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helpfulA) initial amount(A) = 400
Final amount {A(t)} = 1/4× 400 = 100
Given A(T) = A(2^2t)
100 = 400× 2^2t
2^2t = 1/4
2^2t = 2^(-2)
By comparing powers
2t = -2
t = -1
{ Although time can not be negative but as given function it's negative) so by taking mod both side)
|t| = |-1|
t = 1 years
B) initial amount (B) = 100
Final amount B(t) = 100×1/4 = 25
Given B(t)=B(2^-t)
25 = 100× 2^(-t)
25/100 = 2^(-t)
1/4 = 2^(-t)
2^(-t) = 2^(-2)
By comparing powers
-t = -2
t = 2 years
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