Manual 30 Liters of a mixture of water and 10% lemon juice he has a mixture of 8% lemon juice and A mixture of 20% lemon juice. how many liters of the 8% and 20% make should he mix to get what he wants
Answer: Manuel needs 20 liters of the 8% and 5 liters of 20% mixtures to be mixed so as to get 30 liters of a mixture of water and 10% lemon juice.
Explanation:
Let x represent the amount of 8% lemon juice in liters and y represent the amount of 20% lemon juice in liters.
Let x represent the amount of 8% lemon juice in liters and y represent the amount of 20% lemon juice in liters.
Since Manuel wants to produce a 30 liters mixture from 8% lemon juice and 20% lemon juice, hence:
x + y = 30 (1).
Also, Manuel wants 30 liters of a mixture of water and 10% lemon juice, hence:
8% of x + 20% of y = 10% of 30 liters;
0.08x + 0.2y = 3 (2).
Solving equation 1 and 2 simultaneously; multiply equation 1 by 0.2 and subtract equation 2 from the result:
0.12x = 3;
x = 25 liters.
x + y = 30;
25 + y = 30;
y = 5 liters.
Hence, Manuel needs 20 liters of the 8% and 5 liters of 20% mixture.
Answer: Manuel needs 20 liters of the 8% and 5 liters of 20% mixtures to be mixed so as to get 30 liters of a mixture of water and 10% lemon juice.
Explanation:
Let x represent the amount of 8% lemon juice in liters and y represent the amount of 20% lemon juice in liters.
Since Manuel wants to produce a 30 liters mixture from 8% lemon juice and 20% lemon juice, hence:
x+y=30 (1).
Also, Manuel wants 30 liters of a mixture of water and 10% lemon juice, hence:
8% of x+20% of y=10% of 30 liters;
0.08x+0.2y= 3 (2).
Solving equation 1 and 2 simultaneously; multiply equation 1 by 0.2 and subtract equation 2 from the result:
0.12x = 3;
x = 25 liters.
x + y = 30;
25 + y = 30;
y = 5 liters.
Manuel needs 20 liters of the 8% and 5 liters of 20% mixture.