a new carpet cleaning company claims that they can clean 3 times ad many carpets in one week as another company. if both companies combined can clean 332 carpets in one week, how many caroets does the new company clean

The number of carpets cleaned by new company per week  is 249

Step-by-step explanation:

Let us assume :

The number of carpets cleaned by old company in 1 week = m

So, the number of carpets cleaned by new company in 1 week

= 3 x ( Number of carpets cleaned by old company)

 = 3 (m) = 3 m

Total carpet cleaned altogether in a week  = 332

So, Total Carpets cleaned by both companies in 1 week

= Number of carpets cleaned by ( Old + New) company in 1 week.

=  m + 3  m =  4 m

⇒  4  m = 332

or, m = 332 / 4 = 83  , or m = 83

Hence number of carpets cleaned by old company per week = m = 83

The number of carpets cleaned by new company per week

= 3 m =  3 x 83= 249

The number of carpets cleaned by new company per week  is 249

Step-by-step explanation:

Let us assume :

The number of carpets cleaned by old company in 1 week = m

So, the number of carpets cleaned by new company in 1 week

= 3 x ( Number of carpets cleaned by old company)

 = 3 (m) = 3 m

Total carpet cleaned altogether in a week  = 332

So, Total Carpets cleaned by both companies in 1 week

= Number of carpets cleaned by ( Old + New) company in 1 week.

=  m + 3  m =  4 m

⇒  4  m = 332

or, m = 332 / 4 = 83  , or m = 83

Hence number of carpets cleaned by old company per week = m = 83

The number of carpets cleaned by new company per week

= 3 m =  3 x 83= 249

The answer is in the image 

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

The answer is in the image 

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

The answer is in the image 

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

The answer is in the image 

The solution is given in the image below