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Mathematics : asked on alinadancer2717
 02.09.2022

A scientist has 2/3 liter of solution. He uses 1/2 of the solution for an experiment. How much solution does the scientist use for the experiment?

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07.12.2021, solved by verified expert
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Ranjana Bhatt
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Total solution =2/3 L
Solution used in experiment = 1/2 of 2/3
= (1/2)× (2/3)
1/3 litre
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Faq

Mathematics
Ascientist has 2/3 liter of solution. he uses 1/2 of the solution for an experiment. how much solution does the scientist use for the experiment?
Step-by-step answer
P Answered by Specialist
1/6 liter of the solution
Mathematics
Ascientist has 2/3 liter of solution. he uses 1/2 of the solution for an experiment. how much solution does the scientist use for the experiment?
Step-by-step answer
P Answered by Specialist
1/6 liter of the solution
Mathematics
Ascientist has 2/3 liter of solution. he uses 1/2 of the solution. how much solution is used for the experiment ?
Step-by-step answer
P Answered by PhD
Given:
2/3 liter of solution.
1/2 of the solution is used.

Find how much the solution is used for the experiment.

We simply multiply the 2 fractions.

2/3 liters * 1/2 = 2*1 / 3* 2 = 2/6
2/6 is simplified to 1/3
 
1/3 liter of solution was used in the experiment.
Mathematics
Ascientist has 2/3 liter of solution. he uses 1/2 of the solution. how much solution is used for the experiment ?
Step-by-step answer
P Answered by PhD
Given:
2/3 liter of solution.
1/2 of the solution is used.

Find how much the solution is used for the experiment.

We simply multiply the 2 fractions.

2/3 liters * 1/2 = 2*1 / 3* 2 = 2/6
2/6 is simplified to 1/3
 
1/3 liter of solution was used in the experiment.
Mathematics
Ascientist has 2/3 of liter of solution. he uses 1/2 of the solution of the solution for an experiment.
Step-by-step answer
P Answered by Specialist
You just have to multiplied :)

\frac{1}{2} * \frac{2}{3} = \frac{1*2}{2*3}
 = \frac{2}{6} = \frac{1*2}{3*2}
 = \frac{1}{3}

In short, the final answers : \frac{1}{3} and \frac{2}{6}
Both answers are equivalent to each other

Hope this helps !

Photon
Mathematics
Ascientist has 2/3 of liter of solution. he uses 1/2 of the solution of the solution for an experiment.
Step-by-step answer
P Answered by Specialist
You just have to multiplied :)

\frac{1}{2} * \frac{2}{3} = \frac{1*2}{2*3}
 = \frac{2}{6} = \frac{1*2}{3*2}
 = \frac{1}{3}

In short, the final answers : \frac{1}{3} and \frac{2}{6}
Both answers are equivalent to each other

Hope this helps !

Photon
Mathematics
A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker for an experiment. In total, how many milliliter of vinegar did the scientist have left after experiment?
Step-by-step answer
P Answered by PhD

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

Mathematics
A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker for an experiment. In total, how many milliliter of vinegar did the scientist have left after experiment?
Step-by-step answer
P Answered by PhD

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

Mathematics
URGENT HELP! Continued from part A and B A scientist begins an experiment with 20.25 milliliters of a chemical. She adds 0.75 milliliter of water to the chemical every 10 minutes, starting at 1:30 P.M. The scientist continues adding the 0.75 milliliters to the mixture until amount of chemical and water are EQUAL. At that point she uses 2/3 of the mixture for further experiments. How many milliliters of the mixture are unused?
Step-by-step answer
P Answered by PhD

Acoording to me calculations i think it is 8.25

Can i please get one more brainliest please! Thanks! :D

Mathematics
URGENT HELP! Continued from part A and B A scientist begins an experiment with 20.25 milliliters of a chemical. She adds 0.75 milliliter of water to the chemical every 10 minutes, starting at 1:30 P.M. The scientist continues adding the 0.75 milliliters to the mixture until amount of chemical and water are EQUAL. At that point she uses 2/3 of the mixture for further experiments. How many milliliters of the mixture are unused?
Step-by-step answer
P Answered by PhD

Acoording to me calculations i think it is 8.25

Can i please get one more brainliest please! Thanks! :D

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