10.01.2021

I need help with this practice problem about proportionality

. 4

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Business
Step-by-step answer
P Answered by PhD

2 hours working on problems, 2 hours reading

Explanation:

Gilberto solved 100 questions in 1st hour from 8 to 9a.m, then solved 175-100= 75 questions in 2nd hour from 9 to 10am, then solved 225 - 175 =50 questions in 3rd hour from 10 to 11am and 250-225 = 25 questions in last hour from 11 to 12 noon.

The marginal, or additional, gain from Gilberto’s first hour of work, from 8:00 AM to 9:00 AM, is 100 questions.

The marginal gain from Gilberto’s third hour of work, from 10:00 AM to 11:00 AM is 25 questions

Gilberto showed diminishing returns over marginal and reduction in questions solved by 25 each hour.

If Gilberto solves problems for 1 hour from 8 to 9am, then he will solve 100 questions, and 3 hours reading is worth solving 3 × 62.5 =187.5 problems therefore total problems solved= 287.5

If Gilberto solves for 2 hours, then he will solve 175 problems and 2 hours of reading will give 2 × 62.5 = 125 problems, therefore total problems solved = 300

If Gilberto solves for 3 hours, that means he will solve 225 problems, and 1 hour reading will be 62.5 problems, then the total problems solved will be = 225 + 62.5 = 287.5

Therefore, the best choice is 2 hours working on problem and 2 hours reading.

Business
Step-by-step answer
P Answered by PhD

2 hours working on problems, 2 hours reading

Explanation:

Gilberto solved 100 questions in 1st hour from 8 to 9a.m, then solved 175-100= 75 questions in 2nd hour from 9 to 10am, then solved 225 - 175 =50 questions in 3rd hour from 10 to 11am and 250-225 = 25 questions in last hour from 11 to 12 noon.

The marginal, or additional, gain from Gilberto’s first hour of work, from 8:00 AM to 9:00 AM, is 100 questions.

The marginal gain from Gilberto’s third hour of work, from 10:00 AM to 11:00 AM is 25 questions

Gilberto showed diminishing returns over marginal and reduction in questions solved by 25 each hour.

If Gilberto solves problems for 1 hour from 8 to 9am, then he will solve 100 questions, and 3 hours reading is worth solving 3 × 62.5 =187.5 problems therefore total problems solved= 287.5

If Gilberto solves for 2 hours, then he will solve 175 problems and 2 hours of reading will give 2 × 62.5 = 125 problems, therefore total problems solved = 300

If Gilberto solves for 3 hours, that means he will solve 225 problems, and 1 hour reading will be 62.5 problems, then the total problems solved will be = 225 + 62.5 = 287.5

Therefore, the best choice is 2 hours working on problem and 2 hours reading.

Business
Step-by-step answer
P Answered by PhD

Solution:

By 9:00 AM, Andrew has answered 40 problems.

By 10:00 AM, Andrew has answered 70 problems.

So the marginal, or additional, gain from his work between 9:00 AM and 10:00 AM is

70−40=30 problems.

By 11:00 AM, Andrew has answered 90 problems.

By noon, Andrew has answered 100 problems.

So the marginal gain from the fourth hour, 11:00 AM to noon, is

100−90= 10 problems.

Business
Step-by-step answer
P Answered by PhD

Solution:

By 9:00 AM, Andrew has answered 40 problems.

By 10:00 AM, Andrew has answered 70 problems.

So the marginal, or additional, gain from his work between 9:00 AM and 10:00 AM is

70−40=30 problems.

By 11:00 AM, Andrew has answered 90 problems.

By noon, Andrew has answered 100 problems.

So the marginal gain from the fourth hour, 11:00 AM to noon, is

100−90= 10 problems.

Business
Step-by-step answer
P Answered by PhD

Answer and Explanation:

1. The extra gain arises from Van first work hour i.e. from  8:00 AM to 9:00 AM is

= 80 - 0

= 80

2. The extra gain arises from Van third work hour i.e. from  10:00 AM to 11:00 AM is

= 180 - 140

= 40

3. He should select 3 hours of working and 1 hour reading as at the fourth hour for problem solving, he solves only

= 200 - 180

= 20

That brings better off study at it depicts the worth of 30 solving problems

Mathematics
Step-by-step answer
P Answered by PhD

60 ; 20

B.) 1 hour working on problems, 3 hours reading

Step-by-step explanation:

Given the information :

Time - - - Total problems Answered

8am: - - - - 0

9am: - - - - 80

10am: - - - - 140

11am: - - - - -180

noon: - - - - 200

The marginal, or additional, gain from Ana’s second hour of work, from 9:00 AM to 10:00 AM, is ?

(Total problem answered at 10 a.m - Total problems Answered at 9a.m)

(140 - 80) = 60

The marginal gain from Ana’s fourth hour of work, from 11:00 AM to noon, is ?

(Total problem answered at Noon - Total problems Answered at 11a.m)

(200 - 180) = 20

In other to get the best possible exam score,

Since it is assumed that

Solving 70 problems is equivalent to 1 hour of reading in terms of score improvement

Also, it is assumed that the same number of pages is covered for every hour spent whine reading.

Hence it is only during the first hour, that is (8:00 - 9:00) that she was able to solve above 70 questions (80 - 0). Number of questions solved during subsequent hours were not up to 70, hence it would have been more rewarding if they had been used for reading.

Hence, she should have spent 1 hour working on problems and 3 hours reading

Mathematics
Step-by-step answer
P Answered by PhD

60 ; 20

B.) 1 hour working on problems, 3 hours reading

Step-by-step explanation:

Given the information :

Time - - - Total problems Answered

8am: - - - - 0

9am: - - - - 80

10am: - - - - 140

11am: - - - - -180

noon: - - - - 200

The marginal, or additional, gain from Ana’s second hour of work, from 9:00 AM to 10:00 AM, is ?

(Total problem answered at 10 a.m - Total problems Answered at 9a.m)

(140 - 80) = 60

The marginal gain from Ana’s fourth hour of work, from 11:00 AM to noon, is ?

(Total problem answered at Noon - Total problems Answered at 11a.m)

(200 - 180) = 20

In other to get the best possible exam score,

Since it is assumed that

Solving 70 problems is equivalent to 1 hour of reading in terms of score improvement

Also, it is assumed that the same number of pages is covered for every hour spent whine reading.

Hence it is only during the first hour, that is (8:00 - 9:00) that she was able to solve above 70 questions (80 - 0). Number of questions solved during subsequent hours were not up to 70, hence it would have been more rewarding if they had been used for reading.

Hence, she should have spent 1 hour working on problems and 3 hours reading

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