15.07.2021

Graph the image of points a and b after a reflection over the x-axis

. 4

Faq

Mathematics
Step-by-step answer
P Answered by PhD

The coordinates are;

For reflection over the x-axis

A'(-8, 2)

B'(-4, 3)

C'(-2, 8)

D'(-10, 6)

For reflection over the y-axis;

A''(8, 2)

B''(4, 3)

C''(2, 8)

D''(10, 6)

Step-by-step explanation:

When a point (x, y) is reflected over the x, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (x, -y)

Therefore, for the points A, B, C, D we have;

Pre-image A(-8, -2), Image A'(-8, 2)

Pre-image B(-4, -3), Image B'(-4, 3)

Pre-image C(-2, -8), Image C'(-2, 8)

Pre-image D(-10, -6), Image D'(-10, 6)

When a point (x, y) is reflected over the y, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (-x, y)

Therefore, for the points A', B', C', D' we have;

Pre-image A'(-8, 2), Image A''(8, 2)

Pre-image B'(-4, 3), Image B''(4, 3)

Pre-image C'(-2, 8), Image C''(2, 8)

Pre-image D'(-10, 6), Image D''(10, 6).

Mathematics
Step-by-step answer
P Answered by PhD

The coordinates are;

For reflection over the x-axis

A'(-8, 2)

B'(-4, 3)

C'(-2, 8)

D'(-10, 6)

For reflection over the y-axis;

A''(8, 2)

B''(4, 3)

C''(2, 8)

D''(10, 6)

Step-by-step explanation:

When a point (x, y) is reflected over the x, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (x, -y)

Therefore, for the points A, B, C, D we have;

Pre-image A(-8, -2), Image A'(-8, 2)

Pre-image B(-4, -3), Image B'(-4, 3)

Pre-image C(-2, -8), Image C'(-2, 8)

Pre-image D(-10, -6), Image D'(-10, 6)

When a point (x, y) is reflected over the y, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (-x, y)

Therefore, for the points A', B', C', D' we have;

Pre-image A'(-8, 2), Image A''(8, 2)

Pre-image B'(-4, 3), Image B''(4, 3)

Pre-image C'(-2, 8), Image C''(2, 8)

Pre-image D'(-10, 6), Image D''(10, 6).

Mathematics
Step-by-step answer
P Answered by PhD

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

(x,y)\to (x,-y)

Now, using this rule, we get

A(1,4)\to A'(1,-4)

B(3,-2)\to B'(3,2)

C(4,2)\to C'(4,-2)

Therefore, the coordinates of the image  A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

Mathematics
Step-by-step answer
P Answered by PhD
A'(1, -4)B'(3, 2)C'(4. -2)

Step-by-step explanation:

Given

Triangle ABC with coordinates

A(1, 4), B(3, -2), C(4, 2)To findCoordinates of the image A'B'C' after a reflection over the x-axisSolution

Rule for reflection over x-axis is

R(x) = (x, y) → (x, -y)

The coordinates will change as follows

A(1, 4) → A'(1, -4)B(3, -2) → B'(3, 2)C(4, 2) → C'(4. -2)
Mathematics
Step-by-step answer
P Answered by PhD

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

(x,y)\to (x,-y)

Now, using this rule, we get

A(1,4)\to A'(1,-4)

B(3,-2)\to B'(3,2)

C(4,2)\to C'(4,-2)

Therefore, the coordinates of the image  A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

Mathematics
Step-by-step answer
P Answered by Specialist
Okay, well first look at the graph of the point "D". A translation from (7, -3) to (2, 5) is a movement of 8 units up, and 5 units left. So the conversion factor is (8, -5).

Now, I understand the points of the triangle are at (1, 4) (3, -2) and (4, 0). To reflect across the x-axis, to do this, merely flip the signs of the y-values of the coordinates.

A(1, 4) = A'(1, -4)
B(3, -2) = B' (3, 2)
C(4, 0) = C'(4, 0)

And that's all folks!
Mathematics
Step-by-step answer
P Answered by PhD

After reflection over the x-axis, we have the coordinates as follows;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

Step-by-step explanation:

Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis

By reflecting over the x-axis, the y-coordinate is bound to change in sign

So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)

We simply go on to negate the value of the y-coordinate

Mathematically if we apply these to the given points, what we get are the following;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

Mathematics
Step-by-step answer
P Answered by PhD

Answers:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as (x,y) \to (x,-y)

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)Point B = (0, 3) becomes B ' = (0, -3)Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.


HELP! will give brainlest or whatever its called... Triangle ABC has vertices A(–2, 3), B(0, 3), and
Mathematics
Step-by-step answer
P Answered by Specialist
Okay, well first look at the graph of the point "D". A translation from (7, -3) to (2, 5) is a movement of 8 units up, and 5 units left. So the conversion factor is (8, -5).

Now, I understand the points of the triangle are at (1, 4) (3, -2) and (4, 0). To reflect across the x-axis, to do this, merely flip the signs of the y-values of the coordinates.

A(1, 4) = A'(1, -4)
B(3, -2) = B' (3, 2)
C(4, 0) = C'(4, 0)

And that's all folks!
Mathematics
Step-by-step answer
P Answered by PhD

        Co ordinate of A' = (1, -4)

        Co ordinate of B' = (3, 2)

        Co ordinate of C' = (4, -2)

Explanation:

 The figure of the triangle is shown below.

  If we are finding image of the triangle about X-axis all the x -co-ordinates will remain same, but y co-ordinate will change it's sign.

 So, co ordinate of A' = (1, -4)

        Co ordinate of B' = (3, 2)

        Co ordinate of C' = (4, -2)


Triangle abc has coordinates a(1, 4);  b(3, -2);  and c(4, 2). find the coordinates of the image a'b

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