Mathematics : asked on bhhh7351
 04.12.2020

A projectile is launched upward with a velocity of 288 feet per second from the top of a 35 foot platform what is the maximum height attained ?

. 7

Faq

Mathematics
Step-by-step answer
P Answered by PhD

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

Step-by-step explanation:

The height formula has the following formula:

h = h_{0} + v_{0}t - \frac{gt^{2}}{2}

In which h_{0} is the initial height, v_{0} is the initial speed and g = 9.8 m/s² is the gravity.

In this problem, we have that:

We are working with the gravity in meters, so we must convert the feet measures to meters.

Each feet has 0.3048 meters.

So 288 feet per second = 87.78 meters per second.

65 foot = 19.81 meters.

This means that:

h_{0} = 19.81, v_{0} = 87.78

So

h(t) = 19.81 + 87.78t - 4.9t^{2}

The maximum height is attained at the moment of time in which the velocity is 0. The velocity is the derivative of the height. So:

v(t) = h'(t) = -9.8t + 87.78

v(t) = 0

9.8t = 87.78

t = 8.96

The maximum height is attained at 8.96s. This height is

h(t) = 19.81 + 87.78t - 4.9t^{2}

h(8.96) = 19.81 + 87.78*8.96 - 4.9*(8.96)^{2} = 412.94

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

Mathematics
Step-by-step answer
P Answered by PhD

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

Step-by-step explanation:

The height formula has the following formula:

h = h_{0} + v_{0}t - \frac{gt^{2}}{2}

In which h_{0} is the initial height, v_{0} is the initial speed and g = 9.8 m/s² is the gravity.

In this problem, we have that:

We are working with the gravity in meters, so we must convert the feet measures to meters.

Each feet has 0.3048 meters.

So 288 feet per second = 87.78 meters per second.

65 foot = 19.81 meters.

This means that:

h_{0} = 19.81, v_{0} = 87.78

So

h(t) = 19.81 + 87.78t - 4.9t^{2}

The maximum height is attained at the moment of time in which the velocity is 0. The velocity is the derivative of the height. So:

v(t) = h'(t) = -9.8t + 87.78

v(t) = 0

9.8t = 87.78

t = 8.96

The maximum height is attained at 8.96s. This height is

h(t) = 19.81 + 87.78t - 4.9t^{2}

h(8.96) = 19.81 + 87.78*8.96 - 4.9*(8.96)^{2} = 412.94

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

The solution is given in the image below

The solution is given in the image below
Mathematics
Step-by-step answer
P Answered by PhD

Here,

tip=18%of $32

tip=(18/100)*32

=0.18*32

=$5.76

Total payment=32+5.76=$37.76

Mathematics
Step-by-step answer
P Answered by PhD

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

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