23.07.2022

tara and michelle are growing trees in their. backyard math answers

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Mathematics
Step-by-step answer
P Answered by PhD

To determine the exponential growth of Michelle's tree at 12 years, taking into account that it measures 7 feet and grows 14% annually, the following calculation must be performed:

X = 7 x (1 + 0.14) 12

X = 33.7

Thus, in 12 years, the height of Michelle's tree will be 33.7 feet. In turn, the tree of Tara will measure 58 feet at the same time.

The first time Michelle's tree surpasses Tara's will be at age 20, when Michelle's tree will measure 96.2 feet (X = 7 x (1 + 0.14) 20), while Tara's tree will measure 90 feet.

Mathematics
Step-by-step answer
P Answered by PhD

To determine the exponential growth of Michelle's tree at 12 years, taking into account that it measures 7 feet and grows 14% annually, the following calculation must be performed:

X = 7 x (1 + 0.14) 12

X = 33.7

Thus, in 12 years, the height of Michelle's tree will be 33.7 feet. In turn, the tree of Tara will measure 58 feet at the same time.

The first time Michelle's tree surpasses Tara's will be at age 20, when Michelle's tree will measure 96.2 feet (X = 7 x (1 + 0.14) 20), while Tara's tree will measure 90 feet.

Physics
Step-by-step answer
P Answered by PhD

Refer to the attachment for the graph. The shape of both functions should resemble part of a parabola. Assumption: air resistance on the car is negligible.

Explanation:

The toy car started with a large amount of (gravitational) potential energy (PE) when it is at the top of the tree. Since it wasn't moving (as it was within Michelle's grip,) its kinetic energy (KE) would be equal to zero.As the car falls to the ground, its PE converts to KE.When the car was about to reach the ground, its PE is almost zero, while its KE is at its maximum.PE of the car over time

The size of gravitational PE depends on both the mass and the height of the object. In this case, assume that the mass of the car stayed the same, PE should be proportional to the height of the car.

Assume that air resistance on the car is negligible. The height h of the car at time t could be found with the equation:

\displaystyle h = -\frac{1}{2}\, g\, t^2 + h_0 \, (\text{Initial height}),

where

g \approx \rm 9.81\; m \cdot s^{-2} near the surface of the earth, andh_0 is the initial height of the car.

On the other hand, \displaystyle \text{GPE} = m \, g \, h = -\frac{m \cdot g^2}{2}\, t^2 + \underbrace{m \cdot g \cdot h_0}_{\text{Initial GPE}}.

In other words, plotting the gravitational PE of the car against time would give a parabola. Since \displaystyle -\frac{m \cdot g^2}{2} < 0 (the quadratic coefficient is smaller than zero,) the parabola should open downwards. Besides, since at t = 0 the initial GPE is positive, the y-intercept of this parabola should also be positive.

KE of the car over time

Assume that the air resistance on the car is negligible. The mechanical energy (ME) of the toy car should conserve (stay the same.) The mechanical energy of an object is the sum of its PE and KE. The PE of the toy car has already been found as a function of time. Therefore, simply subtract the expression of PE from mechanical energy to find an expression for KE.

To find the value of mechanical energy, consider the PE of the toy car before it was dropped. Since initially KE was equal to zero, the mechanical energy of the toy car would be equal to its initial PE. That's m \cdot g \cdot h_0. If there's no air resistance, the value of ME would stay at

Subtract PE from ME to obtain an expression for KE:

\begin{aligned} \text{KE} &= \text{ME} - \text{PE} \cr &= m \cdot g \cdot h_0 - \left(-\frac{m \cdot g^2}{2}\, t^2 + m \cdot g \cdot h_0\right)\cr &= \frac{m \cdot g^2}{2}\, t^2\end{aligned}.

That's also a parabola when plotted against t. Note that since the quadratic coefficient \displaystyle \frac{m \cdot g^2}{2} is positive, the parabola shall open upwards.


Graphing:  michelle climbs a tree and drops the toy car once she has reached the top.  create an ene
Mathematics
Step-by-step answer
P Answered by PhD
12 Birds

To solve this problem, work it from the end towards the beginning.

Number of birds left = 4

Three more birds flew into the branches of a nearby tree. So you lost 3 birds. Add them to the total giving you 7.

Two birds left the bird feeder to go to another stationed a few feet away. So you had a loss of 2 birds. Add them to the total giving you 9.

On fourth of the birds flew away when they were startled by a noise. Now we have something. We know that after one fourth flew away, 9 were left.

X - (1/4)X = 9

Merge the X terms.

(3/4)X = 9

Divide both sides by 3/4

X = 9/(3/4)

X = 9/1 * 4/3

X = 36/3

X = 12

So the number of birds at the feeder initially was 12.

To prove it.

Start with 12. One fourth flew away, leaving 9.

Two more leave, leaving 7.

Three more leave, leaving 4.
Mathematics
Step-by-step answer
P Answered by PhD
12 Birds

To solve this problem, work it from the end towards the beginning.

Number of birds left = 4

Three more birds flew into the branches of a nearby tree. So you lost 3 birds. Add them to the total giving you 7.

Two birds left the bird feeder to go to another stationed a few feet away. So you had a loss of 2 birds. Add them to the total giving you 9.

On fourth of the birds flew away when they were startled by a noise. Now we have something. We know that after one fourth flew away, 9 were left.

X - (1/4)X = 9

Merge the X terms.

(3/4)X = 9

Divide both sides by 3/4

X = 9/(3/4)

X = 9/1 * 4/3

X = 36/3

X = 12

So the number of birds at the feeder initially was 12.

To prove it.

Start with 12. One fourth flew away, leaving 9.

Two more leave, leaving 7.

Three more leave, leaving 4.

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