Mathematics: Find the probability of each event listed

Find the probability of each event listed, №14549920, 07.10.2020 14:21

Mathematics

Find the probability of each event. Answer IN FRACTION form. A mechanic working under a car requires four different size wrenches from his toolbox, which contains eleven different wrenches. Reaching for his toolbox, he grabs four of them at random. What is the probability that the mechanic has all of the wrenches he needs?

Step-by-step answer

P Answered by PhD

1/330

Step-by-step explanation:

1/11C4 = 1/330

Mathematics

Aset of cards has 20 cards with stars, 10 cards with squares, and 15 cards with circles. find the probability of each event when a card is chosen at random. 1. square 2. circle 3. star or circle 4. not circle or square there are 14 girls and 18 boys in ms. wiley s class. ms. wiley randomly selects on student to solve a problem. find the probability of each event. 5. selecting a boy 6. selecting a girl

Step-by-step answer

P Answered by Master

15

1 (square) is 2/9, .22 repeating, and 22 2/9%

2. (circle) is 1/3, .33 repeating, and 33 1/3%

3. (star or circle) is 7/9, .77 repeating, and 77 7/9% sorry I couldn't finish the rest of them. dad told me to get off the computer.

Mathematics

Aset of cards has 20 cards with stars, 10 cards with squares, and 15 cards with circles. find the probability of each event when a card is chosen at random. 1. square 2. circle 3. star or circle 4. not circle or square there are 14 girls and 18 boys in ms. wiley s class. ms. wiley randomly selects on student to solve a problem. find the probability of each event. 5. selecting a boy 6. selecting a girl

Step-by-step answer

P Answered by Master

15

1 (square) is 2/9, .22 repeating, and 22 2/9%

2. (circle) is 1/3, .33 repeating, and 33 1/3%

3. (star or circle) is 7/9, .77 repeating, and 77 7/9% sorry I couldn't finish the rest of them. dad told me to get off the computer.

Biology

The probability of two independent events occurring together is a.) the sum of the probability of each event occurring separately b.) the product of the probability of each event occurring separately c.) the difference between the probability of each event occurring separately d.) impossible to determine

Step-by-step answer

P Answered by Specialist

18

B or C I'm not for sure but I know it's not impossible to determine and they don't product occur separately. I might go with C

Biology

The probability of two independent events occurring together is a.) the sum of the probability of each event occurring separately b.) the product of the probability of each event occurring separately c.) the difference between the probability of each event occurring separately d.) impossible to determine

Step-by-step answer

P Answered by Master

18

B or C I'm not for sure but I know it's not impossible to determine and they don't product occur separately. I might go with C

Mathematics

Consider a fair coin which when tossed results in either heads (h) or tails (t). if the coin is tossed two times 1. list all possible outcomes. (order matters here. so, ht and th are not the same outcome.) 2. write the sample space. 3. list all possible events and compute the probability of each event, assuming that the probability of each possible outcome from part (a) is equal. (keep in mind that there should be many more events than outcomes and not all events will have the same probability.)

Step-by-step answer

P Answered by Master

1

Sample space = {(T,T), (T,H), (HT), (HH)}

Step-by-step explanation:

We are given a fair coin which when tossed one times either gives heads(H) or tails(T).

Now, the same coin is tossed two times.

1) All the possible outcomes

Tails followed by tails

Rails followed by heads

Heads followed by a tail

Heads followed by heads

2) Sample space

{(T,T), (T,H), (HT), (HH)}

3) Formula:

$Probability = \displaystyle\frac{\text{Favourable outcome}}{\text{Total number of outcome}}$

Using the above formula, we can compute the following probabilities.

Probability((T,T)) = $\frac{1}{4}$

Probability((T,H)) = $\frac{1}{4}$

Probability((H,T)) = $\frac{1}{4}$

Probability((H, H)) = $\frac{1}{4}$

Probability(Atleast one tails) = $\frac{3}{4}$

Probability(Atleast one heads) = $\frac{3}{4}$

Probability(Exactly one tails) = $\frac{2}{4}$

Probability(Exactly one heads) = $\frac{2}{4}$

Mathematics

James conducted an experiment with 4 possible outcomes. He determined that the experimental probability of event A happening is 10 out of 50. The theoretical probability of event A happening is 1 out of 4. Which action is most likely to cause the experimental probability and theoretical probabilities for each event in the experiment to become closer? removing the last 10 trials from the experimental data completing the experiment many more times and combining the results to the trials already done including a fifth possible outcome performing the

Step-by-step answer

P Answered by PhD

52

Completing the experiment a few more times and combining the results to the trails already done.

Mathematics

Consider a fair coin which when tossed results in either heads (h) or tails (t). if the coin is tossed two times 1. list all possible outcomes. (order matters here. so, ht and th are not the same outcome.) 2. write the sample space. 3. list all possible events and compute the probability of each event, assuming that the probability of each possible outcome from part (a) is equal. (keep in mind that there should be many more events than outcomes and not all events will have the same probability.)

Step-by-step answer

P Answered by Master

1

Sample space = {(T,T), (T,H), (HT), (HH)}

Step-by-step explanation:

We are given a fair coin which when tossed one times either gives heads(H) or tails(T).

Now, the same coin is tossed two times.

1) All the possible outcomes

Tails followed by tails

Rails followed by heads

Heads followed by a tail

Heads followed by heads

2) Sample space

{(T,T), (T,H), (HT), (HH)}

3) Formula:

$Probability = \displaystyle\frac{\text{Favourable outcome}}{\text{Total number of outcome}}$

Using the above formula, we can compute the following probabilities.

Probability((T,T)) = $\frac{1}{4}$

Probability((T,H)) = $\frac{1}{4}$

Probability((H,T)) = $\frac{1}{4}$

Probability((H, H)) = $\frac{1}{4}$

Probability(Atleast one tails) = $\frac{3}{4}$

Probability(Atleast one heads) = $\frac{3}{4}$

Probability(Exactly one tails) = $\frac{2}{4}$

Probability(Exactly one heads) = $\frac{2}{4}$

Mathematics

James conducted an experiment with 4 possible outcomes. He determined that the experimental probability of event A happening is 10 out of 50. The theoretical probability of event A happening is 1 out of 4. Which action is most likely to cause the experimental probability and theoretical probabilities for each event in the experiment to become closer? removing the last 10 trials from the experimental data completing the experiment many more times and combining the results to the trials already done including a fifth possible outcome performing the

Step-by-step answer

P Answered by PhD

52

Completing the experiment a few more times and combining the results to the trails already done.

Mathematics

The probabilities for each event are given by the ratio of the area of the event to the total area of 72. for example, event c is red only. so, for the probability of event c, you have: p(c)=area of red/total area=18/12x6=18/72=1/4=0.25 are a and b dependent or independent events? use conditional probabilities to support your conclusion.

Step-by-step answer

P Answered by PhD

45

Let say that you want to take 1 area. Before the event, the probability of A and B would be:
A= blue and green= (18/12x6) + (18/12x6) = 36/72
B= green and yellow= (18/12x6) + (18/12x6) = 36/72

If the area that picked is green, then the probability of A and B become
A= blue and green= (18/12x6-1) + (17/12x6-1) = 35/71
B= green and yellow= (17/12x6-1) + (18/12x6-1) = 35/71

Both of the areas of A and B is decreased because they share the probability of green. So A and B would be a dependent event.

Find the probability of each event listed

Faq

Try asking the Studen AI a question.