the inequality symbol (<):
4 x + 8 < -16
subtract 8 from both sides:
4 x < -16 - 8
4 x < - 24
now divide both sides by 4 to get rid of the 4 that appears multiplying "x":
x < - 24/4
x < - 6
To graph this inequality one needs to highlight all the real numbers of the number line to the left of the value -6, making sure that one draws an open circle around the -6 because we don't want this number to be included (notice that x < -6 implies x-values strictly smaller than -6)
Then one would draw a line starting at -6 going to the left of this number, and with an open circle around the -6.
SI=(P*R*T)/100
P=2000
R=1.5
T=6
SI=(2000*1.5*6)/100
=(2000*9)/100
=180
Neil will earn interest of 180
The answer is in the image
The answer is in the image
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