There is only 1 solution for the length of BC.
We can calculate it using Pythagorean theorem.
We can conclude that triangle's hypotenuse is AC.
If that is the case we are looking for a side BC.
Now put in the data.
Hope this helps.
r3t40
There is only 1 solution for the length of BC.
We can calculate it using Pythagorean theorem.
We can conclude that triangle's hypotenuse is AC.
If that is the case we are looking for a side BC.
Now put in the data.
Hope this helps.
r3t40
Step-by-step explanation:
Let x be number of balls shot through the hoop by Central City High School's robot.
We have been given an equation and we are asked to find the values of a, b and c.
We are told that Central City High School's team earned an additional 12 points for each ball the robot shot through a hoop. So the points earned by shooting x balls through the hoop will be 12x.
The team also earned 80 points for their robot climbing over an obstacle. So total number of points earned by team will be equal to .
We are also told that the team won the round with 344 total points. We can represent this information in an equation as:
Upon comparing this equation with our given equation we will get,
Therefore, the equation can be used to find the number of balls, x, team's robot shot through the hoop.
Step-by-step explanation:
Let x be number of balls shot through the hoop by Central City High School's robot.
We have been given an equation and we are asked to find the values of a, b and c.
We are told that Central City High School's team earned an additional 12 points for each ball the robot shot through a hoop. So the points earned by shooting x balls through the hoop will be 12x.
The team also earned 80 points for their robot climbing over an obstacle. So total number of points earned by team will be equal to .
We are also told that the team won the round with 344 total points. We can represent this information in an equation as:
Upon comparing this equation with our given equation we will get,
Therefore, the equation can be used to find the number of balls, x, team's robot shot through the hoop.
(1) Less than → <
(2) Greater than → >
(3) Less than or equal to → ≤
(4) Greater than or equal to → ≥
(5) At most → ≤
(6) At least → ≥
(7) Maximum → ≤
(8) Minimum → ≥
(9) No more than →
(10) No less than →
(11) Fewer than → <
(12) More than → >
Step-by-step explanation:
Here we have to type the symbols for the written conditions given in the problem.
(1) Less than → <
(2) Greater than → >
(3) Less than or equal to → ≤
(4) Greater than or equal to → ≥
(5) At most → ≤
(6) At least → ≥
(7) Maximum → ≤
(8) Minimum → ≥
(9) No more than →
(10) No less than →
(11) Fewer than → <
(12) More than → >
(1) Less than → <
(2) Greater than → >
(3) Less than or equal to → ≤
(4) Greater than or equal to → ≥
(5) At most → ≤
(6) At least → ≥
(7) Maximum → ≤
(8) Minimum → ≥
(9) No more than →
(10) No less than →
(11) Fewer than → <
(12) More than → >
Step-by-step explanation:
Here we have to type the symbols for the written conditions given in the problem.
(1) Less than → <
(2) Greater than → >
(3) Less than or equal to → ≤
(4) Greater than or equal to → ≥
(5) At most → ≤
(6) At least → ≥
(7) Maximum → ≤
(8) Minimum → ≥
(9) No more than →
(10) No less than →
(11) Fewer than → <
(12) More than → >
Explained below.
Step-by-step explanation:
The question is:
Compare the distributions using either the means and standard deviations or the five-number summaries. Justify your choice.
Set A: {36, 51, 37, 42, 54, 39, 53, 42, 46, 38, 50, 47}
Set B: {22, 57, 46, 24, 31, 41, 64, 50, 28, 59, 65, 38}
The five-number summary is:
MinimumFirst Quartile Median Third Quartile MaximumThe five-number summary for set A is:
Variable Minimum Q₁ Median Q₃ Maximum
Set A 36.00 38.25 44.00 50.75 54.00
The five-number summary for set B is:
Variable Minimum Q₁ Median Q₃ Maximum
Set B 22.00 28.75 48.00 58.50 65.00
Compute the mean for both the data as follows:
Both the distribution has the same mean.Compare mean and median for the two data:
This implies that set A is positively skewed whereas set B is negatively skewed.Compute the standard deviation for both the set as follows:
The set B has a greater standard deviation that set A. Implying set B has a greater variability that set B.A type II error is failing to reject the hypothesis that μ is equal to 2800 when in fact, μ is less than 2800.
Step-by-step explanation:
A Type II error happens when a false null hypothesis is failed to be rejected.
The outcome (the sample) probability is still above the level of significance, so it is consider that the result can be due to chance (given that the null hypothesis is true) and there is no enough evidence to claim that the null hypothesis is false.
In this contest, a Type II error would be not rejecting the hypothesis that the mean lifetime of the light bulbs is 2800 hours, when in fact this is false: the mean lifetime is significantly lower than 2800 hours.
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